I cannot figure out how the sun can rise or set with the version of a flat earth as accepted by this website.
From what I have been able to gather, the earth is a flat circular disc with a diameter of approximately 20,000 km. I get to this number by assuming that the equator is 10,000 km from the North Pole, and the southern ice wall is the same distance from the equator. At least, that is how your published maps look.
On this website I have seen various figures for the altitude of the sun, ranging from 1,100 km to 6,400 km. For the rest of this question I will assume 1,100 km as that is the best case for FE; any higher figure makes sunset even more impossible.
Now let us consider how the sun looks for someone at the North Pole. The furthest that the sun can possibly be away from the North Pole is 20,000 km, assuming it ever got near the southern ice wall. No FE maps show the sun that far south, but again, this is the best scenario for FE. Now, if the sun is 1,100 km high at a distance of 20,000 km, the angle between the horizon and the sun is given by simple trigonometry, as follows:
A = atan(1100/20000) = 3 degrees
If we assume the sun sits at an altitude of 6,400 km then we get
A = atan(6400/20000) = 18 degrees
In other words, even in the best (for FE) case, we can NEVER see the sun less than 3 degrees above the horizon. If the observer is farther south, or if we look at the sun at sunset instead of midnight, the observer will be closer to the sun, and hence the sun will appear even higher above the horizon.
Hence my question: please explain how we can ever see the sun sink below the horizon.
For people who live in the US (most FEers?) and do not understand my new-fangled metrics, here are (approximate) conversions:
20,000 km = 12,430 miles
6,400 km = 4,000 miles
1,100 km= 700 miles