A question about the possible globe earth.

The question is, as i understand it, the earth makes 1 revolution every 24 hours.
It makes 1 orbit around the Sun in 1 year. I do understand minor errors in these
numbers such that result in the leap year where a day is added.

So at 12:00 PM (Noon) everyday the earth faces the same direction. (1 revolution).
In 1 year the earth will be in the same position, in relation to the Sun. (More or less).
So in 6 months 12:00 pm (Noon) should be midnight. Is this correct?

Simple example


     12:00 PM                   -              12:00 PM

     Earth             Sun      -        Sun            Earth



      'o                  O         -         O              'o     


Please help me understand this.

Common mistake. "Minor errors" cause the problem.

It takes 24h between two Noons. But one revolution of the Earth takes ~23h 56min 4sec.

After one revolution the Earth needs to rotate a little more so the Sun reaches desired position (Noon). That is 1 day <> 1 revolution. See https://upload.wikimedia.org/wikipedia/commons/6/67/Sidereal_day_%28prograde%29.png

Now 183*236 is 43188, which is almost 12h. So everything works as it should (up to very small rounding errors).

Thanks Brouwer, I can relate to that,  i was taught a year is 365.25 days (in school), hence a leap year every 4 years.
by this relationship we would need a leap year every 2 years, no? Thanks for the input.
 

by this relationship we would need a leap year every 2 years, no? Thanks for the input.

Well that does not work like that. This relation cannot be used to tell you how many days the year lasts (365.25).

Most common is sidereal year (the time taken by the Earth to orbit the Sun once with respect to the fixed stars), that lasts ~365.25636. Hence leap year every 4 years with the common rule of exepctions.