If you want to I can give you a step-by-step explanation of how I got this equation.

Well, that's exactly what I DID ask for, Lying Liar.

& you refused to answer; Lie much, Liar?

But I'm not interested in your Lying answers any more, Liar.

Because I'm sick of being Lied to by Liars.

So stick your Lies in the same dark hole you keep your Telescope, Liar.

Instead, we shall reconvene on my rocketry thread, to discuss this & various other lulzy space-Lies.

& you shall all follow me there, shan't you, Liars?

Why?

Because it is your Job to do so...

LOL!!!

Nope, you asked me to define the different terms:

I got a bit delayed, but here is a mathematical equation that should give you an approximation of the height H of the ISS based on time t it takes for the ISS to travel 20° through your field of vision.

H=t[pi]8000/(1904.3-t[pi])

So; 'H' is height.

Now define the rest of the terms in your lying equation,, lying scumbag.

=Proven liar.

But, I'll still give you the original equation :

D(ISS Orbit)=2H+8000miles

O(ISS Orbit)=[pi](2H+8000)miles

D(Earth)= 8000miles

H(ISS height over earth)=H

t(Time spent in 20° of your field of view straight overhead) (variable) (in seconds)

T(Time for ISS to make one full lap in orbit)=5400s

S(Length ISS travel along 20° of your field of view straight overhead)=2*H*tan(10°)miles (Using trigonometry, since this is only an approxmation and the arc is pretty small)=0.3527Hmiles (roughly)

t/T=S/D(ISS Orbit) -> ts/5400s=0.3527Hmiles/[pi](2H+8000)miles (equability)

t/5400=0.3527H/[pi](2H+8000)

t=0.3527H*5400/[pi](2H+8000)=1904.3H/[pi](2H+8000)

t[pi](2H+8000)=1904.3H

t[pi]2H+t[pi]8000=1904.3H

1904.3H-t[pi]2H=t[pi]8000

H(1904.3-2t[pi])=t[pi]8000

H=t[pi]8000/(1904.3-2t[pi])

Actually, it seems likesomething went wrong when I posted the equation in the earlier post, as it seems to be missing a number 2. I will edit that one quickly. This equation will only give you an approximation, as you can only approximate 20° of your FOV, approximate the time it travels and because it is doesn't take the curvature into account. But it is close enough to calculate if it is in space or not.

EDIT:

Almost forgot:

D=Diameter

H=Height

S=Straight

t/T=Time