If the sun could be seen from more than 90 degrees around a ball, as your shitty picture claims, you would only have six hours of darkness each day!
You sure do love your blatant dishonesty don't you?
Especially vague claims backed up by nothing.
The diagram was very much not to scale, to make the regions quite clear.
But instead of being honest and accepting that the RE can easily explain what is observed in reality while your delusional BS has no chance; you instead deflect to the not to scale diagram, and dishonestly misrepresenting it.
Firstly, yet again, the sun is NOT visible. That is the point that is being made. The sun is not visible while light indirectly from the sun is.
Even if the sun was visible for more than 90 degrees, that doesn't magically mean only 6 hours of darkness.
If the sun was visible for 90 degrees, that still gives 178 degrees for darkness.
In reality, the sky is a very thin layer around Earth.
The official border of space is 100 km.
At that point there is basically no air.
If you had a picture of Earth, 1000 pixels wide (so much wider than the ones used), then the atmosphere would appear roughly 8 pixels wide.
It wouldn't provide the details required to easily see the key parts.
So a not to scale diagram is used for greater explanatory power.
If you had even a shred of integrity, what you would do is look at the diagram, see what is required to determine what the angle is, and then actually do the math, with the RE numbers, to see just how large an angle it is. And then do the math to see what kind of time that corresponds to.
As you are too dishonest, and will likely cling to this dishonest delusional BS, here is the math for you (still ignoring refraction, as that complicates the diagram more). First an image, this time also considering the observer height:

Key parts:
We have the radius of Earth as r.
We have the height of the observer as ho.
We have the height of the clouds (for this I have just used the sky) as hc.
The angle we want to find is a.
This is first found by constructing a line, initially level with the observer going out horizontally.
Then we take a line from the observer to the horizon then back up to the clouds, then from the clouds to the Earth to find the angle to where the sun can cause this indirect lighting.
We then extend this last line to meet the first line.
This last line is the direction to the sun, and due to the distance would be at ~ the same angle going through the centre of Earth.
We can translate this angle down to the point on Earth, by drawing a line parallel to the first.
We can then switch it to the inside either using the shortcut regarding crossing lines, or via one of the other regions, as that line on the inside is given by 180 degrees - (180 degrees - a))=a; by noting that angles on a straight line add up to 180 degrees.
We can then transfer this to the centre of Earth by noting that the angle marked in blue is 90 degrees - a, as a line tangent to a circle meets an angle from the centre of that circle to that point at 90 degrees, and then as we have a right angle triangle, the angle at the centre of Earth will be 90 - the angle in blue.
We can also see that the angle at the centre is made up of the angle in the three other right angle triangles, 2 of which are congruent.
For these triangles, we note that the angle at the centre is given by arccos(r/(r+h)).
For one of these it will be r/(r+ho), for the other it will be r/(r+hc).
That means we have arccos(r/(r+ho)) + 2*arccos(r/(r+hc)).
Being generous and putting in an observer height of 0.01 km (10 m) and a cloud height of 100 km (the edge of space); along with Earth's radius of 6371 km, this works out to be ~20 degrees.
And if you plot it with the height of the clouds fixed, we see it take quite a lot of height to change that.
Even with an observer height of 10 km, (~the height of mount Everest) it only increases to 23 degrees.
If we make the height of the clouds more reasonable to 20 km, the angle drops to roughly 10 degrees.
Each hour correspond to roughly 15 degrees.
So that means you have to 0.7 to 1.3 hours of twilight, depending on elevation and what standard you use. And doubling that (for morning and evening) we get 1.3 to 2.7 hours.
Also note that for the day, we have more than simply day defined by the time between sunrise and sunset. Even sites like timeanddate show that.
For example, for quito:
https://www.timeanddate.com/sun/ecuador/quito?month=3&year=2023on the equinox we see "daylight" is 6:17 am to 6:24 pm. This is 12 hours and 6 minutes. This is slightly more than 12 hours due to refraction, the fact that the sun isn't a point and is actually larger than Earth, and that the length of the solar day varies over the year. Refraction and the size of the sun gives roughly 0.75 degrees in the morning and 0.75 degrees at night. That gives a total of roughly 6 minutes. So this is reasonable.
"night" is defined as ending at 5:09 am and starting at 7:33 pm. Notice that this is only 9.5 hours.
The remaining 2.5 hours are for twilight. And notice how that fits nicely in between our 1.3 to 2.7 hours of twilight expected?
And again, the RE explains this quite well.
When the sun sets, that simply means Earth is blocking the view from you to the sun.
But the sun can still shine on objects above you, including the sky and clouds, and the sky clouds which are visible.
The sky will still scatter light, giving you twilight.
It is only once the sun can no longer indirectly hit you like that that you actually get night.
And there are different definitions of twilight:
https://www.timeanddate.com/astronomy/different-types-twilight.htmlAnd, this conversion of angles to time only works simply at the equator.
This is because the angle is what is important not how much time after sunrise or sunset.
At the poles, the rotation of Earth doesn't dictate that angle, the position of Earth in its orbit does, so twilight can last for days.
Conversely, this makes no sense in the FE model.
If you appeal to light magically dying, then if the light from the sun is too weak to reach your eyes, then it will certainly be too weak to scatter off the sky and reach your eyes, and even more so to scatter off the clouds to hit some surface and scatter off that to reach your eyes.
So once more, the RE model works while the FE model is clearly delusional garbage.
And if you had a basic understanding of geometry and chose to honestly analyse this you would come to the same conclusion.
Unlike your extremely dishonest representation where you claim the RE magically means you only have 6 hours of night, we see that the RE model produces the observed result.