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Messages - John Jackson

Pages: [1] 2 3 ... 14
1
The Lounge / Re: Post an image of yourself!
« on: February 06, 2009, 07:55:41 PM »
No.  I haven't seen her in 16 years.

has she passed away?

2
Flat Earth Q&A / Re: A distance question
« on: February 06, 2009, 07:20:24 PM »
Quote
So, how much air is between me and the moon.

That would depend where the moon is. When the moon is near the horizon it's just a muddy orange, representing the length of atmosphere its light must shine through.
So, could you give a lower bound. For example, when it is exactly at the top of someone's head.

Quote
And, New York is pretty bright.

Is New York at a distance brighter than the surface of the moon?

I don't understand what you mean. Could you please explain?

3
Flat Earth Q&A / Re: A distance question
« on: February 06, 2009, 07:14:56 PM »
There is significantly more air between New York and Boston than there is between New York and the top of the atmosphere. Not to mention that very bright bodies can shine through the thickness of the atmosphere like headlights in fog.

So, how much air is between me and the moon. And, New York is pretty bright.

4
Flat Earth Q&A / Re: A distance question
« on: February 06, 2009, 07:11:29 PM »
So, isn't there air between me and the moon?
I guess not because if you cant see new york because the you cant see through air then obviously there is no air above us

Non sequitur.

5
Flat Earth Q&A / Re: A distance question
« on: February 06, 2009, 07:03:18 PM »
So, isn't there air between me and the moon?

6
Flat Earth Q&A / A distance question
« on: February 06, 2009, 06:41:18 PM »
From the FAQ:

Quote
Q: "What about the stars, sun and moon and other planets? Are they flat too? What are they made of?"

A: The sun and moon, each 32 miles in diameter, circle Earth at a height of 3000 miles at its equator. They are located midway between the North Pole and the ice wall. Each functions similar to a "spotlight," with the sun radiating "hot light" and the moon "cold light." As they are spotlights, they only give light out over a certain are which explains why some parts of the Earth are dark when others are light. Their apparent rising and setting are caused by optical illusions.

The stars are about as far as San Francisco is from Boston. (3100 miles)

How come I can see the Moon from Boston, but I can't even see New York?

7
The Lounge / Re: Post an image of yourself!
« on: January 30, 2009, 08:28:59 AM »
:o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o
:o :o                 :o     :o :o :o :o     :o :o             :o :o     :o :o     :o
:o :o     :o :o :o :o     :o :o :o :o     :o     :o :o :o     :o     :o     :o :o
:o :o             :o :o     :o :o :o :o     :o     :o :o :o :o :o         :o :o :o
:o :o     :o :o :o :o     :o :o :o :o     :o     :o :o :o :o :o         :o :o :o
:o :o     :o :o :o :o :o     :o :o     :o :o     :o :o :o     :o     :o     :o :o
:o :o     :o :o :o :o :o :o         :o :o :o :o             :o :o     :o :o     :o
:o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o

8
Flat Earth Q&A / Re: Atheist FE'ers
« on: January 30, 2009, 07:46:32 AM »
atheists != scientist.

9
Flat Earth Q&A / Re: Atheist FE'ers
« on: January 30, 2009, 07:38:50 AM »
Are there any FE Atheists out there?

10
The Lounge / Re: Math Problems
« on: January 28, 2009, 10:13:39 PM »
Well you can always move toward where the man will be and where you can get to in the same time. His speed and direction always have an intercept course. Now, I know he can change speed and direction, but as long as the robot lion thing continuously recalculates, he is screwed.

I believed that this is essentially the solution. However, it turned out that there is a startegy that the mand can pursue and not be caught.

11
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:47:08 PM »
Imagine the lion is a robot. How would you program him to chase the man.

12
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:44:52 PM »
If the Tiger runs in the center and increases the radius outwards, he will eventually corner the man along the edge, at that point he can just keep in the smaller circle and overcome the man, then veer outwards and catch him.

Why would the man continue moving along the outer circle?

13
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:41:17 PM »
The tiger can just rin in ever increasing circles and eventually the man will be at the edge of the ring and the tiger can just catch him the same way we get a satellite to catch Mars

the problem is there are no satellites around Mars. stop using some non-scientific nonsense. It is a perfectly well posed problem.
The tiger will always catch the man because if they are moving at the same speed the tiger will have the advantage of being able to move in a smaller circle so he can overtake the man even if the man turns around. like I said the same way that we get a satellite to catch mars

I am afraid i don't follow. Could you sketch something?

14
The Lounge / Re: Post an image of yourself!
« on: January 28, 2009, 07:35:20 PM »
All men are sluts to one degree or another

Bot not all sluts are men.

15
The Lounge / Re: Post an image of yourself!
« on: January 28, 2009, 07:29:20 PM »
sounds like you'll get banned.

16
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:28:29 PM »
The tiger can just rin in ever increasing circles and eventually the man will be at the edge of the ring and the tiger can just catch him the same way we get a satellite to catch Mars

the problem is there are no satellites around Mars. stop using some non-scientific nonsense. It is a perfectly well posed problem.

17
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:27:12 PM »
Run toward the man when he is not running along the wall or is not moving.  Run 45 degrees relative to the man at equal speed when he is running along the wall.

Why 45 degs? what is so special about 45 degs?

18
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:12:28 PM »
Run at an angle 45 degree away from the man's angle of running.

what if the man just stands still?

thankfully the tiger is not run by a calculation robosteve.

At that point move straight towards the man.

So, now the man starts to move away from the lion. Does the lion start the 45 deg strategy?

19
The Lounge / Re: Math Problems
« on: January 28, 2009, 07:07:46 PM »
Run at an angle 45 degree away from the man's angle of running.

what if the man just stands still?

20
The Lounge / Re: Math Problems
« on: January 28, 2009, 06:05:03 PM »
A lion and a man in a closed arena have equal maximum speeds. What tactics should the lion employ to be sure of his meal?

Chase him into a corner.

I forgot to mention that the arena is circular.

21
The Lounge / Re: Math Problems
« on: January 28, 2009, 06:00:06 PM »
A lion and a man in a closed arena have equal maximum speeds. What tactics should the lion employ to be sure of his meal?

22
Flat Earth Q&A / Re: A man will sail around Antarctica.
« on: January 21, 2009, 04:52:18 PM »
Sailing around 'Antarctica' is perfectly possible in FE. See ENaG.

23
The Lounge / Re: Post an image of yourself!
« on: January 21, 2009, 04:36:10 PM »


I gotz teh iPwn! :D

You also got phat.

24
The Lounge / Re: Math Problems
« on: January 21, 2009, 02:44:40 PM »

Find the value of x, and post your visual proof.

Rules:
You can only use elementary geometry. For instance, the angles of a triangle add up to 180 degrees, or use the basic congruent triangle rules (side-angle-side, et cetera.).  Trigonometry, like using the law of sines, the law of cosines, et cetera is strictly forbidden.

My solution:
x = 60


You have a mistake. Your second equation should be x + w = 130, which would give a singular matrix, meaning your equations are not independent. You can't just solve it using the sum of the angles in a triangle is 180. You have to use the special values of the angles.

25
The Lounge / Re: Math Problems
« on: January 21, 2009, 02:14:21 PM »

Find the value of x, and post your visual proof.

Rules:
You can only use elementary geometry. For instance, the angles of a triangle add up to 180 degrees, or use the basic congruent triangle rules (side-angle-side, et cetera.).  Trigonometry, like using the law of sines, the law of cosines, et cetera is strictly forbidden.

After applying sine theorem to triangles AED and BDE on one hand and ABD and ABE on the other, and making some equalities and a considerable ammount of trigonometry, I finally got a nasty solution for x:

x = 27o 33' 17''

Since it is a nasty result, it means I either made some mistake or you wanted to fuck with us. This problem is impossible to solve without trig.

After revising my calculations, I got x = 20, which means it might be solvable without trig. But, I used trig.

26
The Lounge / Re: Math Problems
« on: January 21, 2009, 10:34:21 AM »

Find the value of x, and post your visual proof.

Rules:
You can only use elementary geometry. For instance, the angles of a triangle add up to 180 degrees, or use the basic congruent triangle rules (side-angle-side, et cetera.).  Trigonometry, like using the law of sines, the law of cosines, et cetera is strictly forbidden.

After applying sine theorem to triangles AED and BDE on one hand and ABD and ABE on the other, and making some equalities and a considerable ammount of trigonometry, I finally got a nasty solution for x:

x = 27o 33' 17''

Since it is a nasty result, it means I either made some mistake or you wanted to fuck with us. This problem is impossible to solve without trig.

27
The Lounge / Re: Math Problems
« on: January 20, 2009, 10:00:48 PM »
Quote
The expression you gave diverges. I found a proof.

ORLY?

Actually, I found a mistake in my reasoning, but I still can bet that it diverges.

It doesn't. The solution to 20 decimal places is 1.7579327566180045327. As of now, I cannot find a closed form in terms of some fundamental mathematical constants for this expression.


28
The Lounge / Re: Math Problems
« on: January 20, 2009, 07:28:27 PM »
Quote
The expression you gave diverges. I found a proof.

ORLY?

Actually, I found a mistake in my reasoning, but I still can bet that it diverges.

29
The Lounge / Re: Math Problems
« on: January 20, 2009, 07:12:23 PM »

3

√(1+√(2+√(3+√(4+...)))) = ?

You are correct.

The expression you gave diverges. I found a proof.

30
The Lounge / Re: Math Problems
« on: January 20, 2009, 07:03:55 PM »
My bad. Infinity.

The response remains the same.

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