Role of gravitational force F=GMm/d^2 b/t two objects?

But that doesn't mean that the mass is making it accelerate faster. The change in distance to the other object, by the other object moving is what does. It doesn't show any fault with the theory

Yes, it makes it faster; don’t forget it is a gravitating mass as well, which accelerates the falling masses. Reduction in the “d” w/o increased speed in less time is impossible.

All objects fall at the same speed. This means an object’s weight will not change its falling speed. Both identical spheres with different masses (A and B) act as two point loads. The rule is the rule. If things change at contact then the equation w=f=GMm/d^2 is invalid thereat.

There is a difference b/t “a” and “g”. Falling mass doesn’t matter in the latter case.

If it is the strange phenomenon that “g” doesn’t depend upon the falling mass then the above settlement should be odd as well but in reality, it is not true.

Why would A feel weightless in a state of free fall?

The only force in free fall acting A is gravity – a non contact force. It is said force of gravity can’t be felt without any other opposing forces. The force of gravity doesn’t exit alone. There is always an equal opposing force of gravity to it. This is counteracted by the force of gravity of falling mass. Call it a non-contact in air or space is also wrong because two objects separated by distance “d” in space or air are always in contact with each other due the gravitational force that exists in b/t them. Similarly, if A has sensation of free fall due to the said gravitational force then there is no way A doesn’t feel force of gravity that supports A in falling downward direction with “g”.  Uniform velocity may not be felt but acceleration is always felt.

The force of gravity pulls the body of A towards its center if stands on the ground. There is always an equal but opposite force called the normal force “N” that pushes A in a direction opposite to the force of the earth. It is this force due to which A perceives the force of gravity as weight.

The force of gravity of A pulls the earth towards its center if the earth is placed on A. There is always an equal but opposite force called the normal force “N” that pushes the earth in a direction opposite the force of gravity of A. It is this force due to which earth perceives the force of gravity as weight.

Here mage = Mega = N = N

Both normal forces of equal magnitude but opposite in direction cancel other. So neither A nor earth feels force of gravity of one another.

It is also said that earth also experienced an equal gravitational force from an apple in opposite direction but the acceleration at which an apple falls is greater than the acceleration of earth towards the apple.

Now, come to setting

As explained above, there is no force that exists in b/t the A or B (identical spheres of different masses)  and the earth then how come A and B settled in ground. Similarly, even if A and B experience greater acceleration in the absence of any gravity forces as compared to earth then how come one settled greater than the other when both A and B have the same speed?

All above may be wrong but let there is an object A that rests on the surface of the earth in the absence of all other gravities. A falls on earth due to F = GMm/d^2 and therefore it has “g=9.8 m/s/s = GM/d^2”. Let the earth is suddenly disappeared beneath the A.

Would A remain at rest at its original position in space or moves at a velocity of 9.8 m/s in the direction in which it was attracted before the disappearance of the earth?
 
My answer is it would stay at its original position instead of moving at its final velocity of 9.8 m/s. A has to go through acceleration before attaining a velocity of 9.8 m/s and acceleration needs force of whatever kind for its generation. As explained above “mage = Mega = N = N”. No force means, no acceleration and velocity.

So does "g=9,8 m/s/s=GM/d^2 valid on the surface of earth?

Justify, please!

TY

All objects fall at the same speed. This means an object’s weight will not change its falling speed. Both identical spheres with different masses (A and B) act as two point loads. The rule is the rule.

The rule is g=GM/d^2.
The point of that it doesn't matter what the mass of the falling object is, that value of g will be the same if M and d are the same.
If you change d, you change g.

Why would A feel weightless in a state of free fall?

For the simple reason that gravity acts on all parts of the object. But people don't feel a force applied to them, nor velocity, nor acceleration. Instead they feel their body transmitting a force. And the same effectively applies to all objects.

For example, if you are in a car and you slam on the accelerator, what you actually feel is the chair pressing into your back and your body then transferring that force to the rest of you.

A simple way to understand it is to consider a spring with a mass at each end.
If you push against one end, the spring compresses which results in it pushing the other end. The more you push, the more it is compressed.
If you instead pull the end, the spring is stretched, which results in it pulling the other end.
That compression and stretching is the force being felt.

But if you grab both ends and move it together, the string isn't compressed or stretched.

The force of gravity doesn’t exit alone. There is always an equal opposing force of gravity to it.

Acting on the other object.
We have been over this plenty of times.

If you have 2 objects, A and B, they apply a force to each other.
Object A can be in free fall towards object B and B can be in free fall towards object A.

Call it a non-contact in air or space is also wrong

A contact force is not saying the 2 objects are connected by a force.

Instead, it indicates that a force was a applied to a point of contact on the object, and then transferred through the object.

The force of gravity pulls the body of A towards its center if stands on the ground. There is always an equal but opposite force called the normal force “N” that pushes A in a direction opposite to the force of the earth. It is this force due to which A perceives the force of gravity as weight.

I would not say always. That is the case when A is standing stationary on the ground.

Both normal forces of equal magnitude but opposite in direction cancel other. So neither A nor earth feels force of gravity of one another.

They feel the normal force, not gravity.
But gravity is still there, or else the normal force would result in them being pushed away from each other.

As explained above, there is no force that exists in b/t the A or B (identical spheres of different masses)  and the earth then how come A and B settled in ground.

That was not explained above.

how come one settled greater than the other when both A and B have the same speed?

For a similar reason that throwing a lightweight ball at a wall will have it bounce off, while a much heavier ball smashes the wall.
It is not simply based upon speed or acceleration.

So does "g=9,8 m/s/s=GM/d^2 valid on the surface of earth?

Yes, F=mg.