Lemmi, ausGeoff, gpssjim, JimmyTheCrab, and Dinosaur Neil.
I have no issue with you guys poking fun at people who cannot directly address the question at hand. I actually encourage it. But try to tone it down a bit, because the closest thing I have received in the form of a scientific answer was messenger boy'd (no disrespect Vauxhall, but that move by your council screamed elitist) better than a week ago, and what I got was a calculation based off of 3 grandiose assumptions that break logic from start to finish. Then, the further went so far as to call me a liar. Those people on the council are who I would like to debate with, and I get the idea your presence might make them not even want to bother. Please don't take that as sounding condescending, it is not intended that way.
Jroa, I really wish you had just taken all that time to say that it would not have been visible because the sunlight would have been dispersed too much to be visible.
I could have then pointed out that the the difference in distance to the sun from its furthest, visible point according to FET (lets use that same mountain) is less than 6000 miles, using a 24,0000 mile equatorial circumference, as there are no numbers provided by FET as to the dimensions, even on land, of the disc.
Ergo, the sunlight is twice as far away, traveling through twice the atmosphere, being half as bright. Wanna take a guess at how much brighter it is over that 200w lightbulb 1 foot from your face?