What we expect to see on a round Earth

Quote from: jroa on August 13, 2015, 04:25:52 PM

Quote from: V on August 13, 2015, 04:10:21 PM

FE'ers, we will continue bumping this thread until you properly answer this question.
If you are too lazy to read the rest of the thread, I will restate the question:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

Lol, that is the opposite of the question.  Are you drunk?  You actually make no sense.

Hello Jroa.  While you are here how about you answer the question: What do you expect to see on a round Earth that we do not see in reality?

I did give you an answer.  You people just chose to shrug it off and then pretend you did not get an answer.  I really do not care to waste much more of my time with answers if you are simply going to plug your ears. 

Quote from: mikeman7918 on August 13, 2015, 04:37:27 PM

Quote from: jroa on August 13, 2015, 04:25:52 PM

Quote from: V on August 13, 2015, 04:10:21 PM

FE'ers, we will continue bumping this thread until you properly answer this question.
If you are too lazy to read the rest of the thread, I will restate the question:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

Lol, that is the opposite of the question.  Are you drunk?  You actually make no sense.

Hello Jroa.  While you are here how about you answer the question: What do you expect to see on a round Earth that we do not see in reality?

I did give you an answer.  You people just chose to shrug it off and then pretend you did not get an answer.  I really do not care to waste much more of my time with answers if you are simply going to plug your ears.

Your supposed answer

If the Earth is flat, you should see no curvature at the horizon.

Your answer was not satisfactory because if you are on a sphere that is very large relative to you then the horizon will also appear flat.  This is not an answer to the question.  This is why you are being asked to answer.  Plus you did not really answer the question that was in the OP quoted below. 

I have a question for the flat earthers: what would you expect to observe on a round Earth that we do not observe in the real world?  Is there anything at all?  Please do tell.

So what do you think you should be able to see if you live on a spherical Earth that you do not see in reality.  Remember we covered "but, duhh, it looks flat from the ground".

Quote from: mikeman7918 on August 13, 2015, 04:37:27 PM

Quote from: jroa on August 13, 2015, 04:25:52 PM

Quote from: V on August 13, 2015, 04:10:21 PM

FE'ers, we will continue bumping this thread until you properly answer this question.
If you are too lazy to read the rest of the thread, I will restate the question:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

Lol, that is the opposite of the question.  Are you drunk?  You actually make no sense.

Hello Jroa.  While you are here how about you answer the question: What do you expect to see on a round Earth that we do not see in reality?

I did give you an answer.  You people just chose to shrug it off and then pretend you did not get an answer.  I really do not care to waste much more of my time with answers if you are simply going to plug your ears.

You did not give us an answer. You answered with what we should see on a flat earth that we apparently see in reality. What is being asked is "what should be seen on a round earth that is not seen in reality?"

Also jroa, I can read between the lines.  I know you just worded it differently.  Yes, you are trying to say that you think you should see a curvature if you lived on a spherical Earth and it looks flat.  I believe this has been addressed numerous times before I did earlier. 

On top of what everyone else said, I linked to a thread where I showed that videos meant to prove flat Earth exhibit curvature, basically debunking flat Earth.

There is a difference between debunking and side stepping Jroa, do you need me to coach you on what that difference is?

Looks like Tappet has been beaten, anyone else want to answer our question?
I will restate it if you are lazy:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

"Tappet has been beaten" give it a rest, you will go blind.
In the hemisphere you call  south, a south pointing compass should be a common tool to buy and we should be able to navigate accordingly. Such a simple thing, yet it does not happen.
Would have made things a tad easier for Amundsen in a white desert.

I think mikeman is expexting this kind of response:
"Hi, I believe the earth is flat. If the earth was round, then we should be able to observe [some phenomenon], but we don't see that, do we? So the earth is flat, not round"
So far not a single response like that? All trolls and no flat earthers in here?

Oh, you mean something like if the earth is round the horizon should not come up to meet the eye.
Yeh tried that, but ball earthers think that the horizon coming up to meet the eye proves you are on a ball.
Pointless exercise!

In the hemisphere you call  south, a south pointing compass should be a common tool to buy and we should be able to navigate accordingly. Such a simple thing, yet it does not happen.

So, a compass then....

In case you didn't know, a compass points North-South with a mark to differentiate North from South......

Oh, you mean something like if the earth is round the horizon should not come up to meet the eye.
Yeh tried that, but ball earthers think that the horizon coming up to meet the eye proves you are on a ball.
Pointless exercise!

Yeah, math shows that the horizon will become indistinguishably close to eye level on a round Earth.

Quote from: tappet on August 14, 2015, 02:22:12 AM

Oh, you mean something like if the earth is round the horizon should not come up to meet the eye.
Yeh tried that, but ball earthers think that the horizon coming up to meet the eye proves you are on a ball.
Pointless exercise!

Yeah, math shows that the horizon will become indistinguishably close to eye level on a round Earth.

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

I will walk you through this high school level math and show you why it has one answer and one answer only.  Here is a diagram representing what I have to calculate:


Here comes the explenation.  If you want to call it wrong you will have to point out where you think my fault is.

We are wanting to know angle a (the amount the horizon drops) and we know distance R (the radios of the Earth which is roughly 4,000 miles).  Let's say that your height (H) is 10 feet above sea level which is 0.0019 miles.

This means that we have a right triangle with the hypotenuse having a length of 4,000.0019 miles and the edge ajacent to the center having a length of 4,000 miles, and we want to know angle a.  This is a classic textbook trigonometry probelem, and it can be easily solved with trig ratios.  In case you slept through this part of your math class, here is a refresher:


The side lengths we know are hyponinuse and ajacent, so this calls for cosine, more specifically inverse cosine because trig ratios are meant to figure out relative side lengths given angles and we are trying to figure out angles given the relative side lengths.  This is the equasion we come up with: cos^-1(4,000/4000.0019).  In your calculator cos^-1 will probobaly look like "acos".  If you plug that in to a calculator you get 0.558 which is the amount the horizon is below eye level in degrees.  Like I said, it's a fraction of a degree.  Before you call trigonometry a lie, keep in mind that it was used to design and build your house and if it were a lie then your house wouldn't be very structurally sound and all the pieces wouldn't fit together right.  Trigonometry is also the basis of all physics simulation as it is very nesesary to to velocity vector calculations in a coordinate based system.

Anyway, review my calculations and let me know if I did something wrong.

Quote from: V on August 13, 2015, 04:10:21 PM

FE'ers, we will continue bumping this thread until you properly answer this question.
If you are too lazy to read the rest of the thread, I will restate the question:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

Lol, that is the opposite of the question.  Are you drunk?  You actually make no sense.

*facepalm*

Jroa, you are unbelievably frustrating...

Quote from: V on August 11, 2015, 11:18:38 AM

Looks like Tappet has been beaten, anyone else want to answer our question?
I will restate it if you are lazy:
Assuming that the earth is flat, what phenomena that are not observed in real life would be observed on a round Earth?

"Tappet has been beaten" give it a rest, you will go blind.
In the hemisphere you call  south, a south pointing compass should be a common tool to buy and we should be able to navigate accordingly. Such a simple thing, yet it does not happen.
Would have made things a tad easier for Amundsen in a white desert.

Compasses are dipoles. You can't have a monopole compass. All compasses point both north and south. You can't have a compass that only points north and you can't have a compass that only points south.

Quote from: mikeman7918 on August 14, 2015, 07:59:06 AM

Quote from: tappet on August 14, 2015, 02:22:12 AM

Oh, you mean something like if the earth is round the horizon should not come up to meet the eye.
Yeh tried that, but ball earthers think that the horizon coming up to meet the eye proves you are on a ball.
Pointless exercise!

Yeah, math shows that the horizon will become indistinguishably close to eye level on a round Earth.

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

Why don't you just ask a real doctor?

Quote from: tappet on August 14, 2015, 01:30:51 PM

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

I will walk you through this high school level math and show you why it has one answer and one answer only.  Here is a diagram representing what I have to calculate:


Here comes the explenation.  If you want to call it wrong you will have to point out where you think my fault is.

We are wanting to know angle a (the amount the horizon drops) and we know distance R (the radios of the Earth which is roughly 4,000 miles).  Let's say that your height (H) is 10 feet above sea level which is 0.0019 miles.

This means that we have a right triangle with the hypotenuse having a length of 4,000.0019 miles and the edge ajacent to the center having a length of 4,000 miles, and we want to know angle a.  This is a classic textbook trigonometry probelem, and it can be easily solved with trig ratios.  In case you slept through this part of your math class, here is a refresher:


The side lengths we know are hyponinuse and ajacent, so this calls for cosine, more specifically inverse cosine because trig ratios are meant to figure out relative side lengths given angles and we are trying to figure out angles given the relative side lengths.  This is the equasion we come up with: cos^-1(4,000/4000.0019).  In your calculator cos^-1 will probobaly look like "acos".  If you plug that in to a calculator you get 0.558 which is the amount the horizon is below eye level in degrees.  Like I said, it's a fraction of a degree.  Before you call trigonometry a lie, keep in mind that it was used to design and build your house and if it were a lie then your house wouldn't be very structurally sound and all the pieces wouldn't fit together right.  Trigonometry is also the basis of all physics simulation as it is very nesesary to to velocity vector calculations in a coordinate based system.

Anyway, review my calculations and let me know if I did something wrong.

Right now I am too lazy and sleepy to review all of this, but I think you should also add the refraction. On average circumstances, the refraction makes the curvature of earth appear 15% less prominent, if I recall correctly.

Quote from: tappet on August 14, 2015, 01:30:51 PM

Quote from: mikeman7918 on August 14, 2015, 07:59:06 AM

Quote from: tappet on August 14, 2015, 02:22:12 AM

Oh, you mean something like if the earth is round the horizon should not come up to meet the eye.
Yeh tried that, but ball earthers think that the horizon coming up to meet the eye proves you are on a ball.
Pointless exercise!

Yeah, math shows that the horizon will become indistinguishably close to eye level on a round Earth.

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

Why don't you just ask a real doctor?

Ask a real doctor what?
The Friedewald equation, How about you find a doctor who knows it.

Quote from: tappet on August 14, 2015, 01:30:51 PM

No it does not you fool. It is a bunch of numbers made to try and fit something you see.
Here is an example,
                            LDL=HDL-T/5
This is the math to determine whether you will be taking heart medication or not.
The T represents triglycerides which are affected by sugar consumption, eat a shitload of sugar and according to the math you will have a healthy heart.
You are as blind as the people who use this formula.

I will walk you through this high school level math and show you why it has one answer and one answer only.  Here is a diagram representing what I have to calculate:


Here comes the explenation.  If you want to call it wrong you will have to point out where you think my fault is.

We are wanting to know angle a (the amount the horizon drops) and we know distance R (the radios of the Earth which is roughly 4,000 miles).  Let's say that your height (H) is 10 feet above sea level which is 0.0019 miles.

This means that we have a right triangle with the hypotenuse having a length of 4,000.0019 miles and the edge ajacent to the center having a length of 4,000 miles, and we want to know angle a.  This is a classic textbook trigonometry probelem, and it can be easily solved with trig ratios.  In case you slept through this part of your math class, here is a refresher:


The side lengths we know are hyponinuse and ajacent, so this calls for cosine, more specifically inverse cosine because trig ratios are meant to figure out relative side lengths given angles and we are trying to figure out angles given the relative side lengths.  This is the equasion we come up with: cos^-1(4,000/4000.0019).  In your calculator cos^-1 will probobaly look like "acos".  If you plug that in to a calculator you get 0.558 which is the amount the horizon is below eye level in degrees.  Like I said, it's a fraction of a degree.  Before you call trigonometry a lie, keep in mind that it was used to design and build your house and if it were a lie then your house wouldn't be very structurally sound and all the pieces wouldn't fit together right.  Trigonometry is also the basis of all physics simulation as it is very nesesary to to velocity vector calculations in a coordinate based system.

Anyway, review my calculations and let me know if I did something wrong.

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

So,  in your decades of experience,  why does your distance to the horizon change? 

Quote from: tappet on August 14, 2015, 11:12:46 PM

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

So,  in your decades of experience,  why does your distance to the horizon change?

Don't know, just does.

Quote from: Rayzor on August 14, 2015, 11:31:48 PM

Quote from: tappet on August 14, 2015, 11:12:46 PM

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

So,  in your decades of experience,  why does your distance to the horizon change?

Don't know, just does.

Have you ever seen the green flash?   

http://sandiegopictures.org/greenflash1/index.htm

http://www-rohan.sdsu.edu/~aty/

Quote from: Rayzor on August 14, 2015, 11:31:48 PM

Quote from: tappet on August 14, 2015, 11:12:46 PM

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

So,  in your decades of experience,  why does your distance to the horizon change?

Don't know, just does.

Lol, you're not very bright, are you?

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

Correction: I have 17 years of experience with reality, unless you are suggesting that I'm in the matrix.  I in fact do not have much experience at sea, because the only boat I have been on is a cruise ship a few years ago.

Quote from: Rayzor on August 14, 2015, 11:31:48 PM

So,  in your decades of experience,  why does your distance to the horizon change?

Don't know, just does.

Meanwhile I have one many horizon related calculations that have all been incredibly acurite and conformed flawlessly to reality.  I may not have as many years of experience staring at the horizon but I clearly understand it better then you.

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

Quote from: tappet on August 14, 2015, 11:46:44 PM

Quote from: Rayzor on August 14, 2015, 11:31:48 PM

Quote from: tappet on August 14, 2015, 11:12:46 PM

Your math means nothing to me. At 17 years of age you have no experience with reality you are in a virtual world. I have seen many changes in horizon distance on the ocean for decades longer than you have been alive.
But I do expect after your response to add "extensive experience at sea" to your resume. LOL.

So,  in your decades of experience,  why does your distance to the horizon change?

Don't know, just does.

Lol, you're not very bright, are you?

Obviously not. But look how smart you are.

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

It is this comment alone that proves beyond a doubt how dumb you really are.

Quote from: mikeman7918 on August 15, 2015, 11:27:02 AM

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

It is this comment alone that proves beyond a doubt how dumb you really are.

Argument with scientific basis, responded by something like "wow, you're so dumb" instead of a proper argument. Seems like a troll-like behavior... I'm beginning to suspect that there is actually no real FE believer in the debate section of this forum.

Quote from: mikeman7918 on August 15, 2015, 11:27:02 AM

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

It is this comment alone that proves beyond a doubt how dumb you really are.

Quit evading and point out where you think I manipulated the math to my will.

Quote from: tappet on August 15, 2015, 02:14:19 PM

Quote from: mikeman7918 on August 15, 2015, 11:27:02 AM

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

It is this comment alone that proves beyond a doubt how dumb you really are.

Quit evading and point out where you think I manipulated the math to my will.

Stop getting mad, your 17/18? year old persona is slipping into distant adult mode.

Stop getting mad, your 17/18? year old persona is slipping into distant adult mode.

Or maybe I am just a mature 17 year old.  Is that really so hard for you to comprehend?

Quote from: tappet on August 15, 2015, 02:14:19 PM

Quote from: mikeman7918 on August 15, 2015, 11:27:02 AM

By the way, you still haven't pointer out where I "manipulated numbers to get a desired result".  Math works, and math shows that what we see is what we expect on a round Earth.  Deal with it.

It is this comment alone that proves beyond a doubt how dumb you really are.

Quit evading and point out where you think I manipulated the math to my will.

This is why you are dumb, you think I am accusing you of manipulating math.
You have not manipulated the math. You do not understand what you are applying it to.
Just like the Freidwalde equation for determining heart disease. Same, same.

This is why you are dumb, you think I am accusing you of manipulating math.
You have not manipulated the math. You do not understand what you are applying it to.
Just like the Freidwalde equation for determining heart disease. Same, same.

So you agree that I am not manipulating my math and that math shows that we expect to see exactally what we do see on a round Earth?  Great.