Air Pressure vs Gravity

If you cannot grasp the simple fact that astronomers can determine the exact location of the moon, what would be the sense in going further? I'm not going to type out a dissertation on orbital mechanics for you to insult me and call it "clap trap"

We are having a discussion. I have asked you several questions about your model but you seem intent on avoiding them.

The fact is, humans have the capability to predict eclipses. How do you think this is possible?

If you cannot grasp the simple fact that astronomers can determine the exact location of the moon, what would be the sense in going further? I'm not going to type out a dissertation on orbital mechanics for you to insult me and call it "clap trap"

We are having a discussion. I have asked you several questions about your model but you seem intent on avoiding them.

The fact is, humans have the capability to predict eclipses. How do you think this is possible?

Are you going to answer the question or are you bugging out?
I'm going on a belief that you are the real Bill Nye who is a puppet for the establishment, so come on, answer the question.

I think the information in the OP of this thread is still relevant.
https://www.theflatearthsociety.org/forum/index.php?topic=59130.msg1513460#msg1513460

Simple version for eclipse - the moon  will be precisely between the sun and earth, blocking the sunlight and causing darkness. This is the simple answer. What is the simple answer to your model Scepti?

Also, we're not quite finished discussing the 3 mil plastic sheeting spread over your head, and it not squeezing all around your body as if you were in water. You say the pressure is equalized, but the plastic is blocking the miles and miles of stacked atmosphere above you. If what you say is true, that the air acts like water and we have to push our way through the air, as if you were in water, then the plastic would be stuck to your body all the way around. The small amount of air inside the plastic between you and the plastic is NOT holding you to the ground. Nor is the air on top of the plastic. In fact, the plastic doesn't even take the shape of what's it's stretched over.
You cannot say the air pressure is equalized because then you are admitting that it is not the air holding us down. Air pressure squeezes in all directions equally, not DOWN. If air pressure cannot squeeze down a 3 mil thickness of plastic (that's .003 of an inch - 3 thousandths) and confirm around anything, then I'm afraid denspressure has failed.
Now, if you'll take note, I don't spend half my post telling you how brainwashed you are, how indoctrinated you are, gravity blah blah blah, how you just believe due to peer pressure, all of that nonsense, so I'd appreciate it if you would do that to me. All that does is waste time. And skirts the topic at hand. Now I'm serious, I'd really like to discuss this with you. Do the experiment for yourself, you'll see. That pressure holding you down can't even hold down thin plastic.
And, Happy New Year.. 

I think the information in the OP of this thread is still relevant.
https://www.theflatearthsociety.org/forum/index.php?topic=59130.msg1513460#msg1513460

That works for me ;-)

Simple version for eclipse - the moon  will be precisely between the sun and earth, blocking the sunlight and causing darkness. This is the simple answer. What is the simple answer to your model Scepti?

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.
Now tell me how eclipses work on your model.
Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

Also, we're not quite finished discussing the 3 mil plastic sheeting spread over your head, and it not squeezing all around your body as if you were in water. You say the pressure is equalized, but the plastic is blocking the miles and miles of stacked atmosphere above you. If what you say is true, that the air acts like water and we have to push our way through the air, as if you were in water, then the plastic would be stuck to your body all the way around. The small amount of air inside the plastic between you and the plastic is NOT holding you to the ground. Nor is the air on top of the plastic. In fact, the plastic doesn't even take the shape of what's it's stretched over.
You cannot say the air pressure is equalized because then you are admitting that it is not the air holding us down. Air pressure squeezes in all directions equally, not DOWN. If air pressure cannot squeeze down a 3 mil thickness of plastic (that's .003 of an inch - 3 thousandths) and confirm around anything, then I'm afraid denspressure has failed.

I've tried to explain this and you're refusing to understand it for some reason.
I'll give you it simply and if you won't or can't grasp it then you're lacking in logic and common sense.
Denpressure works by DISPLACING atmosphere by the energy of any object pushed INTO it.
If you push a plastic thin sheet into it, the atmosphere grips both sides and the plastic sheet can only displace that extreme thin amount of atmosphere that it's thickness displaces, which is evened out all over it.
Place that sheet over your body and the sheet is still a sheet. You feel a tiny difference in pressure from the actual atmosphere pushing on the thin part of the sheet only and not under or over because it's equalised which means it cannot be clamped around your body.

It can only drape over your head and your head will take the pressure of the entire atmosphere clamping the thin sheep displacement of it. This is transferred back to your head which you feel as a little extra pressure.

The only way to clamp it to your body is to make that sheet into a bag that seals and then have the air pushed out of it with you in it. Only then will you see that plastic adhere to your skin because you have tipped the atmospheric balance which means it's now transferred the equalised atmosphere from inside to outside.

Now, if you'll take note, I don't spend half my post telling you how brainwashed you are, how indoctrinated you are, gravity blah blah blah, how you just believe due to peer pressure, all of that nonsense, so I'd appreciate it if you would do that to me. All that does is waste time. And skirts the topic at hand. Now I'm serious, I'd really like to discuss this with you. Do the experiment for yourself, you'll see. That pressure holding you down can't even hold down thin plastic.
And, Happy New Year..

Play a fair game and you'll get a fair game played back. It's as simple as that.

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

Quote from: sceptimatic on January 03, 2017, 03:25:19 AM

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

It varies with whatever object and how densely packed it is to overcome atmospheric resistance.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.

That is not a simple model, it makes no sense and yes, it really does need fully explaining.

Now tell me how eclipses work on your model.

He kind of did.

Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

They are predicted by knowing how the different objects behave and their relative positions in space. Their movements are entirely predictable:

https://www.timeanddate.com/eclipse/list.html

When do you predict the next eclipse will be using your model?

Quote from: sceptimatic on January 03, 2017, 12:10:10 PM

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.

That is not a simple model, it makes no sense and yes, it really does need fully explaining.

Quote

Now tell me how eclipses work on your model.

He kind of did.

Quote

Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

They are predicted by knowing how the different objects behave and their relative positions in space. Their movements are entirely predictable:

https://www.timeanddate.com/eclipse/list.html

When do you predict the next eclipse will be using your model?

How does it work with your spinning Earth and why isn't eclipses uniform for your Earth ?
You have seasons by what you tell us about a spin on an axis around a sun with a moon moving in the opposite direction at around 10 mph.
Basically you're in your vacuum of space with nothing acting upon your Earth to change anything.
So tell me why your eclipses are not uniform.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

What happens to an object's weight when you remove the atmosphere?

Quote from: inquisitive on January 03, 2017, 12:18:17 PM

Quote from: sceptimatic on January 03, 2017, 03:25:19 AM

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

It varies with whatever object and how densely packed it is to overcome atmospheric resistance.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

Some typical values for the variation of pressure please.   What are the units of atmospheric resistance?

Quote from: onebigmonkey on January 03, 2017, 12:23:49 PM

Quote from: sceptimatic on January 03, 2017, 12:10:10 PM

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.

That is not a simple model, it makes no sense and yes, it really does need fully explaining.

Quote

Now tell me how eclipses work on your model.

He kind of did.

Quote

Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

They are predicted by knowing how the different objects behave and their relative positions in space. Their movements are entirely predictable:

https://www.timeanddate.com/eclipse/list.html

When do you predict the next eclipse will be using your model?

How does it work with your spinning Earth and why isn't eclipses uniform for your Earth ?
You have seasons by what you tell us about a spin on an axis around a sun with a moon moving in the opposite direction at around 10 mph.
Basically you're in your vacuum of space with nothing acting upon your Earth to change anything.
So tell me why your eclipses are not uniform.

Factors affecting eclipse timing and position:

Rotation of earth
Earth orbit eccentricity
Earth orbital period
Tilt of earths axis
Lunar orbital period
Lunar orbital eccentricity

Earths day does not divide equally into a year (solar or sidereal), or into one lunar orbital period. So already you have regular events that do not line up creating a more chaotic and irregular occurance. However, knowledge of these variables allows forward predictions really very accurately.
Lunar orbit nodes

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

What happens to an object's weight when you remove the atmosphere?

There is no weight measurement if there is no atmosphere.

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

Quote from: inquisitive on January 03, 2017, 12:18:17 PM

Quote from: sceptimatic on January 03, 2017, 03:25:19 AM

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

It varies with whatever object and how densely packed it is to overcome atmospheric resistance.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

Some typical values for the variation of pressure please.   What are the units of atmospheric resistance?

You already know the units.

Quote from: sceptimatic on January 03, 2017, 12:27:40 PM

Quote from: onebigmonkey on January 03, 2017, 12:23:49 PM

Quote from: sceptimatic on January 03, 2017, 12:10:10 PM

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.

That is not a simple model, it makes no sense and yes, it really does need fully explaining.

Quote

Now tell me how eclipses work on your model.

He kind of did.

Quote

Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

They are predicted by knowing how the different objects behave and their relative positions in space. Their movements are entirely predictable:

https://www.timeanddate.com/eclipse/list.html

When do you predict the next eclipse will be using your model?

How does it work with your spinning Earth and why isn't eclipses uniform for your Earth ?
You have seasons by what you tell us about a spin on an axis around a sun with a moon moving in the opposite direction at around 10 mph.
Basically you're in your vacuum of space with nothing acting upon your Earth to change anything.
So tell me why your eclipses are not uniform.

Factors affecting eclipse timing and position:

Rotation of earth
Earth orbit eccentricity
Earth orbital period
Tilt of earths axis
Lunar orbital period
Lunar orbital eccentricity

Earths day does not divide equally into a year (solar or sidereal), or into one lunar orbital period. So already you have regular events that do not line up creating a more chaotic and irregular occurance. However, knowledge of these variables allows forward predictions really very accurately.
Lunar orbit nodes

They could easily be divided up to match but they aren't for a very good reason. The reason is simple. It's a con job to hide the real Earth shape which is flattish and certainly not global.

Quote from: inquisitive on January 03, 2017, 01:51:33 PM

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

Quote from: inquisitive on January 03, 2017, 12:18:17 PM

Quote from: sceptimatic on January 03, 2017, 03:25:19 AM

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

It varies with whatever object and how densely packed it is to overcome atmospheric resistance.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

Some typical values for the variation of pressure please.   What are the units of atmospheric resistance?

You already know the units.

Please state.

And the values of variation of pressure that affect the weight of an object please. Have you found some experiments to comment on?  And the formula I asked for?

Quote from: sceptimatic on January 03, 2017, 03:06:18 PM

Quote from: inquisitive on January 03, 2017, 01:51:33 PM

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

Quote from: inquisitive on January 03, 2017, 12:18:17 PM

Quote from: sceptimatic on January 03, 2017, 03:25:19 AM

Quote from: Copper Knickers on January 03, 2017, 03:05:38 AM

Question for sceptimatic:

Suppose there is a set of balance scales in a chamber. On one side of the scales is a metal block of volume 1 litre (0.001m³) and on the other side is a block of less dense metal of volume 2 litres.

The air pressure in the chamber is 1 bar (100 kPa). The scales are in balance - indicating that both metal blocks have the same 'weight' under these conditions.

Now suppose the air pressure in the chamber is reduced to 0.5 bar. What would happen to the scales in the denpressure model? Would they remain in balance or would one side go down? Assume the scales are sensitive enough to detect a difference in weight if there is one.

Well you've already balanced the scales to even the both blocks up by adding more density to the less dense block side, so nothing will change as everything will simply even up around the scales and blocks.

You tell us the weight of an object varies with the air pressure, by how much?

Please let us have your formula for calculating the time an object takes to fall to the ground from a certain height, dependant on its density.

It varies with whatever object and how densely packed it is to overcome atmospheric resistance.

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

Some typical values for the variation of pressure please.   What are the units of atmospheric resistance?

You already know the units.

Please state.

And the values of variation of pressure that affect the weight of an object please. Have you found some experiments to comment on?  And the formula I asked for?

The variation of pressure is easily verified by a man made scale to measure the weight.
It's disguised with a name like gravity, which is a made up term to supposedly describe a mass on mass force that is so magical that apparently Earth can pull on something like what we are told is a rocky, orbiting moon and yet that same supposed weak moon gravity that lifts up oceans and also drop them as it passes by in a gravitational type orbital pull thingymajiggy thing.

It's laughable when given a minutes thought.

Quote from: IonSpen on January 03, 2017, 11:36:51 AM

Simple version for eclipse - the moon  will be precisely between the sun and earth, blocking the sunlight and causing darkness. This is the simple answer. What is the simple answer to your model Scepti?

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.
Now tell me how eclipses work on your model.
Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

Quote from: IonSpen on January 03, 2017, 11:36:51 AM

Also, we're not quite finished discussing the 3 mil plastic sheeting spread over your head, and it not squeezing all around your body as if you were in water. You say the pressure is equalized, but the plastic is blocking the miles and miles of stacked atmosphere above you. If what you say is true, that the air acts like water and we have to push our way through the air, as if you were in water, then the plastic would be stuck to your body all the way around. The small amount of air inside the plastic between you and the plastic is NOT holding you to the ground. Nor is the air on top of the plastic. In fact, the plastic doesn't even take the shape of what's it's stretched over.
You cannot say the air pressure is equalized because then you are admitting that it is not the air holding us down. Air pressure squeezes in all directions equally, not DOWN. If air pressure cannot squeeze down a 3 mil thickness of plastic (that's .003 of an inch - 3 thousandths) and confirm around anything, then I'm afraid denspressure has failed.

I've tried to explain this and you're refusing to understand it for some reason.
I'll give you it simply and if you won't or can't grasp it then you're lacking in logic and common sense.
Denpressure works by DISPLACING atmosphere by the energy of any object pushed INTO it.
If you push a plastic thin sheet into it, the atmosphere grips both sides and the plastic sheet can only displace that extreme thin amount of atmosphere that it's thickness displaces, which is evened out all over it.
Place that sheet over your body and the sheet is still a sheet. You feel a tiny difference in pressure from the actual atmosphere pushing on the thin part of the sheet only and not under or over because it's equalised which means it cannot be clamped around your body.

It can only drape over your head and your head will take the pressure of the entire atmosphere clamping the thin sheep displacement of it. This is transferred back to your head which you feel as a little extra pressure.

The only way to clamp it to your body is to make that sheet into a bag that seals and then have the air pushed out of it with you in it. Only then will you see that plastic adhere to your skin because you have tipped the atmospheric balance which means it's now transferred the equalised atmosphere from inside to outside.

Quote from: IonSpen on January 03, 2017, 11:36:51 AM

Now, if you'll take note, I don't spend half my post telling you how brainwashed you are, how indoctrinated you are, gravity blah blah blah, how you just believe due to peer pressure, all of that nonsense, so I'd appreciate it if you would do that to me. All that does is waste time. And skirts the topic at hand. Now I'm serious, I'd really like to discuss this with you. Do the experiment for yourself, you'll see. That pressure holding you down can't even hold down thin plastic.
And, Happy New Year..

Play a fair game and you'll get a fair game played back. It's as simple as that.

I think you're kind of flipping the script here just a bit. You not long ago said to pretend you're in an upside down swimming pool, and you had to make your way through it, pushing the water out of the way as you walked through it. Same way with the air, you have air all around you, squeezing you, and you have to push it out of  the way to walk through it. So now if the thin plastic is covering you while you're standing on the ground, shouldn't it squeeze you all around just like the water? Since air technically is a fluid, right? But, you say the air inside the plastic is equalized to the air outside the plastic. Why doesn't the outside air squeeze the plastic tight around the person, if it's in fact what squeezes the person to the ground and holds him there?
And I explained how how a solar eclipse works - the moon lines up perfectly with the earth and the moon blocks a path of sunlight from reaching earth. If you want a more detailed version than that you're more than welcome to Google it. Heck there's even tons of live videos of it.
So now I'd love to hear your theory in detail, I've never heard it. OK, the central Earth sun reflection off the dome hits a points as the energy decreases - OK stop there. Where is it it reflecting off the dome, and why is reflecting, and say, not absorbed, or split into colors like a prism (rainbows, sun dogs, other atmospheric phenomenon) - and why does the energy decrease? What causes this decrease? And then what increases it? OK, next it moves down the center of the earth it intersects between opposite reflections. Scepti, my friend, I'm sorry but I have no absolute idea what you're saying here. Truly a drawing or diagram or a model of some sort would GREATLY help here (does anyone else agree with me?)

I will tell you, I'm making the 8 hour drive north to witness the solar eclipse next August. I'm sorry you won't be able to view it. I'll post plenty of pics though! The diamond ring is the coolest part, next to the corona..

I think you're kind of flipping the script here just a bit. You not long ago said to pretend you're in an upside down swimming pool, and you had to make your way through it, pushing the water out of the way as you walked through it.
Same way with the air, you have air all around you, squeezing you, and you have to push it out of  the way to walk through it.

It helps to pay attention and try to grasp what's been and being said.
I never said make your way through it, I said imagine flipping a pool upside down if you could but nothing else changes.
You appear to not want to even think on this.

So now if the thin plastic is covering you while you're standing on the ground, shouldn't it squeeze you all around just like the water? Since air technically is a fluid, right?

I've just explained this to you. Are you not reading it?

But, you say the air inside the plastic is equalized to the air outside the plastic. Why doesn't the outside air squeeze the plastic tight around the person, if it's in fact what squeezes the person to the ground and holds him there?

I've just explained this to you, are you not reading it?

And I explained how how a solar eclipse works - the moon lines up perfectly with the earth and the moon blocks a path of sunlight from reaching earth. If you want a more detailed version than that you're more than welcome to Google it. Heck there's even tons of live videos of it.
So now I'd love to hear your theory in detail, I've never heard it. OK, the central Earth sun reflection off the dome hits a points as the energy decreases - OK stop there. Where is it it reflecting off the dome, and why is reflecting, and say, not absorbed, or split into colors like a prism (rainbows, sun dogs, other atmospheric phenomenon) - and why does the energy decrease? What causes this decrease? And then what increases it? OK, next it moves down the center of the earth it intersects between opposite reflections. Scepti, my friend, I'm sorry but I have no absolute idea what you're saying here. Truly a drawing or diagram or a model of some sort would GREATLY help here (does anyone else agree with me?)

I think it's way over your head. You can't even take the time to understand the simple logic I placed before you with the atmosphere.

I will tell you, I'm making the 8 hour drive north to witness the solar eclipse next August. I'm sorry you won't be able to view it. I'll post plenty of pics though! The diamond ring is the coolest part, next to the corona..

Good for you but it doesn't prove a globe and nor does it prove gravity.

Now how about telling me how a spinning globe on a 23.5 degree axis, spinning around a massive so called central sun manages to produce eclipses that massively differ in time frames.

Let me just explain what I mean, just in case you side step again.
Your Earth spins at around 1000 mph and also travels at 66,000 mph  around your sun, as well as your moon orbiting in the opposite direction and is also spinning at around 10 mph, as we are told.
All this happens in a so called vacuum and all is apparently uniform and yet low and behold, we have massive variations in eclipses.
Can you explain why this is the case?

Quote from: Mainframes on January 03, 2017, 02:24:08 PM

Quote from: sceptimatic on January 03, 2017, 12:27:40 PM

Quote from: onebigmonkey on January 03, 2017, 12:23:49 PM

Quote from: sceptimatic on January 03, 2017, 12:10:10 PM

My simple answer is the central Earth sun reflection off the dome hits a point as the energy decreases as it moves down the centre of the Earth it intersects between opposite reflections. It requires fully explaining but that's the basics.

That is not a simple model, it makes no sense and yes, it really does need fully explaining.

Quote

Now tell me how eclipses work on your model.

He kind of did.

Quote

Tell me how they are predicted, bearing in mind that we're told that the Earth follows a pattern in space that doesn't change and yet here we are having eclipses that do not match up to any regular pattern.

They are predicted by knowing how the different objects behave and their relative positions in space. Their movements are entirely predictable:

https://www.timeanddate.com/eclipse/list.html

When do you predict the next eclipse will be using your model?

How does it work with your spinning Earth and why isn't eclipses uniform for your Earth ?
You have seasons by what you tell us about a spin on an axis around a sun with a moon moving in the opposite direction at around 10 mph.
Basically you're in your vacuum of space with nothing acting upon your Earth to change anything.
So tell me why your eclipses are not uniform.

Factors affecting eclipse timing and position:

Rotation of earth
Earth orbit eccentricity
Earth orbital period
Tilt of earths axis
Lunar orbital period
Lunar orbital eccentricity

Earths day does not divide equally into a year (solar or sidereal), or into one lunar orbital period. So already you have regular events that do not line up creating a more chaotic and irregular occurance. However, knowledge of these variables allows forward predictions really very accurately.
Lunar orbit nodes

They could easily be divided up to match but they aren't for a very good reason. The reason is simple. It's a con job to hide the real Earth shape which is flattish and certainly not global.

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

Yes you can.

Quote from: Mainframes on January 03, 2017, 03:50:44 PM

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

Yes you can.

The earth does approximately 365.25 rotations per revolution around the sun. Are you saying we could just decide to divide it up into, say 1000 rotations per revolution or any other arbitrary number?

Sorry let me rephrase that question. Whatever is causing the seasons etc. it takes approximately 365.25 days to cycle through them. Are you saying we could arbitrarily decide to make our year 500 days long or any other arbitrary number?

Quote from: sceptimatic on January 03, 2017, 03:53:28 PM

Quote from: Mainframes on January 03, 2017, 03:50:44 PM

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

Yes you can.

The earth does approximately 365.25 rotations per revolution around the sun. Are you saying we could just decide to divide it up into, say 1000 rotations per revolution or any other arbitrary number?

Sorry let me rephrase that question. Whatever is causing the seasons etc. it takes approximately 365.25 days to cycle through them. Are you saying we could arbitrarily decide to make our year 500 days long or any other arbitrary number?

We could do anything at all to fit anything if we so desired.

Quote from: Boots on January 03, 2017, 04:16:33 PM

Quote from: sceptimatic on January 03, 2017, 03:53:28 PM

Quote from: Mainframes on January 03, 2017, 03:50:44 PM

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

Yes you can.

The earth does approximately 365.25 rotations per revolution around the sun. Are you saying we could just decide to divide it up into, say 1000 rotations per revolution or any other arbitrary number?

Sorry let me rephrase that question. Whatever is causing the seasons etc. it takes approximately 365.25 days to cycle through them. Are you saying we could arbitrarily decide to make our year 500 days long or any other arbitrary number?

We could do anything at all to fit anything if we so desired.

Alright. So you feel defining a day as one rotation of the sun/earth and a year as one complete cycle through the seasons is part of some big con started way back since the dawn of time?

How do you think a day should be defined? How about a year?

Scepti why are you refusing my bet?

Quote from: Boots on January 03, 2017, 04:16:33 PM

Quote from: sceptimatic on January 03, 2017, 03:53:28 PM

Quote from: Mainframes on January 03, 2017, 03:50:44 PM

You can't just arbitrarily divide up defined variables to match each other. A day is set by the rotation of the earth, a year by its revolution around the sun. They are what they are, and they don't divide equally.

Yes you can.

The earth does approximately 365.25 rotations per revolution around the sun. Are you saying we could just decide to divide it up into, say 1000 rotations per revolution or any other arbitrary number?

Sorry let me rephrase that question. Whatever is causing the seasons etc. it takes approximately 365.25 days to cycle through them. Are you saying we could arbitrarily decide to make our year 500 days long or any other arbitrary number?

We could do anything at all to fit anything if we so desired.

Really!
The Sumerians and many other ancient civilisations tried 360 days in the year, which is what lead to our 360° in a circle, 60 seconds in a minute and 60 minutes in an hour, etc.
This is described in The calendar and the sexagesimal "base 60" (as contrasted to our own base 10) number system have an ancient relationship, as described by Robert K. Englund, Ph.D., professor of Assyriology & Sumerology at UCLA, in his paper Administrative Timekeeping in Ancient Mesopotamia in the Journal of the Economic and Social History of the Orient, 1988, pp. 121-122:

Sumerian Calendar:
The sexagesimal system of counting... is attested in periods much earlier than any secure attestation of the Sumerian language, namely in the periods Uruk IV-III [~3200 B.C.], and possibly in some token assemblages from clay envelopes unearthed in levels of proto-elamite Susa corresponding to Uruk V [~3400 B.C.]. ... A mixture of this sexagesimal system with a heritage of natural cycles resulted in the 3rd millennium time divisions attested by administrative documents. ... The resulting system... which without question complemented throughout the 3rd millennium natural, lunistellar divisions, is attested in its basic form of a twelve-month, 360-day year in the archaic documents from the end of the 4th millennium [B.C.].
. . . . . . . . . . . . . . .
The Ecliptic: Because of their great distance, the stars beyond our Sun appear fixed in the sky. The Earth's orbit over the course of a year therefore makes the Sun appear to rise day after day adjacent to differing stars to complete what looks like a full circle through the heavens. Ancient Sumeria, Babylonia, and apparently some in India divided this circle, called the ecliptic, into 360 degrees. . . . . . . . . . 360 is thus divisible by many numbers including (in bold) those especially helpful for calendars and timekeeping: 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, and 180. A year of 360 days is reasonably divisible even by the 2 equinoxes, 2 solstices, four seasons, 12 months, etc., 24 hours in a day, 24 time zones of 15 nominal degrees each, 60 minutes in an hour, 60 seconds in a minute (and consider also our comfort with a "dozen" and with 12 inches in a foot and 36 inches in a yard).

From An Original 360-Day Year

It's really worth reading, especially to show how advanced these people were.
And yes, I believe that their earth was flat, BUT the sun and moon did actually rise from below the horizon and set to below the horizon - no sun and moon circling above the earth.

They were quite advanced with their mathematics for people living around 3,000 BC.

Quote from: markjo on January 03, 2017, 01:14:43 PM

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

What happens to an object's weight when you remove the atmosphere?

There is no weight measurement if there is no atmosphere.

Have you verified that prediction with an experiment?

Quote from: markjo on January 03, 2017, 01:14:43 PM

Quote from: sceptimatic on January 03, 2017, 12:23:37 PM

As for weight.
The weight of an object is determined by how much atmosphere it displaces whilst pushing from a solid surface that can measure a man made reading known as a weight.

What happens to an object's weight when you remove the atmosphere?

There is no weight measurement if there is no atmosphere.

Prove it!

Quote from: Badxtoss on January 03, 2017, 07:58:59 AM

Quote from: sceptimatic on January 03, 2017, 07:50:35 AM

Quote from: markjo on January 03, 2017, 06:36:45 AM

Quote from: sceptimatic on January 03, 2017, 06:02:22 AM

Quote from: deadsirius on January 03, 2017, 05:54:31 AM

Quote from: sceptimatic on January 03, 2017, 03:20:29 AM

To give you a visual, it's like pouring sand onto polystyrene balls in a tub and shaking it to see that the smaller, more dense sand has tried to crush the polystyrene balls, only the polystyrene balls get pushed UP rather than being crushed.

Well that explains why we're all floating around in the upper atmosphere, as we all know.  Still doesn't explain why the air (or the sand, in the metaphor) has a tendency to go down in the first place.

It perfectly explains it but people like you will never see it because you not only have blinkers on, you also have a blindfold over the blinkers and listening to the story tellers telling you what they want to you to believe.
From that point on you just follow protocol. It's like a very powerful addictive drug. It's called a FTM drug.
Follow the masses in case you were struggling.

Scepti, no one is denying that buoyancy (pretty much what you call denpressure) exists.  We're just saying that you still need gravity (or some form of acceleration) to cause the more dense stuff to sink and the less dense stuff to rise.

I've just explained why gravity bullshit is not required. I obviously do not, nor ever expect you and your like-minded peers to accept it. I'm well aware that gravity is required to keep the globe Earth alive and also the fictional space, etc.

I'm just showing the real genuine people that a small amount of common sense and the ability to see past the mainstream bullshit, makes it easy to actually get a more real look at what we are living in/on.

But you didn't.  Your explanation requires some outside forcing pushing down or it doesn't work.  Every example you gave requires that.

It requires no outside force at all.

Literally every example you gave requires something pushing, or pulling downward.  Without that force there is no down.  I honestly don't see how you get around that.  I know you said you've explained it but every example in your explaination requires it.  I'm not trying to be insulting, it just doesn't make any sense without that other force.