It seems you still don't understand what is going on.
The value chosen in 1954 by the 10th Conférence Générale des Poids et Mesures (CGPM) for the standard atmosphere is directly related to the sacred cubit.
https://www.bipm.org/jsp/en/ViewCGPMResolution.jsp?CGPM=10&RES=41013250 dynes per square centimetre (
101325 Pa).
In 1982, the International Union of Pure and Applied Chemistry (IUPAC) recommended that for the purposes of specifying the physical properties of substances, “standard pressure” should be precisely 100 kPa (1 bar) =
100,000 Pa.
http://goldbook.iupac.org/html/S/S05921.htmlNow, the ratio of these magnitudes equals, to four decimal places, exactly π
2.
By the way, you must be really desperate and scared to round off 0.9869233 to 0.9869: it is 0.987 still a perfect three decimal places match to the other quantity.
Like all numbers it can be expressed in terms of other numbers.It doesn't work like that.
Modern atmospheric physics:
"Geology has been viewed as a collection of events derived from insignificant causes, a string of accidents."
Yet, out of this string of accidents, we obtain a four digit perfect match between the value of the standard atmosphere and the magnitude of the g acceleration, and between the sacred cubit and the value of the standard atmosphere.
As if this wasn't enough, we have the technical atmosphere; it was in widespread use before 1971.
Why?
Because the unit of measure is exactly one kilogram-force per square centimeter, and its value equals the accepted g acceleration figure, 9.80665.
Then, the RE have a huge problem.
980.665 mbar = 98.0665 kPa technical atm = 28.959136 inHg = 32.8093 ft of water =
10.00027464 m
We are supposed to believe that, given the complete random and aleatory chemical composition/mass of the atmosphere over the eons, now the ratio of the two standard atmosphere accepted values will equal π
2/10, and that the conversion of 980.665 mbar (technical atmosphere) to the height of the column of water will equal exactly 10 meters.
Not a chance.
You close one of the bottles.
You now come back down.
You close the other bottle.
What is different between them?The situation is now this: you close one of the plastic bottles at a high altitude, the other is open, you come back down, and now you close the other bottle.
The very same explanation applies.
At the higher altitude, the molecules of air are more rarefied (less density). As the bottle is being brought down to a lower altitude, the density/effect of the dextrorotatory waves will increase, the rate of absorption of aether will increase, the bottle will implode.
At the lower altitude, perhaps right next to the surface of the Earth, the density of the air inside the bottle which was brought down UNSEALED will be much higher (than the density of air for the bottle at the higher altitude), so that the rate of absorption will be lower (even though the effect of the dextrorotatory waves at a lower altitude is greater than that at a higher altitude).
In the first case, the rarefied gas is closer to the first state of ether, a higher absorption rate, which increases, as the bottle is brought to a lower altitude.
In the second case, the much higher density of the molecules means that the rate of absorption is much reduced, the bottle will not implode.
It has everything to do with the balance between the amount of aether absorbed by the right handed spin subquarks, the amount of aether emitted by the left handed spin subquarks.
This is appealing to atmospheric pressure.You seem to be addicted to atmospheric pressure and forget that there are other, much better explanations for this phenomenon.
The density of air DECREASES with increasing altitude because of the effect of the antigravitational/laevorotatory waves upon the molecules of the gases.
Yes, as there will no longer be air pressure inside the bottle to hold it open and instead it will be crushed.Not at all.
If the air is removed from the plastic bottle, it will implode immediately; instantaneously, the dextrorotatory receptive vortices will absorb any aether left in the tanker/soda can/plastic bottle, causing a complete implosion of the object.
In vacuum, once the air (gas subquarks) is pumped out, one is left with the pure potential, the ether drift with laevorotatory and dextrorotatory strings propagating in double torsion fashion.
Then, instantaneously, the dextrorotatory receptive vortices will absorb any aether left in the tanker/soda can/plastic bottle, causing a complete implosion of the object.
The train tanker is IMPLODING, and not crushing under the influence of the "atmosphere pressure".
rejecting air pressure and then appealing to it.Not me: I have used only the effect of the potential ether waves.
You, on the other hand, are still to explain the barometer pressure contradiction which proves immediately that atmospheric pressure is not subject to the law of attractive gravitation.