Den Pressure - A Definable Hypothesis & Experiments (Scepti, iWitness)

Quote from: Aliveandkicking on September 13, 2016, 09:40:22 AM

Quote from: sceptimatic on September 13, 2016, 09:33:02 AM

Quote from: Aliveandkicking on September 13, 2016, 09:29:17 AM

It is a somewhat irrelevant point.  What is relevant is you have claimed there is something difficult about creating low pressure in large containers and there is absolutely nothing in your model to cause that.

What do you mean by this?

Quote from: Aliveandkicking on September 13, 2016, 09:29:17 AM

What do you mean by 'more atmospheric pressure'?     It should be simple to use different words to describe what you mean by that expression.

What do you mean by this?

I can hardly be bothered to reply to you in the first place and i have no intention of being your victim again.

That's good because you had little to say in the first place. Backward is the word I'd use for you. Utterly backward and unable to understand what's been said even when told many many times.
You just carry on being backward.

Denpressure does that to people.   You will be on your own with it till you give up or die.

I did my best and failed.  So be it.

Scepti how did the arc light at the center of the earth form?

Does the crystal on top move?

Scepti how did the arc light at the center of the earth form?

Does the crystal on top move?

You can't even get a grip on denpressure so I'm hardly going to explain any further to people like you who have absolutely no intention of understanding anything of it, except to simply try and ridicule anything that is said.

I'm only interested in those that are genuine or at least have a mind to want to understand.
You people merely rant and scream stuff like, "wahhhhh your theory is crap because we can't grasp it."

Bollocks.

Quote from: SpJunk on September 12, 2016, 08:32:21 PM

Quote from: sceptimatic on August 25, 2016, 03:52:31 PM

...
 but different masses will all fall at different rates of speed.
...

LOL

Take one clay ball of 100 grams.
Drop it from wherever you want.

Take two clay balls of 100 grams each.
Drop them from same point.
Same speed of fall.

Take three clay balls of 100 grams each.
Again, same speed of fall.

Join two clay balls into one.
Will they fall at the same speed as two separate balls?
Ofcourse.
There wasn't difference in fall speed when they were separated,
so it won't be if you join them. There is no difference in acceleration and speed.

Drop one clay ball of 100 grams, and two joined balls of 2 x 100 grams as one.
Will they fall at same speed, or ball of 200 grams will fall faster?

Remember, 2 x 100 grams fall the same speed whether you join them or not.
So, 3 x 100 grams will also fall at the same speed.
Join them or not, it will change nothing.

Now, take one ball of 100 grams and divide it into two of 50 grams.
Or into 5 of 20 grams.
Or into 100 of 1 gram.

Each of those grams will fall at the same speed, joined with others or not.

Same goes for milligrams, and so on...

wrong, it would change. It just won't change to your eye perception at close range.

For change it requires air drag, and in case of 100, 200 and 300 gram clay balls the change is too small.

In that big vacuum chamber won't change. You saw ball and feathers falling at the same speed, when high level of vacuum was achieved.

Quote from: sceptimatic on September 13, 2016, 02:13:20 AM

Quote from: SpJunk on September 12, 2016, 08:32:21 PM

Quote from: sceptimatic on August 25, 2016, 03:52:31 PM

...
 but different masses will all fall at different rates of speed.
...

LOL

Take one clay ball of 100 grams.
Drop it from wherever you want.

Take two clay balls of 100 grams each.
Drop them from same point.
Same speed of fall.

Take three clay balls of 100 grams each.
Again, same speed of fall.

Join two clay balls into one.
Will they fall at the same speed as two separate balls?
Ofcourse.
There wasn't difference in fall speed when they were separated,
so it won't be if you join them. There is no difference in acceleration and speed.

Drop one clay ball of 100 grams, and two joined balls of 2 x 100 grams as one.
Will they fall at same speed, or ball of 200 grams will fall faster?

Remember, 2 x 100 grams fall the same speed whether you join them or not.
So, 3 x 100 grams will also fall at the same speed.
Join them or not, it will change nothing.

Now, take one ball of 100 grams and divide it into two of 50 grams.
Or into 5 of 20 grams.
Or into 100 of 1 gram.

Each of those grams will fall at the same speed, joined with others or not.

Same goes for milligrams, and so on...

wrong, it would change. It just won't change to your eye perception at close range.

For change it requires air drag, and in case of 100, 200 and 300 gram clay balls the change is too small.

In that big vacuum chamber won't change. You saw ball and feathers falling at the same speed, when high level of vacuum was achieved.

Yes the change would be extremely small in a low pressure chamber but as far as the large so called vacuum chamber is concerned, it's nothing more than a big con job and should easily be seen as such by any genuine normal person who takes the time to question this stuff.
Naturally people like you won't see anything wrong in anything, because that's not your purpose.

Yes the change would be extremely small in a low pressure chamber but as far as the large so called vacuum chamber is concerned, it's nothing more than a big con job and should easily be seen as such by any genuine normal person who takes the time to question this stuff.
Naturally people like you won't see anything wrong in anything, because that's not your purpose.

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

Quote from: sceptimatic on September 14, 2016, 01:16:56 AM

Yes the change would be extremely small in a low pressure chamber but as far as the large so called vacuum chamber is concerned, it's nothing more than a big con job and should easily be seen as such by any genuine normal person who takes the time to question this stuff.
Naturally people like you won't see anything wrong in anything, because that's not your purpose.

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

What are you babbling on about?

Quote from: SpJunk on September 14, 2016, 01:31:48 AM

Quote from: sceptimatic on September 14, 2016, 01:16:56 AM

Yes the change would be extremely small in a low pressure chamber but as far as the large so called vacuum chamber is concerned, it's nothing more than a big con job and should easily be seen as such by any genuine normal person who takes the time to question this stuff.
Naturally people like you won't see anything wrong in anything, because that's not your purpose.

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

What are you babbling on about?

Yes, i guess the whole idea of "Archimedes Principle" would seem like babbling to you.

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

1. Weight does change with atmospheric pressure, but also     

2. Weight changes with distance from the Earth.   An absolute gravity measurement using laser interferometery, measuring the speed of a falling object in an almost perfect vacuum , can detect 1mm change in height.

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

Well why not?

A one kilogram Gold bar would be about three quarters of a cent cheaper during extreme highs.   

 

Quote from: sceptimatic on September 14, 2016, 08:53:01 AM

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

Well why not?

A one kilogram Gold bar would be about three quarters of a cent cheaper during extreme highs.   

 

It doesn't really matter what price change there  is, just that there would be one in some weather change, day by day.

It's like having a brick in water then taking it out one day and weighing it. Then the same brick weighed again after being left in a dry place for a day. You will see change.
If any of you had any basic sense you'd start to understand how and why denpressure works like this on any dense object by seeing changes in porousity.

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

My scales are not weather dependent. Now run back to your fantasy world.

Quote from: sceptimatic on September 14, 2016, 08:53:01 AM

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

My scales are not weather dependent. Now run back to your fantasy world.

Unlike you who's always under it. You sad git. 

Quote from: sokarul on September 14, 2016, 09:04:24 AM

Quote from: sceptimatic on September 14, 2016, 08:53:01 AM

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

My scales are not weather dependent. Now run back to your fantasy world.

Unlike you who's always under it. You sad git. 

What is the relationship between weight and atmospheric pressure, a formula please.

Quote from: sokarul on September 14, 2016, 09:04:24 AM

Quote from: sceptimatic on September 14, 2016, 08:53:01 AM

Quote from: markjo on September 14, 2016, 08:22:19 AM

Quote from: sceptimatic on September 14, 2016, 07:49:51 AM

Quote from: markjo on September 14, 2016, 06:22:39 AM

The question of weight changing with atmospheric pressure changes at various altitudes has been raised many times, but has anyone considered how weight might change due to atmospheric pressure changes due to weather?  It seems that the weight of a given object should change depending on whether it's a nice sunny day (generally associated with higher atmospheric pressure) or storming (generally associated with lower atmospheric pressure).  After all, we see these changes in a column of mercury in a barometer, so why don't we see it elsewhere?

We do see it everywhere.

So you're saying that precious metals dealers need to take the weather into account when buying or selling gold?

Absolutely.

My scales are not weather dependent. Now run back to your fantasy world.

Unlike you who's always under it. You sad git. 

Use any of your pretend millions to preform an experiment yet?

It doesn't really matter what price change there  is, just that there would be one in some weather change, day by day.

It's like having a brick in water then taking it out one day and weighing it. Then the same brick weighed again after being left in a dry place for a day. You will see change.
If any of you had any basic sense you'd start to understand how and why denpressure works like this on any dense object by seeing changes in porousity.

Umm...  That isn't quite what I'm talking about.  I'm talking about atmospheric pressure changing with the passing of high and low pressure systems.  It isn't unusual to have fairly significant changes in atmospheric pressure as various weather systems pass through during the course of the day.  It seems that the weight of the brick should change as the day goes from cool, dense air in the morning to warm and less dense air in the afternoon and back to cool and dense overnight.  Why does no one ever notice those changes in weight?

Quote from: TheRealBillNye on September 13, 2016, 03:53:13 PM

Scepti how did the arc light at the center of the earth form?

Does the crystal on top move?

You can't even get a grip on denpressure so I'm hardly going to explain any further to people like you who have absolutely no intention of understanding anything of it, except to simply try and ridicule anything that is said.

I'm only interested in those that are genuine or at least have a mind to want to understand.
You people merely rant and scream stuff like, "wahhhhh your theory is crap because we can't grasp it."

Bollocks.

You're right. I don't understand denpressure (not because of a lack of effort, however). A major issue with how this model is supposed to work is the sun, moon and stars. Your explanation for these observations is not in line with reality. I suggest you obtain a telescope and examine the heavens for yourself and see if your theory stands up to scrutiny.

My biggest issue with your theory, however, is your refusal to answer simple questions. You just shut your ears and scream "LA LA LA YOU CANNOT GRASP MY GENIUS LA LA LA"

What is the relationship between weight and air pressure in Denpressure?

How much less or more does a person weigh on Everest where atmospheric pressure is less than third of the sea level pressure?

Are we heavier or lighter up there??

Quote from: SpJunk on September 14, 2016, 01:31:48 AM

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

What are you babbling on about?

I'm talking about homework I gave you at page 25 of this thread:

"1. Learn how adhesion works on water drops on wet window.

2. Learn Archimedes principle. How it works and why.

3. Find the weight of the air at 70 degrees fahrenheit at sea level
displaced by iron cube of 1200 cubic inches,
and how much that air reduces the weight of the cube.

4. Repeat for displacement of sea water by the same cube. Compare with (3)."

You didn't search and learn anything about it?

And you talk about "learning your model".
What have YOU learned?

Quote from: sceptimatic on September 14, 2016, 09:01:57 AM

It doesn't really matter what price change there  is, just that there would be one in some weather change, day by day.

It's like having a brick in water then taking it out one day and weighing it. Then the same brick weighed again after being left in a dry place for a day. You will see change.
If any of you had any basic sense you'd start to understand how and why denpressure works like this on any dense object by seeing changes in porousity.

Umm...  That isn't quite what I'm talking about.  I'm talking about atmospheric pressure changing with the passing of high and low pressure systems.  It isn't unusual to have fairly significant changes in atmospheric pressure as various weather systems pass through during the course of the day.  It seems that the weight of the brick should change as the day goes from cool, dense air in the morning to warm and less dense air in the afternoon and back to cool and dense overnight.  Why does no one ever notice those changes in weight?

Because people wouldn't be of the mind to bother. Why don't you try it over a week or so and see for yourself.
Having said that, it should be fairly obvious to genuine people.

Quote from: sceptimatic on September 14, 2016, 12:12:52 AM

Quote from: TheRealBillNye on September 13, 2016, 03:53:13 PM

Scepti how did the arc light at the center of the earth form?

Does the crystal on top move?

You can't even get a grip on denpressure so I'm hardly going to explain any further to people like you who have absolutely no intention of understanding anything of it, except to simply try and ridicule anything that is said.

I'm only interested in those that are genuine or at least have a mind to want to understand.
You people merely rant and scream stuff like, "wahhhhh your theory is crap because we can't grasp it."

Bollocks.

You're right. I don't understand denpressure (not because of a lack of effort, however). A major issue with how this model is supposed to work is the sun, moon and stars. Your explanation for these observations is not in line with reality. I suggest you obtain a telescope and examine the heavens for yourself and see if your theory stands up to scrutiny.

My biggest issue with your theory, however, is your refusal to answer simple questions. You just shut your ears and scream "LA LA LA YOU CANNOT GRASP MY GENIUS LA LA LA"

Then don't worry yourself about it.

What is the relationship between weight and air pressure in Denpressure?

How much less or more does a person weigh on Everest where atmospheric pressure is less than third of the sea level pressure?

Are we heavier or lighter up there??

Take some scales up and find out.

Quote from: sceptimatic on September 14, 2016, 05:37:19 AM

Quote from: SpJunk on September 14, 2016, 01:31:48 AM

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

What are you babbling on about?

I'm talking about homework I gave you at page 25 of this thread:

"1. Learn how adhesion works on water drops on wet window.

2. Learn Archimedes principle. How it works and why.

3. Find the weight of the air at 70 degrees fahrenheit at sea level
displaced by iron cube of 1200 cubic inches,
and how much that air reduces the weight of the cube.

4. Repeat for displacement of sea water by the same cube. Compare with (3)."

You didn't search and learn anything about it?

And you talk about "learning your model".
What have YOU learned?

You would be best learning my model instead of fighting it. Learn it and grasp it. Nobody says you have to eventually accept it. Simply try to understand it before you keep spouting off about the stuff that's readily available in all books of mainstream science.

Quote from: SpJunk on September 14, 2016, 09:48:38 AM

Quote from: sceptimatic on September 14, 2016, 05:37:19 AM

Quote from: SpJunk on September 14, 2016, 01:31:48 AM

Hahaha.

"People like me" see wrong only where is wrong.
There are exceptions and errors ofcourse.
But we don't forcibly keep ourselves in error to make others think "we are always right".

Have you already calculated by now how much air gets displaced by iron cube of 1200 cubic inches,
and how much that air makes the cube lighter?

And 1200 cubic inches of sea water?

Did you learn Archimedes Principle?

What are you babbling on about?

I'm talking about homework I gave you at page 25 of this thread:

"1. Learn how adhesion works on water drops on wet window.

2. Learn Archimedes principle. How it works and why.

3. Find the weight of the air at 70 degrees fahrenheit at sea level
displaced by iron cube of 1200 cubic inches,
and how much that air reduces the weight of the cube.

4. Repeat for displacement of sea water by the same cube. Compare with (3)."

You didn't search and learn anything about it?

And you talk about "learning your model".
What have YOU learned?

You would be best learning my model instead of fighting it. Learn it and grasp it. Nobody says you have to eventually accept it. Simply try to understand it before you keep spouting off about the stuff that's readily available in all books of mainstream science.

I just do not understand how you can type out a sentence without any mistakes and yet produce something like denpressure

Do you really believe it describes reality or is it a big joke for you??

Quote from: markjo on September 14, 2016, 09:23:20 AM

Quote from: sceptimatic on September 14, 2016, 09:01:57 AM

It doesn't really matter what price change there  is, just that there would be one in some weather change, day by day.

It's like having a brick in water then taking it out one day and weighing it. Then the same brick weighed again after being left in a dry place for a day. You will see change.
If any of you had any basic sense you'd start to understand how and why denpressure works like this on any dense object by seeing changes in porousity.

Umm...  That isn't quite what I'm talking about.  I'm talking about atmospheric pressure changing with the passing of high and low pressure systems.  It isn't unusual to have fairly significant changes in atmospheric pressure as various weather systems pass through during the course of the day.  It seems that the weight of the brick should change as the day goes from cool, dense air in the morning to warm and less dense air in the afternoon and back to cool and dense overnight.  Why does no one ever notice those changes in weight?

Because people wouldn't be of the mind to bother.

Dealers in precious materials would.

Why don't you try it over a week or so and see for yourself.

It isn't my claim that atmospheric pressure is responsible for what we experience as weight, so it isn't my responsibility to do your research for you.

Having said that, it should be fairly obvious to genuine people.

What would you know about genuine people? 

You would be best learning my model instead of fighting it. Learn it and grasp it. Nobody says you have to eventually accept it. Simply try to understand it before you keep spouting off about the stuff that's readily available in all books of mainstream science.

What is there to fight?
You don't even explain atoms consistently.
Your atoms and molecules have no consistent forms and characteristics.

You are trying to create model and force it on people without even basic knowledge?
Would basics kill you?

Learn the very simple thing: Archimedes Principle, then apply it on your model.

Archimedes Principle is old, proven, and used in real life.
Gives real and practically useful results.

One of uses is to calculate ship hulls.