Can you substantiate your claim that your UA...can magically make the light from the sun bend in such a way as to produce an apparent negative angle of elevation? Note: This requires a justification of the magnitude of the effect.
Don’t forget the left/right bending effect as well. To illustrate what I mean by that, I calculated the actual position of FE’s “nearby sun above the flat earth” from the viewpoint of an observer located at 45° North latitude on the day of the September Solstice. I did this using simple trigonometry, as illustrated below, calculating the distance and compass direction to the sub-solar point on the earth's surface, and then the elevation angle up to the sun knowing the distance and height. I did this ignoring any atmospheric or perspective effects, which matches how Rowbotham and other FE calculate the sun's height. (Notice in the wiki, for example, that during the section on
calculating the height of the sun, no allowance is made for the sun
appearing to be at 45° elevation angle while
actually being somewhere else. No, it is assumed to
actually be where it
appears to be, at 45° elevation) I did ten minute increments all night and day, midnight to midnight.
I then pulled information from the
US Naval Observatory web site listing the projected direction and elevation angles for the same geographic location and also in ten minute increments. I then calculated the difference between the USNO numbers and my calculation, and graphed the result. This number is the magnitude of the FE proposed perspective and atmospheric effects. It is how much the sun’s apparent position deviates from the FE sun’s supposed actual position. The X axis on the graph is the difference between the compass direction the sun is observed to be, and the direction it is supposed to be at that time of day. The Y axis the difference in how high above the horizon the sun should be, absent the proposed perspective and atmospheric effects. This curve is slightly asymmetrical due to my local apparent solar noon not lining up exactly with clock noon, so the USNO numbers are coming in slightly ahead of my calculated numbers.
