You can never have acceleration of parabolic free fall. The whole meaning of parabolic free fall is nonsense.
I never said acceleration of parabolic free fall.
I said a constant acceleration giving rise to parabolic free fall. There is nothing nonsensical about it.
But here you go, dismissing yet another simple fact of reality to try and avoid admitting you were wrong.
You have already accepted that acceleration is just another form of acceleration.
So if you constant accelerate downwards, you follow a parabolic path.
The simplest one is considering your vertical position as a function of time.
But if you have constant horizontal motion, you can have it as vertical position as a function of horizontal position.
If you start at v0 and d0, with a constant acceleration of -a, then at time t your velocity will be v=v0-a*t, and your position will be d=d0+v0*t-0.5*a*t^2.
notice how this is the function of a parabola?
And guess what happens if you throw something into the air? It follows this equation with a as roughly 9.8 m/s^2.
So yes, you can have a parabolic free fall.
It doesn't help any of us but you decided to go down this route and this is what you get.
Yes, I decided to go down this route to try and have you admit the error of your ways, but no, you just double down.
You see, this is where your so called science messes you up.
No, science has nothing to do with it now.
This is how you justify your claim that you can't have constant acceleration while still claiming you can have constant speed.
One minute you can travel in so called space at a constant velocity and yet distance and speed are not strictly an issue because space is apparently a nothing.
When you are at a constant speed and then when you accelerate.
Neither of these address the issue at all.
The first statement makes no sense and I have no idea what you are trying to say.
The second is just a statement which doesn't help at all.
When you are at a constant position and then when you start moving.
Again, why can you have a constant rate of change per unit time, but not a constant rate of change per unit time?
Both velocity and acceleration are rates of change.
Your initial objection was that acceleration was a rate of change, but that would apply equally for velocity.
It sure seems like you have no justification at all and just don't want to admit that you were wrong.
It's like you trying to tell me about being close to infinity.
Any idea how close near infinity is?
Answer that and then the vacuum one will naturally answer in the same vein.
No, it is nothing like that.
It is telling you to be close to 0, as in a perfect vacuum the pressure will be 0.
He asked about being at near vacuum conditions, i.e. near 0 pressure, not near infinite pressure.
So did you also miss that a vacuum is 0, not infinite?