You already posted this garbage. The problem is you are confusing angular size and real size.

Again, here is a more accurate picture:

If you want to try drawing pictures showing what is being obscured, including lines going from the eyes, you need to use the real size.

If you want to use one based upon angular size, a picture isn't really needed, instead just numbers can be.

However if you did want to draw a picture, then the y axis would be angular size and thus the region blocked by the wave would be a horizontal line, not starting at the eye.

The eye position would be at 0. Anything below the eye would be at a negative angle, anything above would be positing.

Lets not bother with such a picture and instead just use the numbers.

Firstly, your person is 1.65 m high (at least there eye height is there). That is the reference you would use. So assuming they are looking straight out (i.e. level, that is what you need to focus on.

This means the wave, which is 1 m high, would actually be referenced as 0.65 m below the eye line.

This puts it (assuming it is still 5 m away) roughly 7.4 degrees below your eye line. Thus anything above these 7.4 degrees would not be blocked by the wave.

So let's see how far down an object has to be again, using 150 m for the distant building/object to be below 7.4 degrees. (note we don't even need trig, we can just use similar triangles for this). As it is 30 times as far, the object needs to be 30 times lower.

This means that in order for the wave to obscure the object entirely, the top of the object would need to be 19.5 m below you. That gives it a height of -17.85 m.

Stop just spouting nonsense. Actually address what has been said.

If you don't want to debate, go back to the preaching section.