Happy birthday Leonhard Euler

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mathsman

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Happy birthday Leonhard Euler
« on: April 15, 2013, 12:51:38 AM »
It's the 306th anniversary of Leonhard Euler's birthday today. Not only my hero also my avatar. For those of a mathematical disposition who haven't heard of him google some of his work and boggle at his command of the subject. For those who think they have the ability to reinvent mathematics stay away from him: you're not fit to wipe his arse.

John Davis

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Re: Happy birthday Leonhard Euler
« Reply #1 on: April 15, 2013, 06:55:57 AM »
I wonder if Euler had similar around.
Quantum Ab Hoc

Rushy

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Re: Happy birthday Leonhard Euler
« Reply #2 on: April 15, 2013, 10:23:14 AM »
Math. Not even once.

FlatOrange

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Re: Happy birthday Leonhard Euler
« Reply #3 on: April 15, 2013, 08:38:21 PM »
Yay for math nerds!
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mathsman

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Re: Happy birthday Leonhard Euler
« Reply #4 on: April 21, 2013, 06:26:11 AM »
Below is a quote from Sandokahn in the flat earth believers forum. It is part of one of two responses to this thread. Why he posted this in a thread in which only a select few can reply is anybody's guess. Have a read through the post and see what you think.

Here is a formula which the conspirators missed while inventing Euler's work (I discovered this formula back in 1998; it makes any and all logarithm tables obsolete; LN v = natural logarithm of v):

LN v = ((-2 +{2+[2+...(2+ 1/v + v)^1/2]^1/2}^1/2))^1/2 x 2^n

n+1 parantheses to evaluate - in the last parenthesis we substract 2 and take the square root one last time (n+1), before we multiply the result by 2^n

For v very large, we can omit the term 1/v

Example LN 9999999999 = 23.02585093 (8 significant digits)

For our formula we will use n=12

The first parenthesis 2 + v (where v, of course, is equal to 9999999999), and we calculate the square root, (2 + v/2)^1/2 (n=1)

We add 2 to the result, and calculate the next square root (n=2), and so on, for n=12 we will obtain: 2.000031602

So for n=13 (12 + 1, n+1), we substract 2 in the last parenthesis, and calculate the last square root, obtaining:

5.62154783 x 10^-3

We multiply by 2^12, that is 4096 and get the final excellent approximation:

23.02585991

?

Thork

Re: Happy birthday Leonhard Euler
« Reply #5 on: April 21, 2013, 06:28:05 AM »
Leonhard Euler sounds like a porn name. Are you sure he's famous for maths?

mathsman

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Re: Happy birthday Leonhard Euler
« Reply #6 on: April 21, 2013, 06:38:12 AM »
Oh yes.
Your being an engineer I thought you would have heard of him. But it may be your impish sense of humour.

DDDDAts all folks

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Re: Happy birthday Leonhard Euler
« Reply #7 on: May 11, 2013, 01:03:09 PM »
Euler was a wise man.