Does Anyone Find it Suspect There Is No HD Live Video Of The Entire Globe?

I got a bit delayed, but here is a mathematical equation that should give you an approximation of the height H of the ISS based on time t it takes for the ISS to travel 20° through your field of vision.

H=t[pi]8000/(1904.3-2t[pi])

Quote from: markjo on August 27, 2015, 01:23:42 PM

Of course the ISS is a n.e.o. 

Truth hidden in plain sight...

Are you growing a Conscience, markjo?

I'm confused about the point that you're trying to make.  Are you suggesting that artificial satellites, such as the ISS, aren't objects near the earth?

I got a bit delayed, but here is a mathematical equation that should give you an approximation of the height H of the ISS based on time t it takes for the ISS to travel 20° through your field of vision.

H=t[pi]8000/(1904.3-t[pi])

So; 'H' is height.

Now define the rest of the terms in your lying equation,, lying scumbag.

Quote from: Master_Evar on August 28, 2015, 01:50:46 AM

I got a bit delayed, but here is a mathematical equation that should give you an approximation of the height H of the ISS based on time t it takes for the ISS to travel 20° through your field of vision.

H=t[pi]8000/(1904.3-t[pi])

So; 'H' is height.

Now define the rest of the terms in your lying equation,, lying scumbag.

It's pretty self explanatory, t is time.  He gave a full description of what the equasion does and the input is the time it takes for the ISS to go 20 degrees in your field of vision.

It has to be when the ISS is passing straight overhead, or close to. The amount of seconds for the ISS to travel 20 degrees along your FOV when passing overhead is the variable t. If you want to I can give you a step-by-step explanation of how I got this equation.

If you want to I can give you a step-by-step explanation of how I got this equation.

Well, that's exactly what I DID ask for, Lying Liar.

& you refused to answer; Lie much, Liar?

But I'm not interested in your Lying answers any more, Liar.

Because I'm sick of being Lied to by Liars.

So stick your Lies in the same dark hole you keep your Telescope, Liar.

Instead, we shall reconvene on my rocketry thread, to discuss this & various other lulzy space-Lies.

& you shall all follow me there, shan't you, Liars?

Why?

Because it is your Job to do so...

LOL!!!

Wow. Your posts have literally devolved into 1/2 of it being the word 'lie' or 'shill'

Quote from: Master_Evar on August 28, 2015, 03:04:02 PM

If you want to I can give you a step-by-step explanation of how I got this equation.

Well, that's exactly what I DID ask for, Lying Liar.

& you refused to answer; Lie much, Liar?

But I'm not interested in your Lying answers any more, Liar.

Because I'm sick of being Lied to by Liars.

So stick your Lies in the same dark hole you keep your Telescope, Liar.

Instead, we shall reconvene on my rocketry thread, to discuss this & various other lulzy space-Lies.

& you shall all follow me there, shan't you, Liars?

Why?

Because it is your Job to do so...

LOL!!!

Nope, you asked me to define the different terms:

Quote from: Master_Evar on August 28, 2015, 01:50:46 AM

I got a bit delayed, but here is a mathematical equation that should give you an approximation of the height H of the ISS based on time t it takes for the ISS to travel 20° through your field of vision.

H=t[pi]8000/(1904.3-t[pi])

So; 'H' is height.

Now define the rest of the terms in your lying equation,, lying scumbag.

=Proven liar.

But, I'll still give you the original equation :

D(ISS Orbit)=2H+8000miles

O(ISS Orbit)=[pi](2H+8000)miles

D(Earth)= 8000miles

H(ISS height over earth)=H

t(Time spent in 20° of your field of view straight overhead)  (variable)  (in seconds)

T(Time for ISS to make one full lap in orbit)=5400s

S(Length ISS travel along 20° of your field of view straight overhead)=2*H*tan(10°)miles  (Using trigonometry, since this is only an approxmation and the arc is pretty small)=0.3527Hmiles  (roughly)

t/T=S/D(ISS Orbit) -> ts/5400s=0.3527Hmiles/[pi](2H+8000)miles  (equability)

t/5400=0.3527H/[pi](2H+8000)

t=0.3527H*5400/[pi](2H+8000)=1904.3H/[pi](2H+8000)

t[pi](2H+8000)=1904.3H

t[pi]2H+t[pi]8000=1904.3H

1904.3H-t[pi]2H=t[pi]8000

H(1904.3-2t[pi])=t[pi]8000

H=t[pi]8000/(1904.3-2t[pi])

Actually, it seems likesomething went wrong when I posted the equation in the earlier post, as it seems to be missing a number 2. I will edit that one quickly. This equation will only give you an approximation, as you can only approximate 20° of your FOV, approximate the time it travels and because it is doesn't take the curvature into account. But it is close enough to calculate if it is in space or not.

EDIT:

Almost forgot:

D=Diameter

H=Height

S=Straight

t/T=Time