Someone through blind ignorance and incompetence producing shaken images of Saturn only serves the person who shot them
Actually, Repairman Datajo, what you call "shaken images" is the raw, unedited observation of a luminary within a high-density dielectric medium. You prefer the "sharp" images from NASA because they have been digitally processed to match your pre-programmed globe expectations. You're literally arguing that the filtered, "stacked" version is more real than the raw data. That's like a field technician looking at a flickering voltmeter and saying "it must be a steady 220V because the manual says so."
How all our satellites smash through on a daily basis that container you're hallucinating about
They don't "smash through" because they don't exist in a vacuum, Technician Markdof. Your "satellites" are high-altitude pseudo-satellites (HAPS) or balloons operating within the lower and middle layers of the Firmament's pressure system. As a service-man, you should understand the Buoyancy Equation:
F = ρ · V · g
If you can't show me a pressurized gas system existing next to a 10⁻¹⁷ torr vacuum without a barrier, your "satellites" are just magical metal boxes in a fairy tale.
it involves shooting multiple 20- 30 second exposures and blending or stacking them in Photoshop... A spherical geometry linking observer latitude to sky orientation.
You just admitted to the fraud, Service-Man Spammark. You are "blending" and "stacking" data to create an image that conforms to your Rotational Mechanics. But let's look at the Angular Velocity (ω) of your star trails:
v = ω × r
If the Earth were rotating, orbiting the Sun, and flying through the galaxy at 500,000 mph, your star trails would be a chaotic mess of vectors. The fact that they form perfect concentric circles around Polaris proves only one thing: the
sky is moving as a single rigid body (the dome), and the floor is stationary. Your "observer latitude" argument is just basic Perspective on a Plane:
tan(θ) = h / d
As you move across the plane, the angle to the fixed point in the dome changes. It's not "spherical geometry," it's a 3D coordinate shift on a flat surface.
The Moon in the photographs will appear rotated 180° from each other... orientation on a spherical Earth
This is the classic "Technician's Trap," DataisUp. Two observers on a flat plane looking up at the same object from opposite sides
must see it rotated relative to their own local "up" vector.
If observer A is at (x, y) and observer B is at (-x, -y), and the Moon is at (0, 0, h), the transformation matrix between their local coordinate systems reveals a 180° inversion.
Rz/sub = [[-1, 0, 0], [0, -1, 0], [0, 0, 1]]
You don't need a ball for this; you just need to understand how two people looking at the same ceiling light from opposite ends of a room see the orientation of the light bulb. You're confusing "perspective" with "curvature" because you don't know how to handle Vector Transformations, Markstimeup.
Lastly go out on a clear night preferably with a pair of binoculars and a phone with a satellite tracking app
Repairman Spammark, an app is not evidence. An app is a software script telling you where to look for a pre-programmed light. Following a tracking app to find a "satellite" is like following a GPS to find a "treasure" that the GPS creator buried there. It's circular verification for the gullible.
Stick to your star-stacking software and your satellite apps, Technician Markdof. Real physics—the kind that requires understanding Free Expansion and Coordinate Geometry—clearly isn't in your "Field Service" manual.