*you are unable to provide any evidence for your astonishing claim the sun is a paltry 600meters in diameter.*But I have already provided the answer four times.

Which means you are trolling this thread.

How many times does an answer need to be run by you before it dawns on you?

Algebraic approach to time-delay data analysis: orbiting case

K Rajesh Nayak and J-Y Vinet

https://www.cosmos.esa.int/documents/946106/1027345/TDI_FOR_.PDF/2bb32fba-1b8a-438d-9e95-bc40c32debbeThis is an IOP article, published by the prestigious journal Classic and Quantum Gravity:

http://iopscience.iop.org/article/10.1088/0264-9381/22/10/040/metaIn this work, we estimate the effects due to the Sagnac phase by taking the realistic model for LISA orbital motion.

This work is organized as follows: in section 2, we make an estimate of Sagnac phase

for individual laser beams of LISA by taking realistic orbital motion. Here we show that, in general, the residual laser noise because of Sagnac phase is much larger than earlier estimates.

For the LISA geometry, R⊙/L is of the order 30 and the orbital contribution to the Sagnac phase is larger by this factor.

Are you able, scientifically, to understand what I have just posted?

Here are the direct quotes:

https://web.archive.org/web/20161019095630/http://tycho.usno.navy.mil/ptti/2003papers/paper34.pdfDr. Massimo Tinto, Jet Propulsion Laboratory, Principal Scientist

In the SSB frame, the differences between back-forth delay times are very much larger than has been previously recognized. The reason is in the aberration due to motion and changes of orientation in the SSB frame. With a velocity V=30 km/s, the light-transit times of light signals in opposing directions (Li, and L’i) will differ by as much as 2VL (a few thousands km).

SSB = solar system barycenter

Published in the Physical Review D

https://arxiv.org/pdf/gr-qc/0310017.pdfWithin this frame, which we can assume to be Solar System Barycentric (SSB), the differences between back-forth delay times that occur are in fact thousands of kilometers, very much larger than has been previously recognized by us or others. The problem is not rotation per se, but rather aberration due to motion and changes of orientation in the SSB frame.

The kinematics of the LISA orbit brings in the effects of motion at several orders of magnitude larger than any previous papers on TDI have addressed. The instantaneous rotation axis of LISA swings about the Sun at 30 km/sec, and on any leg the transit times of light signals in opposing directions can differ by as much as 1000 km.

Aberration due to LISA’s orbit about the Sun dominates its instantaneous rotation.

The formula is 2VL/c.

V = RΩ

The ORBITAL SAGNAC calculated at the Jet Propulsion Laboratory amounts to an admitted difference in path lengths of 1,000 kilometers.

The difference in path lengths for the rotational Sagnac is 14.4 kilometers:

https://arxiv.org/pdf/gr-qc/0306125.pdf (Dr. Daniel Shaddock, Jet Propulsion Laboratory)

https://gwic.ligo.org/thesisprize/2011/yu_thesis.pdf (pg. 63)

As for the discoidal Sun, here is your pal proving exactly this point:

Of course, the surface gravity of the Sun is roughly 274 m/s^{2}!

And here is another way to check that 274 m/s^{2} value for the Sun's surface gravity.

Average distance from earth to Sun: 149,597,870,000 m.

*Radius of Sun*: 695,510,000 m

*Sidereal year*: 31,558,150 secs

Hence *Earth's orbital Angular Velocity* = 2 x π / (Sidereal year) = 1.99099E-07 rad/s

Hence *Earth's centripetal Acceleration about Sun* = (1.99099 x 10^{-7})^{2} x (149,597,870,000) = 0.005930 m/s^{2}.

But the (*Sun's gravity at the Earth*) = (*Earth's centripetal Acceleration about Sun*) = 0.005930 m/s^{2}.

Now the gravity due to the Sun decreases as 1/(*distance from the sun*)^{2}.

The Earth is 149,597,870,000 m from the Sun's centre and the Sun's surface is 695,510,000 m from the Sun's centre.

Therefore the Sun's gravity at its surface = 0.005930 x (149,597,870,000/695,510,000)^{2} =** 274.35 m/s**^{2} - *QED*.

So that agrees quite well with the surface g of the Sun as calculated from its mass, radius and the *Universal Gravitational Constant* - funny that!

Therefore, the value of 274 m/s2 RESTS ENTIRELY ON THIS STATEMENT:

*Hence Earth's orbital Angular Velocity = 2 x π / (Sidereal year) = 1.99099E-07 rad/s*If the Earth is not orbiting the Sun, a(sun) DOES NOT equal 274.35m/s2: IN FACT IT IS EQUAL TO ZERO.

Then, we are left with the centrifugal acceleration: a

_{c} = 0.0063 m/s

^{2}.

Algebraic approach to time-delay data analysis: orbiting case

K Rajesh Nayak and J-Y Vinet

https://www.cosmos.esa.int/documents/946106/1027345/TDI_FOR_.PDF/2bb32fba-1b8a-438d-9e95-bc40c32debbeThis is an IOP article, published by the prestigious journal Classic and Quantum Gravity:

http://iopscience.iop.org/article/10.1088/0264-9381/22/10/040/metaIn this work, we estimate the effects due to the Sagnac phase by taking the realistic model for LISA orbital motion.

This work is organized as follows: in section 2, we make an estimate of Sagnac phase

for individual laser beams of LISA by taking realistic orbital motion. Here we show that, in general, the residual laser noise because of Sagnac phase is much larger than earlier estimates.

For the LISA geometry, R⊙/L is of the order 30 and the orbital contribution to the Sagnac phase is larger by this factor.

Therefore, the value of 274 m/s2 RESTS ENTIRELY ON THIS STATEMENT:

*Hence Earth's orbital Angular Velocity = 2 x π / (Sidereal year) = 1.99099E-07 rad/s*If the Earth is not orbiting the Sun, a(sun) DOES NOT equal 274.35m/s2: IN FACT IT IS EQUAL TO ZERO.

Since the GPS satellites ARE NOT registering/recording the missing ORBITAL SAGNAC, that means that the Earth is not orbiting the Sun.

This is the fourth time, today, where I have answered those specific questions.

If you are unable to follow scientific papers, or to understand them, use the CN. Here you are spamming this thread.