If I get a rock out of the creek in my back yard, and then walk to the top of the nearest peak, will the rock fall apart because of the differential gravity? No? Well then, perhaps your theory is flawed.

s =

^{1}/

_{2}at

^{2}Distance traveled is one-half acceleration times time squared.

If you accelerate, say, the center of a deformable flat disc at 9.80 m/s

^{2} and the edge at 9.81 m/s

^{2}, after one second, the center would have traveled 4.90 meters and the edge 4.905 meters. Since it can be deformed, the center is lagging behind the edge by 5 mm. One second later, the center will have traveled 19.60 m and the edge, 19.62 m; the center in now 2 cm behind.

Distances traveled (meters) after accelerating at 9.80 and 9.81 m/sec

^{2} for different times:

Time (sec) | Lower Accel. (meters traveled) | Higher Accel. (meters traveled) |

1 | 4.900 | 4.905 |

2 | 19.600 | 19.620 |

3 | 44.100 | 44.145 |

60 | 17640 | 17658 |

3600 | 63,504,000 | 63,568,800 |

86400 | 36,578,304,000 | 36,615,628,800 |

After only one minute, the slower part is 18 meters behind the faster part. After an hour, it's 64.8

kilometers behind. After only a day (86400 seconds), the slower part is lagging by 37,324.8

kilometers. Thus, "Why doesn't the earth rip apart?"