That post was a joke 
I was making fun at just how ridiculous your Heliocentric model is.
It is impossible for the Moon's shadow to move the opposite way to the Moon itself when the earth's angular velocity is allegedly 27 times greater than the Moon's alleged actual velocity.
It is impossible for any object to cast a shadow 24 times smaller than itself.
I cannot imagine anyone being so ignorant of the geometry of shadows you ever even think that!
Look at this diagram:That should make it completely obvious that
- if the light source size is greater than the size of the object, then the umbra is smaller than the size of your object,
- if the light source size is equal in size to the object, then the umbra is equal in size to the object and
- if the light source size is less than the size of the object, then the umbra is greater than the size of the object.
This should help you figure out the direction the moon and it's shadow travel. No magic just basic trigonometry and relative motion.
Further, see my previous post. It will straighten out your misconceptions on the size of the moons shadow.
Mike
No, that video is nonsense and contradictory.
It claims the Earth's angular velocity is up to 79 times greater than the Moon's actual velocity.
I haven't found the bit where "It claims the Earth's
angular velocity is up to
79 times greater than the Moon's
actual velocity".
Would you please point out where it says that.
Nobody disputes that
Earth's angular velocity is greater than the
Moon's angular velocity, though on average by 29.5306 times.
Then at the end it claims the Moon's velocity is greater than the Earth's angular velocity using a video from NASA .
No it doesn't! You simply cannot compare
the Moon's velocity with
the Earth's angular velocity.
Velocity has the units
distance/time or metres/secs, while angular velocity has the units
angle/time or radians/sec.
So you are comparing quite different things -
chalk and cheese.
What you must compare is the
surface velocity of the earth where the eclipse will pass with the
velocity of the moon's shadow.
And
tangential (or surface velocity) = angular velocity (in radians/second) times the radius!
The radius of the earth at 40° latitude =
cos(40°) x 6.366 x 106 = 4.876 x 106 m.
The angular velocity of the earth =
(2 x π)/86400 = 7.272 x 10-5 radians/sec.
So the earth's surface velocity (in the middle of USA) is
4.876 x 106 x 7.272 x 10-5 = 356 m/s.
The radius of the moon's orbit averages
3.850 x 1008 m.
So angular velocity of the moon afound its orbit is
(earths angular velocity/29.5306) = 2.463 x 10-6 radians/sec.
And the orbital velocity of the moon is
3.850 x 1008 x 2.463 x 10-6 = 948 m/s.
So even though the
moon's angular velocity is much less than the
angular velocity of the earth,
the
moon's orbital velocity is somewhat more than the
surface velocity of the earth.
The moon's shadow travels very slightly faster (about 0.25%) than the moon's orbital velocity.
And the speed of the shadow from west to east is just the shadow's velocity less the surface velocity of the earth.
Exactly as everyone, except
Mr Ignorance.is.Wonderful now seems to understand.
Everyone can verify that the earth's angular velocity is greater than the Moon's actual velocity as the Moon rises in the East and sets in the west every day.
You cannot compare
angular velocity with
actual velocity - they are "different animals"!
When the moon rises, where it appears in the sky and when it sets
all depend on the relative angular velocities.
But the moon's shadow is cast from the distant sun from the moon moving at 3413 km/hr.
Most people can verify that the Earth's actual rotational velocity does not determine what we see in the sky as in the north pole where the rotational velocity is negligible on your heliocentric model; the moon the sun and the stars still do a full rotation " EVERY DAY "
Are you daft? It is the angular velocity that determines what we see "in the sky", but the moon's shadow is not something that is seen "in the sky"!
Your Heliocentric model does not match reality and as such is FALSE.
So the
Heliocentric Globe fits precisely what we see in reality!
Now, where is this detailed flat earth explanation of the solar eclipse, explaining just how an umbra up to 494 km across can be caused by a 50 km diameter sun and a 50 km diameter moon?
Bye bye - go and dream about you imaginary
neo-Flat Earthism Religion, because that's all it is - a dream!
[/quote]
What a load of nonsense a shadow is caused by the object blocking the light not the light itself.
As I have said the rotational velocity does not determine what we see in the sky.
For example at the north pole where the rotational velocity is negligible the Sun Moon and Stars do a full rotation every day this is due to the angular velocity so your explanation is nonsense.
Light travels in straight lines the moon's shadow will be directly below the moon as a solar eclipses occurs when the Moon passes between the Sun and the Earth on your model so the light source the sun is directly behind the moon and the earth is directly in front.
Your fooling no one .
Didn't think you was stupid enough to get involved in this one.
Your reputation will not recover from this
Your Strange Heliocentric Religion is finished.