Conker: again, lots of blah but ZERO evidence.
Let me remind everyone why you are here...
You cut in at the point that I was concluding that a rocket could not, under any circumstances, exceed the maximum velocity of its own exhaust.
In the case of the Space Shuttle the maximum exhaust velocity is 10,000 mph; yet to reach 'orbital velocity' (lol) the Shuttle must attain 17,500 mph.
This is clearly impossible, due to Newton's 3rd (EQUAL & OPPOSITE, yes?), yet you tried to contradict this OBVIOUS FACT with a lot of POMPOUS SPAM but NO GENUINE EVIDENCE WHATSOEVER...
You & your idiot brethren have continued this SPAMMING for pages now; so either PROVIDE EASILY-VERIFIABLE EVIDENCE & SIMPLE EXPERIMENTS TO SUPPORT YOUR CLAIMS OR BUTT OUT!
But you won't, will you?
& neutral readers will note that fact...
So LOL!!!
I'm tired of talking to you like if you were a rational person, while you insult me. You awoken the spaniard on me, retard.
How can a car go faster than the road, if the road weights more than the car!
The answer is simple, you haven't read Newton's third, nor you know what a force is. The reason for it is that you are either a homeschooled retard who hasn't put a feet on a science class in its life. It's like when creationists say that the second of thermodynamics says evolution is impossible. Same level of retardation.
Let's read Newton's third, shall we?
When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.
Hm, it IS true, you are right! it DOES say equal... and opposite... I MUST BE WRONG.
...
Oh, right, it is same magnitude and opposite direction... of the force. Now here's the trick: Equal force does not mean equal velocity. Gee, I wonder why... Oh, right, its because of Newton's Second.
The vector sum of the external forces F on an object is equal to the mass m of that object multiplied by the acceleration vector a of the object: |F| = ma.
Using mathematics used by Newton himself to actually prove this laws (he wasn't on the experimental mindset, more philosophy than science), we can then deduce that, since |F
a| = |F
b|, then:
m
a * a
a = m
b * a
bWhich means a
a = (m
b * a
b) / m
aNow we are stuck. Certainly, behind all this data, there is nothing left. I should accept my defeat i this super important war on the internet... or does it?
Since we know body b (the exhaust) is less massive than body a (the rocket), we know that m
b/m
a is always less than one. We can then change this for a <1 constant. Then, a
a = <1 a
bBUT CUNKER ISNT'T THATH WHAT I SAYS?
??
First off, shut up. Second, I haven't finished. Acceleration isn't just a magical constant out of nowhere. Acceleration is just a name we put on the mathematical construct dv/dt. You see the problem now?
No?
Ok, I guess you don't understand what a derivative is. When we derivate velocity over time (which is what dv/dt means) what we mean is that we try to find out the instant change of velocity as a function of time. Mathematically speaking, we find out the find out the limit of the change in velocity respect to the change in time, when the change in time aproaches zero. (lim t->0 of (delta v/ delta t).
Seen the problem yet?
Lets keep going then.
So, then, the "magical" equation we had above becomes dv
a/dt = <1 dv
b/dt
Holy macarena, barman, that means the speed of the exhaust must be higher! Just as you predicted! We are DOOOOOOMED.
Oh wait, what? Sorry, someone is talking to me over the shoulder...oh... yeah... aha... Oh.
Yeah, dv
a and dv
b aren't velocities. They are changes in velocities. Since the rocket is accelerating for minutes, every single time the change in speed is lower than the change in speed on the particles of the exhaust that is being accelerated. But while the exhaust only accelerates for, at most, seconds, the rocket keeps this acceleration throughout the entire burn. Since, as you know, v
final = v
initial + a[the function that expresses acceleration respect to time] * t
total.
Do you understand this, or do I have to pull some kids youtube science videos? They don't pay me enough for me to give you a full scientific education, you know?
Don't reply if its not a rebbutal to the mathematical deduction proccess, or an answer to the question.