Its vice versa, global can’t be exist without gravity because all the rounded earth rules built on the gravity
No. People knew it was round long before they understood gravity.
Thanks, yet I wonder how a tiny ballon filled by helium Can beat the Gravity power!
So what you mean is you have no idea what you are talking about at all and instead just make up pathetic strawmen to pretend there is a problem.
Helium doesn't beat gravity. It loses.
Air wins, falling down, pushing the balloon out of the way.
If you would like to know how gravity factors into it, consider an object with a density of po, in a medium with a density of pm.
This object can be approximated as a cylinder (or a series of prisms).
It has a height of h, and a cross sectional area of A.
At the top of the object, the medium has a pressure of PT.
At the bottom, due to gravity, the medium has a pressure of PB=PT+pm*h*g. This is because for a given area (a), the weight of the air in the column is given by F=m*g, m=pm*V, V=h*a.
F=pm*h*a*g.
The pressure due to that is P=F/a=pm*h*g.
So at the bottom you have that extra pressure.
So the object experiences a downwards force of Fd=PT*A+po*A*h*g (this last part is m*g for it).
It experiences an upwards force (from the bottom) of Fu=PB*A=(PT+pm*h*g)*A
Thus the net force (upwards for simplicity) will be Ft=TFu-Fd=PT*A+pm*h*g*A-PT*A-po*A*h*g
=A*pm*h*g-po*A*h*g=A*h*(pm-po)*g=V*g*(pm-po).
For objects much denser than the medium they are in, they sink. Otherwise they rise.
This is different to the normal idea of all objects beings accelerated equally.
However, the density of air is roughly 0.0012 g/ml. The density of most other objects are much higher. Water is 1 g/ml, so that tiny difference doesn't normally effect it. But for some objects, like balloons it does. (There are also issues of air resistance as it moves).
If you feel that Im stupid please stop answer
I will answer regardless so others can see the answer.