Linear speed increases with a factor of the radius. So a point on the surface of your fabled rotating globe would be travelling 5,102,400 times as fast as the 24hr merry-go-round of 5m diameter... Centripetal force then increases with the square of that tangential velocity. Are you sure that is the comparison you wanted to make?

If the Earth were flat and non moving the stars would be the same every night right?

Why? Why don't you put a moment's thought into the question and see of you can figure out the celestial sphere for yourself?

You have no idea what you are talking about. Let’s do some math...

Earth’s circumference at the equator is about 40,075 km. On equator surface, Earth moves at 464 m/s (1,044 mph).

The Earth’s rate of rotation is about 15 degrees per hour, .0042 deg/s, one rotation per day.

Earth’s average radius is about 6,370 km.

Centripetal acceleration at the equator... a = v^2/r, is about .034 m/s/s.

Let’s look at centripetal force in the United States:

At the U.S. latitude of 39 degrees, the radius from the surface to the axis of rotation is about 4,951 km and the Earth’s linear velocity 360 m/s (811 mph)

centripetal acceleration (a=v^2/r) is .026 m/s/s

F=ma, so 1 kg mass (2.2 lb at Earth’s surface) * .026 m/s/s results in a centripetal force of .026 Newtons (N)

weight in lb (at the Earth’s surface) / 2.2 = mass in kg

Multiply mass in kg by centripetal acceleration, .026 m/s/s = centripetal force in Newtons (N)

Convert Newtons (N) to lb: force in N / 4.45 = force in lb.

Centrifugal Force= (( lb / 2.2 ) * .026 ) /4.45

cf = ( lb * .012 ) / 4.45

cf = lb * .0027

Take your weight in lb times .0027 to get the centripetal force felt at U.S. latitude of 39 degrees.

100 lb object = 0.27 lb centrifugal force

150 lb object = 0.40 lb centrifugal force

200 lb object = 0.54 lb centrifugal force

Ski, let’s assume you weigh 200 pounds like the rest of us in America carrying a little extra weight. In the middle of the U.S. you would feel about .54 lb of centrifugal force...

Force of Gravity >>>>> Centrifugal Force. So, no, water has no problems sticking to the Earth and no, a 200 pound person isn’t going to be thrown off the surface by half a pound of force.