Because Newton later said it?
No, that was Archimedes (translated).
Even in their time, they knew of weight, and treated weight separately to buoyancy.
What they didn't know was why there was weight.
Originally, it was called gravitas. (not translated).
Here is the translated version of Archimedes principle:
"Any object, totally or partially immersed in a fluid or liquid, is buoyed up by a force equal to the weight of the fluid displaced by the object."
i.e. buoyancy is an upwards force.
It relies upon a downwards force (weight).
You are the one trying to hijack that and change it.
How scientific!
Yes, how scientific, to follow the evidence to gain a better understanding of the world to provide better explanations.
Instead of your entirely unscientific approach to reject anything which doesn't fit your fantasy.
The original version of buoyancy involves density, and dates to about the 3rd century BC.
No, I provided the original, which involves weight.
You can extrapolate from that to get a result that for objects denser than the fluid, the weight will be a greater force and so the object will sink, and for objects less dense than the fluid, the buoyant force will be greater so it will rise, until it goes above the surface of the fluid and the weight of the fluid displaced will be equal to the weight of the object.
Gravity is a newer invention, going back to the 17th or 18th century.
No, Newtonian gravity (and later Einsteinian) is a better understanding of that force called weight.
But we can tell that there is no opposing force rather easily by the ease that this scrawny bird can fly.
Why must you cling to this dishonest BS even though it has been refuted countless times?
Birds rely upon their wings so they can fly.
They are also quite light, so only a small force is needed to keep them up.
Take off their wings, and they fall, being unable to fly.
If gravity wasn't real, wings wouldn't be needed.
That gravity is measured in "meters per second"
This entirely depends upon what you are measuring.
If you are measuring the strength of a gravitational field you measure it in units of N/kg. That is equivalent to m/s^2. (not meters per second)
Just like for an electric field you measure it in units of N/C, which is simplified to V/m.
If you want to know the force on an object, that is measured in N.
To get an idea of how mathematically insignificant gravity is, this is 0.0000000000668 (may have missed a zero somewhere).
All this shows is how weak it is, and demonstrates how dishonest your attempted experiments to refute it are.
Earth is massive, so the force is significant.
Your motor cycle and rock are quite small, so the force between them is insignificant.
To say nothing of basically recycling numbers, any sensible rounding would round to zero
...
You cannot use the total mass of Earth in an equation because the whole includes the parts.
Gravity's force, therefore, is zero. Because it will always only be the mass of its parts, and none of those parts is anywhere near that mass, nor do any of them exert real gravitational force.
And there you go failing basic math again.
If you consider a tiny object, then yes the force will be basically 0.
But whenever you are doing calculations like this, you should not round prematurely.
If you add up all those tiny forces, you can get a significant force.
Just like you can do with the mass of an object.
Remember, people are made up of tiny molecules, in fact they are made up of tiny atoms (which are further made up of subatomic particles).
One of these is hydrogen, with a mass for each atom of roughly 0.00000000000000000000000000167 kg.
Another is carbon, with a mass per atom of 0.00000000000000000000000001993 kg.
Another is oxygen, with a mass per atom of 0.00000000000000000000000002657 kg.
So should we say all of these are basically 0, and therefore deem that in total your mass should be basically 0?
Or should we do it honestly, and add up each and every little bit, until we get the total mass on the order of 10s to hundreds of kg?
When you add up a tiny number a lot of times, you can get a big number.
If I took 0.1 c from every person living on Earth, I would have roughly 7 million dollars.
So to calculate the force of Earth, you need to add up all those tiny forces.
Fortunately, for a spherical symmetric object that you are outside of, you can treat it as a single point in the centre and get the same result.
The other problem with your "calculation" is that you are just happily sticking in random numbers with no explanation and no units.
Is it a 2500 kg motorcycle with a 5 kg rock which is 15 m apart?
You are also just arbitrarily setting F to 1, which means you aren't even coming close to calculating the actual value of G.
You are entirely ignoring the observation and just making shit up.
And even doing that you entirely fail with basic math.
You set the force to 1, and to calculate G, to then calculate F.
If you did that correctly, you would get F=1.
Instead, you entirely failed to get any numbers which make any sense at all.
If you want to set the force between your 2500 kg motor bike and 5 kg rock at a distance of 5 m to 1 N, then G must be 0.018.
Instead of taking that value, you "rearranged" the equation:
F=GMm/r^2 into:
"G"=G*F*r^2/(M*m).
Notice the problem?
You are taking the value of G, and just scaling it by a factor of F*r^2/(M*m) to make it smaller, with you arbitrarily setting F to 1.
You then take that smaller version to effectively get G out.
i.e. you substitute that BS into your above equation to get:
F=(G*1*r^2/(M*m))*M*m/r^2, which simplifies to G.
So why not try doing it properly, considering you already have the value of G?
Doing that will give you a force of 3.7*10^-9 N
Quite different to the 1 you presumed, and different to the pure BS you came up with your "math".
By dividing the weight of the earth into the equations for gravitational constant, you always get get an artificially large negative exponent, which is then balanced artificially by multiplying the entire equation by itself.
Because you are just doing dishonest BS, not actual math.
Lets do it properly shall we?
Substituting in the mass of Earth as 5.9722*10^24 kg, the mass of the hummingbird as 0.0025 kg, the actual value of G, rather than your delusional BS, and a distance of 6371000m (the distance to the centre, what is need for a treatment of a spherically symmetric object); we end up with a force of 0.025 N.
So small, but still significant.
In both cases, despite adding a freakish load to the equation, I nearly got nearly the same thing I started with
Yet, instead of that giving you pause and having you wonder if you entirely screwed up your "math", you just post that pure BS here to pretend there is a problem with gravity.
There is no problem with gravity. There is a problem with you.
All your BS math can boil down to this dishonest equation:
"F" = (G*1*r^2/(M*m))*M*m/r^2
which simplifies to:
"F" = G.
You aren't calculating the force.
You are taking the value of G, and using it to "calculate" the value of G along with a few other numbers.
Even if you didn't complete screw up your equation to "calculate" G originally, you would have started with the same assertion that F=1, and so would have ended up with wildly different values of G and the same force of 1 N for both, because that was your assumption.
All that complicated math led nowhere.
i.e. your BS lead no where.
The question now is did you do this knowingly to pretend there is a problem with gravity, or are you really that far gone and that bad at math that you thought that what you were doing was correct?
Are you going to be honest enough to admit you7 entirely screw up, and all your calculations demonstrate is your complete inability to do math or your blatant dishonesty?
Again.
Again, the honest one:
Weight (gravity) > Buoyant force: object sinks.
Weight (gravity) < Buoyant force: object floats.