You didn't eliminate all the 'nuclear' processes.
True, but the third nuclear process, radioactive decay, produces even less energy per volume and declines with time exponentially. You can plug in several of the energy values into the equation and you'll find them to be less, but then you'll have to deal with the half-life of the isotope you select.
The solar irradiance at the Earth's surface with the surface perpendicular to the Sun's rays is approximately 1 kW/m
2. This is an experimentally measurable fact.
All other
calculations using this figure are model dependent and are drastically different between RE and FE.
For example, assuming RE and a Sun - Earth distance of 1.50 x 10
11 m, one finds that the Sun should radiate such power that a sphere with this radius will be irradiated with the above mentioned irradiance. This gives an estimate for the Solar power of:
P
RE Sun = 10
3 W/m
2 x 4 x 3.14 x (1.50 x 10
11 m)
2 = 2.83 x 10
26 W
In FE, however, the Sun is about 3,100 mi = 5.0 x 10
6 m from the Earth. Then, the power is
P
FE Sun = 10
3 W/m
2 x 4 x 3.14 x (5.0 x 10
6 m)
2 = 3.1 x 10
17 W
Did you account for this huge difference of around 9 orders of magnitudes? Please note that the energy that the RE Sun could radiate in 1 second would be radiated by the Sun in FE in 29 years! Did you account for this discrepancy while "refuting" FE?