We get repeatedly told that the sun is a ball about 50 km (or 31 miles) in diameter and about 5,000 km (or 3,100 miles) above the surface of the earth.
This makes the angular size of the sun about 0.57° when viewed from directly underneath and this is about the size we observe.
When the sun is not directly overhead, however, it must be at a greater distance from the observer as in this diagram.
Sun Angular Size on Flat EarthFor any given sun elevation angle (
"Elev" on the diagram),
the distance from the observer to the sun can be calculated from Sun distance = (Sun height)/sin(Sun's Elevation).
We know the height (on the Flat Earth model) is always 5,000 km, so we can easily calculate the sun's angular size from any location.
Now there are plenty of websites that give us data about the sunrise, sunset and sun's position in the sky at any location and any time.
Since the actual size of the sun must remain constant, as the distance changes the angular size (the apparent size to us) must change, and can be calculated as
angular size = (sun size/sun distance,
this will give a result radians which can be converted to our usual degrees by dividing by 57.3.
Now on Youtube there is a video made by a
the Flat Earther, Matrix Decode with very good photos of the sun through a filter (an arc welder's glass) showing the sun at a number of times of day from 9:30 AM to 7:00 PM on 9/March/2016 in Malaga, Spain.
The following screen shots from his video does an excellent job of proving that the sun size does not change!
Do I need to say more? Our kind Flat Earther,
Matrix Decode, has said it all!
The "sun does not appear to change it size until just before sunset" - a then only a little in height!
In the following table, I have given the angular size of the sun based on the information I could get on the camera used. The actual size is not very important, though, it is the constancy that matters here.
Then to compare with the Flat Earth model I have given the elevation angle for each time, from which the distance to the sun is calculated. Most of these distances look "preposterous", maybe some Flat Earther can explain them!
Then from these distances, I have calculated the angular size the sun should appear on the Flat Earth. The Wiki explains this away as
Magnification of the Sun at Sunset
Q. If the sun is disappearing to perspective, shouldn't it get smaller as it recedes?
A. The sun remains the same size as it recedes into the distance due to a known magnification effect caused by the intense rays of light passing through the strata of the atmosphere.
But these photos were taken
through a filter to remove the glare, and most are quite sharp. In any case for "magnification effect caused by the intense rays of light passing through the strata of the atmosphere" to keep the size so close if very hard to accept.
Time | | Ang Size | | Elev | | FE distance | | FE ang size |
09:30 | | 0.57° | | 21.1° | | 13,864 km | | 0.21° |
10:00 | | 0.57° | | 26.6° | | 11,178 km | | 0.26° |
11:00 | | 0.56° | | 36.4° | | 8,420 km | | 0.34° |
12:00 | | 0.56° | | 44.2° | | 7,174 km | | 0.40° |
13:00 | | 0.57° | | 48.5° | | 6,672 km | | 0.43° |
14:00 | | 0.57° | | 48.4° | | 6,685 km | | 0.43° |
15:00 | | 0.57° | | 43.8° | | 7,221 km | | 0.40° |
17:00 | | 0.57° | | 26.0° | | 11,414 km | | 0.25° |
18:00 | | 0.57° | | 14.9° | | 19,484 km | | 0.15° |
19:00 | | 0.57° | | 3.1° | | 91,281 km | | 0.03° |
Now, I don't know what you are going to about the "ridiculous" distances of 19,484 km and especially 91,281 km, but if the sun is at the given elevation and 5,000 km above the earth, that's where is has to be - you work it out!
On the Flat Earth with the sun at around 5,000 km altitude, the distance to the sun varies a huge amount from when it is overhead to when it sets, so the angular size (our apparent size) must change by a large amount.
If I have made some logical or arithmetic mistakes, I would be glad to hear it.