I did show you the math, showing the actual volume of air displaced rather than your pathetic strawman where you only looked at the volume of the helium atom rather than the volume of air displaced.
Are you saying that by placing one atom in a chamber that it will not displace anything?
Talk about a strawman argument…
Yes, talk about a strawman argument, where you go to the complete opposite of what I said.
If you put a helium atom in a chamber at any "normal" temperature, it will displace more than the volume of the atom, much more.
Where did I (or anyone) ever indicate that it wouldn't displace anything?
The person closest to suggesting that would be you.
We are talking about 1 atom in a box with loads of other atoms, comprising a gas, which thus will displace more than just the physical volume of the atom.
Please make up your mind if the Helium will displace anything or not. You are jumping back and forth, in your assumptions.
No, I'm not.
I have continually said that helium will displace the gas unless it is a liquid, in which case the air would be as well, unless you go to magic fantasy land.
So no, I have been consistent in my assumption that the helium atom will behave realistically.
So why are you trying to apply it to a gas?
Hello, anybody home, a gas is a form of a liquid. Oh really what makes a hot air balloon go up in the air, gravity? Then my next question is what keeping you down, because you write with a lot of hot air…
No it isn't.
Both gases and liquids are forms of fluids.
Fluids are substances which flow freely (i.e. you don't need to break it up) and conform to the shape of their container.
Liquids are one with a fairly constant volume, while gases will expand to fill the volume of their container (at least at small scales while the pressure is still significant).
So no, a gas is not a liquid.
My point was that you were wrong, yet again. Are you going to admit it this time?
Yes it does. If the helium is frozen without any thermal energy, it will not rise.
Stop trying to change the subject. I never ever said at what temperature the helium atom is. You are trying to weasels your way out of this and you can’t!!!
No, you didn't directly say it. But the only way for it to only displace the size of the atom is if it is at 0K.
So your analysis requires the temperature to be 0K. As such, it doesn't matter if you said it or not, it is a requirement of your analysis.
Stop trying to weasel your way out of this, you can't.
We are talking about volume of air displaced, which again is dependent on temperature and pressure.
Are you telling the world that if I place one Helium atom in the chamber of the size of 1 cubic meter , that the temperature and pressure will change. Are you in grade school and not taken any chemistry class….
No, when did I ever say this?
However, if you don't remove anything from the box and the box cannot expand, then you cannot keep the temperature and pressure constant by introducing a gas molecule to it.
Remember, PV=nRT=NkT. As we are dealing with atoms, I will use the latter form:
PV=NkT
N=PV/kT
Now then, your volume is constant, k is a constant.
You wish to keep the Pressure and temperature constant.
That would require N to be constant.
So how about you tell me this?
How do you plan to change N (the number of atoms in the box) without changing any of the other parameters?
You can also do this focusing on the air in the box excluding the helium atom.
In this case you can get this form:
V=NkT/P
Now, N is constant (as you aren't taking any of the air out of the box), k is a constant and you want to keep T and P constant.
That means the volume the gas takes up must be constant.
So how are you planning on putting some helium gas in to displace some of the air to reduce the volume occupied by the air?
Are you still in pre-school?
Haven't you learnt that in equations (or relations) like that, you cannot just change one variable, you need to change at least 2?
I just realized that I can’t discuss with you about this subject because you have no idea what you are talking about.
You mean I understand too well and will keep on refuting you, so you need to find some excuse to ignore me?
How about you go to the below thread and try to answer the question of a free body diagram of a real airplane taking off and landing on real runways
How about you stop trying to detract from your failings and instead just admit you were wrong?