I am not 'manipulating' space at all. All I do is move forward with the almost universally accepted laws of Newton's Motion and the conjecture that gravity is a pseudo-force. If you accept those two tenants, which the bulk of modern physics is based upon, you must accept that satellites are traveling straight lines and thus the earth is flat.
Yes. You are. Gravity being a pseudo-force doesn't mean the satellites are travelling in straight lines.
Again you completely misrepresent the equivalence principle.
What the principle actually states is that you cannot distinguish between a satellite orbiting Earth, and Earth orbiting that satellite. The 2 are equivalent.
In the first case the satellite is being accelerated towards Earth resulting in a circular orbit. In the second, instead Earth is accelerating towards the satellite producing a circular orbit around the satellite.
So using the equivalence principle, the satellite is stationary, not moving in a straight line, and the lines from it to Earth are not parallel. Instead they diverge from the centre.
So yes, you are manipulating space.
Also, if you think our understanding of physics is so flawed, why continue with Newton's laws?
If what you are suggesting is true, and gravity is a pseduo-force that doesn't cause acceleration such that objects travel in a straight line, then how do things fall?
There is no force to accelerate them towards Earth.
First off, a perfectly orbiting satellite is in an inertial frame of reference. This can easily be seen by realizing that these silly balls are supposedly in 'free-fall' and exhibit microgravity. This is why the FoR are called inertial and non-inertial - based on whether from their FoR they exhibit the laws of inertia or as we often call them Newton's Laws of Motion. As we know from Newton's laws, if an object is in an inertial frame of reference it must either be still or traversing a straight line. If it were accelerating, which means a change in speed or direction, they would not be in an inertial frame of reference
No. They aren't.
A free-fall condition is inherently non-inertial as it involves acceleration.
You even admitted that in your blog post:
They both are accelerating frames of reference.
An accelerating reference frame is a non-inertial one.
Do you notice how you are now going around in circles?
You claim it is an inertial reference frame to claim it is travelling in a straight line to claim it is in an inertial reference frame.
It doesn't work like that.
Your explanation is also completely wrong.
An inertial reference frame is one that is not accelerating. It has nothing to do with the objects inside it. It is entirely to do with the reference frame itself.
In the case of a frame orbiting Earth, or the case of a frame in free fall, it is accelerating.
Either perfect satellites do not exhibit weightlessness, or they are traveling in straight lines. You will have a very hard time avoiding this conclusion, but I'm eager to see you attempt it.
They don't even exist. If they did, in order to experience complete "weightlessness", the satellite would have to be massless and everything would be in a single point. But that wouldn't require it to be travelling in a straight line.
Otherwise, there would be weight, but so tiny it isn't funny and more complicated due to the orbit.
Some "simple" math:
The acceleration due to gravity is GM/r^2.
The acceleration required for a circular orbit is omega^2*r (I'm not sure if I should use this one or v^2/r, to try and maintain the same orbital period, as the fixed sections of the craft would, or to maintain the same velocity as passengers in the craft that are drifting back and forth would).
For the orbit, they need to be equal, thus GM/r^2=omega^2*r:
omega^2=GM/r^3.
Now, the rate of change, to a first approximation:
For a circular orbit, da/dr=omega^2.
And for gravity, it is -2GM/r^3
So, if you are a little bit closer (dr), the acceleration required for a circular orbit drops by omega^2*dr.
The acceleration due to gravity increases by 2GMdr/r^3
So this means gravity wins and you would feel a slight acceleration towards Earth.
But what would this be?
Well, the increase in force, minus the difference in force required to maintain the orbit is:
2GMdr/r^3+omega^2*dr, and as omega^2=GM/r^3, this becomes:
GM/r^3*(2dr+dr)=3GMdr/r^3.
So lets say you are 100 m from the centre of a craft orbiting at 6800 km (6800000 m), what would the acceleration you perceive be?
well, taking G and M as their accepted values you get 3.8E-4.
To give you an idea, that is roughly 0.0039% that of gravity on the surface of Earth.
That means your "weight" in that circumstance would be roughly 0.0039% that of what it would be on the surface of Earth, or roughly one 25 000th.
Far too small for people to notice.
Every other aspect of the equivalence principle fits perfectly fine into my model and you have failed to show where a conflict may arise.
No. I explained quite clearly the problem.
The equivalence principle allows you to consider the situation as Earth orbiting the satellite or the satellite orbiting Earth.
Similar to how you either have the person falling to the floor of the elevator or the elevator rising to the person.
So if you change it so the satellite is stationary or moving in a straight line, then you need to have Earth orbiting the satellite.
It doesn't matter if you got the rest right. Having this fundamental aspect wrong destroys the whole argument.
Yes, this theory does not require the South to be around the disk, as saying something is 'around' the disk is somewhat nonsensical. The only tenant one has to hold to be a flat earther is that the earth is flat.
And flat in non-flat geometry is not what most people think of when they hear flat.
I disagree. Given our knowledge of philosophy of science, the flat earth - a revolutionary idea at odds with both theory and empirical data - is the correct methodological move as it presses a paradigm shift. It happened similarly during our last resurgence that also happened to lead to the relativistic revolution.
It isn't a revolutionary idea. It is an ancient, discredited idea. Yes, it is an idea at odds with all data.
The same was not true for relativity.
It being at odds with all data indicates it is wrong.
What lead to the "relativistic revolution" was that the data didn't match the current theory of relativity.
We had the speed of light (in a vacuum) being constant for all observers, and we had relative speeds add up such that if A, travelling at speed u relative to C, throws object B at speed v relative to themselves, then object B will travel at speed V=u+v, relative to C.
These produced a contradiction, as if you sub in light, with speed c, then v and V are both c, such that you have c=u+c, which only works for stationary objects.
Relativity wasn't something that completely didn't match the data. Instead it solved this problem to make the data match.
It needed a formula where V=u+v for low speeds, and V=v for high speeds, and u and v should be free to be swapped.
The one that works is V=(u+v)/(1+uv/c^2), which for simplicity later =c^2*(u+v)/(c^2+uv) (if you like I can do the math for this as well).
This lead to a revolution because it matched both theory (relativity for low speeds and the speed of light being constant), and the empirical data of relative speeds and the speed of light.
When u<<c and v<<c, then uv/c^2<<1, thus (1+uv/c^2)~1 (the difference is so small it isn't funny, for example, if they are both 100 m/s, then you have (200 m/s)/(1+10000/299792458^2)=199.99999999997774699887893010734 m/s so the difference is ~-2E-11. That would be 20 pico meters over 200 m, or to travel those 200 m, it would take a time of 1.0000000000001112650056053618432 s, or 1E-13 seconds more than expected.)
When v=c (or u=c and you switch u and v), you get V=c^2(u+c)/(c^2+u*c)=c^2(u+c)/(c*(c+u))=c(u+c)/(c+u)=c.
The same is true for the quantum revolution.
We had what was known as the ultraviolet catastrophe, where the classical models were not able to predict black body radiation curves and instead predicted far more UV.
There was the issue of light behaving as a wave in numerous experiments, and the issue of it behaving as a particle in some.
This was solved by quantum mechanics, a theory which could explain this behaviour.
It led to a revolution because it matched the empirical data and harmonised the theories.
You don't start a scientific revolution by going against all the data.
Yes, I am always happy to talk about different models and conjectures we might have. Anything else would be intellectually dishonest. I am also happy to loudly proclaim we are ignorant on which is correct - but we are certain the Earth is Not A Globe. You might have noticed how many books written over the years have held this moniker, and they have done so for a very good reason. I can't say which is correct. I can certainly point out which ones are incorrect though. This however does not disclude them from conversion, as they still have their worth both to me and others.
They have that to sell or for self-promotion.
One thing I am certain of is that you are wrong, and that Earth is round and spinning.
Yes, you guys show conviction that Earth is not round, but you do not know that it isn't, as you have nothing to back up that nonsense claims.
I can point out which flat Earth models are incorrect, all of them that I have seen.
And I wish you would stop claiming that "Einstein's Relativity proves earth flat"! Einstein's Relativity certainly does not prove the earth flat.
Your imaginary "Leo Ferrari effect" might, but that is not "Einstein's Relativity".
We've discussed this before. To me, the subject matter experts I've talked to agree. I agree, after careful study. You have yet to raise a serious concern that shows this is not the case. I have stopped saying as much, but I doubt I'll ever go back and rename the article. Simply accept that sometimes articles on the internet are ill named.
I have pointed out why it isn't the case, with a very serious concern which you only dismissed.
Yes, lots of articles on the internet are named with (and contain) pure bullshit. That's only a reason if you are happy being as shit as everyone else.
The infamous Eratosthenes experiment does nothing to confirm the shape of the earth, as it assumes the earth is round. It might help us find the circumference of said imaginary globe if one were to exist. It has been repeated time and time again, so much so that we made a poster about it. There are obviously several other models that must exist that can explain this. The standard flat earth model derives its suns path as well as its movements throughout the year using this experiment. Rowbotham additionally goes into greater detail in Earth: Not A Globe.
Yes. It assumes Earth is round and the sun is far enough away that its rays are effectively coming in parallel.
However it can (with multiple points) be used to show that Earth cannot be flat, at least not in flat geometry.
No. There are not necessarily (or obviously) several other models that must exist that can explain it.
The standard model uses just sets of 2 points (or just 1), and only 1 set at a time. That is because if it uses any more, it shows it to be completely wrong. Depending upon which points you use and when, you get completely different numbers/locations.
The "standard model" uses 45 degrees north (or south) and the equator at the equinox at midday (astronomically speaking) to show that the sun is 5000 km high. It then uses the tropics at their respective solstice to show it is overhead then. It also uses several points along these lines to show that it moves in a circle above them, but only considering one longitude at a time.
If you use the north pole and the equator at the equinox, you still find the sun over the equator, but closer to a height of 0.
If you use 45 degrees north and the north pole, you get it just south of 45 degrees north.
If instead you use several points on the equator at the equinox to map the motion of the sun during the day, you find it travels in a straight line East-West, rather than following the curve of Earth. It rises due east, not north east as the model would indicate.
This indicates the equator must be a circle with the sun outside and in the same plane (and the ground "below" inside and in the same plane) as this circle, not "above" (or "below") it in a different plane.
In the southern hemisphere during summer it gets even more screwy for the standard model, with the sun rising from the south east, when it is only ever north of that position.
If you use multiple places on the equinox (excluding the very point of the pole where it will just be due south or due north as that is the only direction available), you find the sun rising effectively due east (while being directly overhead somewhere on the equator). This means the sun is so far away it isn't funny, and the only way for you to see it rising from that far away while directly overhead somewhere else is if Earth is round.
It is only by dishonestly using that experiment, picking points and times to give you what you want, that one can track the sun to produce the standard model.