How would spin affect gravity?
Dunno, guess it woodn't!
Actually, the spin only reduces gravity by .03 m/s2.
And explain how you got this answer.
The question really should be why you cannot work this out for yourself! All the information is available on-line.
I guess the thing you might search for might be "Centrifugal force".
Centrifugal force
In Newtonian mechanics, the term centrifugal force is used to refer to an inertial force (also called a 'fictitious' force) directed away from the axis of rotation that appears to act on all objects when viewed in a rotating reference frame.
plus a whole lot more
from
Google centrifugal forceOr you might choose one of the many other sources.
Wherever you get the info
centripetal acceleration (the cause) = (Velocity squared)/radius or v2/R in compatible units, say mks.
Now the earth has an equatorial radius of 6,384 km (Wikipedia again) or 6.384 x 10
6 m and
the earth actually rotates once in a little under 24 hours
[1], or once in 86164 secs.
So on the equator the surface velocity is the (circumference of the earth)/(time for one revolution) or
v = (2 x π x 6.384 x 106/86164 m/s = 465.5 m/s
So our centripetal acceleration acent = 465.52/6.384 x 106 = 0.034 m/s2
[1] This is because in 24 hours the same spot faces the sun again, but in that time the earth has moved 1/365.24 of its orbit around the sun. So the earth rotates 360° in a bit under 24 hours.