First of all yes, please forgive my European notation ;-)
There are infinite real numbers between 0 and 1, this lead us to the fact that for any iota ( ANY ) that allows me to consider:
x+i = 1, even if x= 0,99999999999999999.. ( you put as many 9's here as you want ), "i" is still NOT 0
The fact that there are infinite 9s cancels out the fact that there are infinite numbers between 0 and 1. Would you dispute the fact that 0,333... is equal to 1/3? If you do, I wish you luck in the third grade; if not, I hope you realize that it is the same principle at work here. Technically you can put as many 3s after the decimal point you want, it will still not be equal to 1/3 (which by definition can't be expressed by a terminating decimal anyway); but if it's understood that there are an infinite number of 3s after the decimal point, it is equal to 1/3.
0,333... x 3 = 0,999...; do you dispute the logic?
1/3 x 3 = 1; do you dispute the math?
Therefore, 0,999... = 1.
In other words, there is no iota.
About the topic; I am not discussing the logic nor the math. However..... (1/3) X 3 = 1 ... Absolutely OK, nothing to say..
0,3333 X 3 = 0,9999 .... how many 3?
Maybe this is just spinning out; what I say is that THERE is, a difference, a Iota, between these infinite "3", or "9", and the complete number. It is just out of convenience, and because it is much better, that we type 1/3 instead of the zillions of 3`s ... and this is precisely the point... 1/3 is a solid complete number; so it is 1.
I understand your point ( for real), but I only can accept that 0,999999 (period) IS 1 as APROXIMATION.
Again, for most common uses, even Pi can be considered as 3,1416 ... but it is NOT. Pi is Pi ..... and NO short description of Pi ( even with zillions of numbers) is Pi
1) (1/3) + (1/3) + (1/3) = 1
2 ) The 0,3333 version.......... I cannot support it from an strict mathematical point of view. Again, I can accept it as approximation.
I'd use a pregnancy simile.. but unsure if it's out of rules :-P