You are counting poles PAST THE HORIZON to calculate distance to the horizon.
Maybe this will help...
You should be using the 22 towers TO the horizon not all that are visible.
22 stanchions spaced 950 feet apart
22 x 950 = 20,900 feet.
20,900/5280 = 3.96 miles
Just what is expected for someone standing in a boat (about 10').
No.
I can see the stanchions also past your point indicated on the photo.
That means I can see individual stanchions to an horizon seven miles out.
According to RE-tard math, not possible.
Are you just playing dumb to avoid admitting that you are wrong or can you possibly be that stupid?
I'll give you another chance since you're such a nice and charming guy with this analogy.
You are standing in a field looking down a fence that as 37 posts spaced 10' apart.
There is another fence that runs perpendicular to fence one and intersections fence one at post 22. Post 22 is shared by both fences.
The question arises how far away is fence two (the horizon)?
I'll even make it multiple choice to help you.
How far away is fence two(the horizon)A. There are 22 posts to fence two(the horizon) therfore 22 x 10' = 220'
B. There are 22 posts to fence two(the horizon) and there are 15 posts past fence two(the horizon) therefore 37 x 10' = 370'
C. I cannot answer this question on the grounds that it proves me wrong, dumb, or both.
My advice is to stop digging.