There may be a trivial answer that eludes me, but this question popped up after thinking on the Flat Earth Hypothesis.
Under conventional physics, the force due to gravity is balanced by the vertical component of the normal force. This explains why objects do not accelerate vertically under this model while on the ground. I attempted to remove the gravitational force but was unable to figure out what could balance the normal force. Again, it may be trivial, but can such a force be pointed to under FEH?
They would be exactly the same, but the notation would be inverted. In the gravity situation, the object exerts a force due to gravity (F_g) on the surface, which reacts with a reactive force (F_r) upward.
In the flat earth model, the earth exerts a an impact force due to universal acceleration (F_ua) on the object (upwards), which in turn reacts with a downward force (F_r).
That makes sense, though would the forces still balance on an angled surface? In order to get the same results, wouldn't the force due to the UA need to be perpendicular to the surface? It would need to if it is the force pointing upwards, right? I wonder if there is a site that allows you to create FBDs. That would help illustrate the situation better.
The forces balance. I can just direct you to Einstein's Equivalence Principle, but I rather enjoy physics so I'm gonna try to tackle this one head on.
I don't know of any sites that allow you to make FBDs, but I do know of Google Docs, which allow you to draw things, which is close enough
https://docs.google.com/drawings/d/19iK8JqR90IvvCEoxnOMnufIi1tTyN9khzvlo8he2J1Q/edit?usp=sharingHere's a terrible drawing of a box on an inclined plane in RET.
Let's call the angle of inclination 30 degrees. The box will weigh 10 kg, because ten is an easy number. Coefficient of friction is .1, because why not?
Give me moment to calculate all of the forces.
Fw= 98.1 N
Fw||= 49.05 N
Fw⊥= 84.96 N
Fn= 84.95 N
Ff=8.59 N
Now let's look at it from a Flat Earth perspective, shall we?
https://docs.google.com/drawings/d/1KoabP6y_TRBwguyqlbFcDFX2dOMgOV9VAHzbtZSgguQ/edit?usp=sharingNow, I'm going to have to explain all of the forces, I'd imagine.
The UA force is pushing up on the inclined plane, not the box. It would be difficult to actually give it a value in newtons, because f=ma and we have the a but not the m. So let's just call it a 9.81 m/s
2 acceleration and leave it at that.
So let's calculate some vectors. For the purposes of this thought experiment, let's pretend that the incline is a flat plane and the UA force is what is rotated 30 degrees.
The vertical acceleration vector that is acting on the box is 4.905. Adding in the box's mass to get a force, we get 49.05 N. Does that number sound familiar?
The horizontal acceleration vector is 8.495, or 84.95 N. Which, as you'll remember, is equivalent to the RET scenario as well. Putting the scenario back into the context of an inclined plane, we get this to be the FW⊥ value, which, being equivalent to the normal force value, means that normal force is equal for both theories.
Any questions?