So spherical geometry works perfectly on the surface of the earth, does that suggest anything to you about the shape of that surface?

My god you're dense.

Really?

The distance from the North Pole to the South Pole on the Globe and on the usual flat earth map is a little over 20,000 km.

For the Globe, according to Wikipedia, the polar circumference is 40,008 km

For the Flat Earth "24,900 miles is the diameter of the known world", so "rim to rim" the earth is 40073 km - close enough.

So on both the Globe or the flat earth, the distance from the North pole to the equator is close enough to 10,000 km.

Now the equatorial circumference of the real earth is 40,075 km, close enough to 40,000 km.

I would like you to fit those dimensions onto your flat earth.

You insist that

**circumference = 2 × π × radius** and

*it is* on a flat surface.

But on the real earth

**circumference = 2 × 2 × radius**.

Now, I (we) did say elsewhere that in

*non-Euclidean geometry*. as on the surface of a sphere,

**circumference ≠ 2 × π × radius** and in

*Spherical Geometry*, as on the surface of a sphere

**circumference < 2 × π × radius**.

The bottom line is that the

**Equatorial Circumference = 4 × (North Pole to Equator distance)** fits on a sphere but not on a plane surface.

In other words

*the measured dimensions of the earth will not fit on a plane surface*.

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**The Flat Earth Myth Disproved**