Hi Saros, nice to see you here also!
Shall we fight with them like adults?
@ AUSGeoff, it's nice to hear you laughing, especially when i begin to feel desperate like Charlie in this scene:
" class="bbc_link" target="_blank" rel="noopener noreferrer"> Also, do you remember captain Bligh (Trevor Howard) how funny he looked like while attempting to dance tahitian dance?
Let's get serious now:
@ 29silhouette, calculating the differences of the different speeds of the Sun (when the Sun is above different latitudes) caused me to stumble upon "Equator" problem...
Few days ago (when there was sunny here) i have tried to measure the speed of the Sun (with a welding glass and a stopwatch). I noticed that the Sun moves one of his diameter in two minutes, that is roughly in accordance with zetetic reckoning of the diameter of the Sun AND with the RET & FET agreement over Equator circumference.
30 * 2 (minutes) = 1 hour
1666 / 30 = 55,5 km = 32 nautical miles = 34 statute miles = diameter of the Sun
So far, so good, but yes, you are right, the differences between the different speeds of the Sun (when the Sun is above different latitudes) would be too great to be acceptable if we calculated those differences assuming applicability of simple mathematical rules in the case of the Sun although we don't really know how Sun works at all...
That is why we should maybe reconsider these words of Sandokhan more carefully:
Therefore, statements such as: On March 21-22 the sun is directly overhead at the equator and appears 45 degrees above the horizon at 45 degrees north and south latitude. As the angle of sun above the earth at the equator is 90 degrees while it is 45 degrees at 45 degrees north or south latitude, it follows that the angle at the sun between the vertical from the horizon and the line from the observers at 45 degrees north and south must also be 45 degrees. The result is two right angled triangles with legs of equal length. The distance between the equator and the points at 45 degrees north or south is approximately 3,000 miles. and If a navigator neglects to apply the sun's radius to his observation at sea, he is 16 nautical miles (nearly) out in calculating the position his ship is in. A minute of arc on the sextant represents a nautical mile, and if the radius of the sun is 16 miles, the diameter is of course 32 miles. And as measured by the sextant, the sun's diameter is 32 minutes of arc, that is 32 nautical miles in diameter. cannot be true given the effect of the many layers of aether (of various densities) upon the light emitted by the Sun. Also, measuring the angle of the sun from a latitude of 30 degrees or 60 degrees will give different results.
And there are further issues to be dealt with, if we use simple triangulation to obtain possible figures for the Earth-Sun distance:
Read more, post #12 on this page: http://www.theflatearthsociety.org/forum/index.php?topic=39728.msg994892#msg994892
Plane Sailing 33 000 miles:
http://www.energeticforum.com/265962-post590.htmlProving water to be convex:
http://www.energeticforum.com/255875-post14.html