Wise is correct in two ways. A change in angle of sunlight alone, should not weaken the amount of solar energy on a solar panel. Also, the sun is actually further away from any particular spot on Earth from a globalist view also, at either sunrise or sunset, compared to midday, by being rotated away from as opposed to being square on.
The ingredient which weakens sunlight from the globalist standpoint, either side of midday, is Earth's atmosphere. Sunlight must pass through more atmosphere, as the angle decreases, which disperses more infra red and visible sunlight rays.
Take away Earth's atmosphere, and angle would make no difference on a solar cell.
You could not be further from the truth.
The angle is by far the most significant factor.
The atmosphere is negligible until sunrise or sunset.
The distance is effectively nothing.
At most the distance changes by ~6400 km from dawn to midday, or 0.00004 times the distance to the sun. That results in change in the power by a factor of roughly 1.00009. Nothing like what is observed.
Likewise, the atmosphere does not significantly absorb or scatter the radiation from the sun.
If it did you could easily look up at it, without any risk of damage to your eyes.
Again, it is simple geometry.
The sun is emitting radiation at a fairly constant rate.
Lets just call it k W/m^2, and consider a solar panel that is 1 m^2.
Now if the panel is perpendicular to the incoming radiation that means it is hit by the full power of k W.
If instead we tilt it to 45 degrees, then it no longer takes up that full 1 m^2. Instead it takes up roughly 0.7 m^2, and thus the power it gets it ~0.7 k W.
Again, a simple diagram represents this:
Notice how the grey line is shorter than the black line?
That means the sun rays coming at an angle give the panel less power.
This is why the location solar panels are installed is important, where you want the optimal angle, and why people make tracking solar panels which track the sun through the day.