When i said that i used arrows ON THE DESKTOP as my reference frame, what i really meant to say is this : you can consider this arrows as they are drawn on the lens of my camera, and that is exactly what you see in this video (and on the photographs (above) which are taken out of that ZIGZAG video demonstration) : an arrows are STRICTLY in the line of sight of the lens of the camera, so that an arrow which points to the left can almost perfectly represent the left eye of the viewer (who watch this ZIGZAG video demonstration) and an arrow which points to the right can almost perfectly represent the right eye of the observer (who watch this ZIGZAG video demonstration)!
So you are using an arbitrary reference frame based upon a moving camera?
Guess what, with that you can show anything.
You could leave the camera facing the centre of the rod, akin to someone standing on Earth facing north.
Then as the rod turns clockwise, from above, (in this case, to the left, but again, it is quite poor to use left or right to explain rotation), the sun appears to move to the left, circling counterclockwise around the person.
This roughly matches what would be observed regardless (i.e. if Earth was flat with the sun circling above the tropic or if it was round rotating around its axis with the sun relatively stationary).
You could do what the video makes a horrible attempt at doing, and instead of keeping the camera fixed w.r.t. the wooden rod, keep it pointing parallel to a line connecting the rod and the light (indicating the sun).
In this case it does show a "zig-zag" movement, as I already explained. It would be a mere 9 seconds of arc. So basically nothing.
On the typical flat earth, you would also expect this zig-zag movement, but instead of being a tiny 9 seconds of arc, it would be over 19 degrees.
So again, this would show the flat Earth model is wrong.
And then you could do more dishonest crap, like turning the camera however you feel like to make it do whatever you wanted.
You could turn it clockwise, making the sun look like it goes even further left than if you kept it aligned with the rod.
You could turn it in a more complex way to exaggerate the zig-zag.
How about you try telling us what this would correspond to in reality (or if you like, the pseudo heliocentric model).
Would it be a person standing and turning around?
Given all that i've just said, an arrows on the lens of my camera PERFECTLY represent the reference frame of the observer who is in demonstrated ZIGZAG situation!!!
Again, what is this reference frame that is meant to be represented? And no, it isn't perfect as the camera is being moved by hand in a horribly imprecise way.
So, you again prove an indisputable fact : you are a jack of stupidity!!!
No. Once again I have proven I am intelligent enough to see through your bullshit and you have shown that you are unable to answer simple questions and present your case honestly and rationally.
P.S. Very interestingly, you haven't even try to decline the justification of my accusation regarding my conviction according which Jack Black and Alpha2Omega are the same person... 
I must have missed that.
I have no idea who that person is.
They are not me.
How about you try and deal with the argument rather than trying to find ways to avoid it?
Read and learn you stupid asshole :
How about you try to read what we say and understand what we say rather than continually spout the same bullshit?
1. Heliocentric model = you are on a merry go round = you are OUT OF A CIRCLE = THERE IS A PARALLAX = THERE IS A ZIGZAG PHENOMENA
2. Geocentric model = the sun circles AROUND you = you are WITHIN A CIRCLE = THERE IS NO PARALLAX = NO ZIGZAG
No. The only way to remove parallax is if the sun circles you. Not the earth you are on, but you (or the exact point on Earth you are on).
Also, due to how reference frames work, the 2 are equivalent.
It doesn't matter if you are circling a point (e.g. circling the north pole) with an object far away remaining stationary, or you are remaining stationary with an object circling you.
There is absolutely no difference in the math and the parallax produced.
It is the same if Earth is stationary with the sun orbiting it at 150 000 000 km, or if Earth is 150 000 000 km away from the sun, and Earth is rotating.
They produce the exact same parallax.
It doesn't matter if Earth was a flat stationary disc with the sun circling above the tropic or if the sun was stationary and Earth was spinning below it. The math is the same.
The further away the sun is, the less the parallax. The closer it is, the greater the parallax.
The further you are from the centre of that rotation (so either the centre of rotation of Earth, or the centre of the suns orbit around Earth), the greater the parallax.
This means in a heliocentric model, with the sun 150 000 000 km away, we would expect a tiny parallax (less than 9 seconds of arc at the equator).
This means on a geocentric model with the sun circling above the tropic, we would expect a massive parallax (19 degrees for 90 degree offset, e.g. rather than the sun being due-east it is ENE.
YOU ARE FOLLOWING THE SUN CONTINUOUSLY BY TURNING AROUND YOURSELF 360 DEGREES PER 24 HOURS.
Are you following the sun, or remaining parallel to the line connecting the sun and Earth?
If the former, you expect no parallax as you are continually looking at the sun.
If the later, then ignoring axial tilt, you expect a parallax of 9 arc seconds, virtually nothing.
Do the same on a flat Earth, you expect a parallax (in the second case) of over 19 degrees.
WHAT DOES IT MEAN? IT MEANS THAT YOU WOULDN'T CHANGE YOUR POSITION WITH RESPECT TO THE STATIONARY SUN, YOU WOULD ONLY CHANGE YOUR POSITION WITH RESPECT TO THE SPINNING-EARTH-BALL-ENVIRONMENT, AND THE RESULT WOULD BE A ZIGZAG PHENOMENA (THE SUN WOULD APPARENTLY GO TO THE RIGHT FIRST HALF OF THE ARCTIC SUMMER DAY, AND THEN WOULD APPARENTLY GO TO THE LEFT SECOND HALF OF THE ARCTIC SUMMER DAY) WHICH DOESN'T EXIST IN OUR REALITY.
Again, if you kept it the same w.r.t. the sun, it wouldn't change.
If you countered the rotation of Earth, then you would expect an un-noticeable 9 seconds of arc.
In the flat Earth model, the first case remains the same, the second case produces over 19 degrees of parallax.
So again, this zig-zag BS refutes a flat Earth.
IN THIS SCENARIO YOU ARE WATCHING STRICTLY TOWARDS THE NORTH (NOT TOWARDS THE SUN). WHAT HAPPENS NOW? WHAT HAPPENS NOW IS AN OPPOSITE SCENARIO THAN IN THE FIRST CASE:
No. It isn't really opposite, it is completely different.
If you stand facing the north pole, then the sun appears to circle you.
It is quite dishonest to describe that as a left to right and right to left movement.
And guess what? The same (ignoring the parallax) happens on a flat Earth model.
YOU DON'T MOVE AT ALL, BUT NOW THE SUN GOES FROM YOUR RIGHT HAND TO YOUR LEFT HAND (FOR THE FIRST HALF OF THE ARCTIC SUMMER DAY), AND FROM YOUR RIGHT HAND TO YOUR LEFT HAND AGAIN (FOR THE SECOND HALF OF THE ARCTIC SUMMER DAY).
How did it magically get back to your left hand?
I assume one of them was meant to be the other way?
Again, in either model, what would typically be considered the day, the sun would be behind you moving right to left. Then it goes in-front of you and moves left to right.
This is what is observed.
YOU SEE, NOW THE SUN MAKES KIND OF A ZIGZAG WITH RESPECT TO YOU AS AN OBSERVER, BUT THE HUGE DIFFERENCE IS THIS : IN THIS SCENARIO YOU CAN'T SEE THE SUN FOR ALMOST 12 HOURS (ONE HALF OF IT'S FULL CIRCUIT AROUND YOU).
No. It makes a circle around you. There isn't a zigzag.
If it was a zig zag, it would be in front of you the whole time, moving back and forth.
You even admit, it is a circuit, i.e. not a zigzag.
ON THE OTHER HAND IF THE EARTH WAS A SPINNING BALL YOU WOULDN'T BE ABLE TO SEE THE SUN FOR ABOUT 12 HOURS, ALSO, BUT IN THIS (HELIOCENTRIC MODEL) THE SUN WOULDN'T MAKE ANY KIND OF A ZIGZAG WITH RESPECT TO YOU AS AN OBSERVER ON A SPINNING BALL, IN THIS CASE THE SUN WOULD CONSTANTLY-APPARENTLY MOVE FROM YOUR RIGHT HAND TO YOUR LEFT HAND FOR THE FULL 24 HOURS.
How would it do that?
How would it then magically get back to your right hand to be able to rise again for the next day?
Like I said, in either model, the sun would appear to circle you (ignoring parallax).
It would start out to your right, go behind you, to the south, then to the west, before coming into view and going in front you to the north and then back to the east.
You would expect it to circle you, just like it does in reality.
Do I need to draw pictures for you again so you can understand?
Or do you think you could do it with your rod? Put the camera so it stays facing the centre, and see what the light does.