But not through the 4500 km of atmoplane on a flat earth, No way José.
Where the hell are you getting that figure from?! Or you you too just pretending the atmosphere doesn't lose 90% its density at just 16km altitude? Good luck getting to 4500km with that.
No, Jane, I do not pretend!
And I was presenting the 4500 km as the length of the light path to see the "see the UK from the East Coast", which is the topic.
Learn a little about
Rayleigh and Mie Scattering,
scale height and
extinction distance and I'll try to explain it further.
But a couple of points might be relevant.
On the Globe, because of curvature, we never look through an effective atmospheric distance of more than roughly 300 km, based on a
scale height of 9 km.
But on a flat-earth, ignoring possible refraction, seeing an object on the surface (horizon?) looking at a distant object (mountain or lighthouse) means looking through that "thickness" of Atmoplanic.
Very roughly, even in the clearest air, each 60 km (approximate
extinction distance) reduces the contrast by a factor of roughly
e.
You do the sums but a couple of realistic cases (on the Globe) are:
Looking at the sun, moon or a star:
directly overhead though an effective atmospheric thickness of about 9 km (one
air mass to an astronomer) reduces contrast (intensity) by a factor of about 1.16 and
on the horizon though an effective atmospheric thickness of about 300 km reduces contrast (intensity) by a factor of almost 150.
I believe that you'll find those not far off when comparing the illumination from the sun when overhead and near sunset.