The Globe has no such problem.
The average radius is 6371 km and 2 × π × 6371 = 40,030 km.
The distance from the equator to the North Pole is 10,002 km (to the nearest kilometre).
The discrepancy between 4 × 10,002 km (Meridional Circumference), 2 × π × 6371 = 40,030 km (from the average radius) and 40,075 km the Equatorial Circumference is simply because the earth is not a perfect sphere.
But it does have such problems.
This is the correct FE map (Piri Reis map):
It has a radius of 6363.63 km.
For the RE map, you have to DOUBLE the radius: it now becomes 12727.2727 km.
That is, you take the map, DOUBLE its radius and fill in the remaining space with water.
Your map has the following surface area expressed for a circle: π(2r)
2 (=4πr
2) (surface area for a sphere: 4πr
2 = π(2r)
2)
The FE map has this formula: πr
2The RE map has a radius TWICE THE SIZE of the radius of the FE map.
FE radius = 6363.63 km
RE radius = 12727.27 km
Problem #2: how do four trillion billion liters of water stay glued next to the outer surface of a sphere without attractive gravity?
You want to use gravitons?
How do two gravitons attract each other?
Can you explain the attractive mechanism?
Can you explain to your readers how two gravitons attract each other? What is the mechanism of attraction?
You cannot, therefore those trillions of billions of liters of water are glued to an outer surface by pure magic.
Even pure magic cannot explain this horrendous hypothesis.
You claim that terrestrial gravity is attractive, yet you cannot explain the mechanism.
It is even worse than pure magic.
Please explain the physics to your readers.
What you are telling your readers is even worse than Aristotle's Credo Quia Absurdum Est (I believe because it is absurd).
The attractive gravity hypothesis is not even a credible fairy tale, it is even beyond the powers of pure magic to explain how four trillion billion liters of water stay glued next to the outer surface of a sphere.
It is though the exemplification of a fanatical and dogmatic agenda which goes even beyond what organized religion has to offer.
Do you want to use gravitons?
So, how do four trillion billion liters of water stay glued next to the outer surface of a sphere?
Let us examine the graviton problem. There are only two possible choices: either these gravitons were a one-time emission five billion years ago, or they are being emitted continuously by the iron/nickel core. In both cases the graviton must either consist of two kinds of particles, one which has an emissive vortex, the other one which has a receptive vortex, or a single particle with two ends consisting of an emissive vortex, while the other end has a receptive vortex.
In both cases we are dealing immediately with the defiance of the law of conservation of energy: how in the world can these vortices function after five billion years with no loss of energy?
Moreover, you have another huge problem: each object on the surface of the earth must connect to the gravitons emitted by the iron/nickel core through strings of gravitons which fit neatly and totally to each and every graviton released by the object itself. How then can that object move freely on the surface of the sphere? Obviously the strings of gravitons emitted by the iron/nickel core are not intelligent enough to know the random direction of movement of the object. Are you telling your readers that the strings of the object can slide freely from a static string of gravitons emitted by the iron/nickel core, to another with no loss of energy, not to mention the very mechanism itself?
The gases in the atmosphere do not obey any kind of an attractive law of gravity.
The gravitons cannot be used to explain attractive gravity.
Please explain to your readers how attractive gravitation functions. If you cannot, then what you are telling yourself and to your readers is that gravity on a spherical earth is governed by pure magic.
Problem #3: the position of the centre of gravity varies according to the shape of the object.
And, according to the official theory we do have an applied external force:
You MUST have a symmetrically perfect ellipsoid (or geoid) or there will be a clear and direct DEFIANCE of the law of universal gravitation.
Let us carefully calculate the effect/distribution of mass of the continents with respect to both hemispheres (northern and southern).
"The area of land in the northern hemisphere of the earth is to the area of land in the southern hemisphere as three is to one.
The mean weight of the land is two and three-quarter times heavier than that of water; assuming the depth of the seas in both hemispheres to be equal, the northern hemisphere up to sea level is heavier than the southern hemisphere, if judged by sea and land distribution; the earth masses above sea level are additional heavy loads - we include here all the mountains/hills.
But this unequal distribution of masses does not affect the position of the earth, as it does not place the northern hemisphere with its face to the sun. A “dead force” like gravitation could not keep the unequally loaded earth in equilibrium. Also, the seasonal distribution of ice and snow, shifting in a distillation process from one hemisphere to the other, should interfere with the equilibrium of the earth, but fails to do so."
The northern hemisphere has a greater mass than its southern counterpart.
The unequally loaded perfect oblate spheroid (first four layers) DEFIES the law of attractive gravity.
It should rotate with the northern hemisphere facing the sun.
At present, the RE has an unequal distribution of mass: the northern hemisphere has more mass than the southern hemisphere.
For the Pangeea continent the situation is much worse: such a concentration of land mass in just one place would have meant an EVEN GREATER unequal load upon the inner layers of the Earth.
BASIC NEWTONIAN PHYSICS: we have a center of gravity which is located ABOVE THE EQUATOR, given the fact that the northern hemisphere has more mass than the southern hemisphere. Then, the accepted law of universal gravitation tells us that the Earth should revolve facing the Sun with its North Pole.
Now, that is one HUGE problem for your map!