OK. The rays are bound to cross, because the function has a minimal point. So if we apply that to a life flat earth scenario, there is a point on the light ray where the ray curves upwards again. Right? But where is this point? Is it above ground? Directly on the ground? Or below the ground? For if it is below ground rays will get absorbed before getting the chance to curve upwards, consequently the Bollybill effect wouldn't happen.
It depends on which ray of light you are talking about. They do not all need to have their minimum at the same altitude (and it would not make much sense for them to).
This is exactly the point I'm unsure about. I'm still not sure if i understand the subject, for my competence is limited, so I have the following question:
1.Every light ray emitted from the sun at a certain point of time shall be conceived as a function fr(x) = y , where y is the height above the earth plane and x is a spacial direction perpendicular to it, neglecting the third spacial direction. There is, of course, an infinite number or lightrays and thus functions: f1, f2, f3.....fn
2.The equation y = (.75)((b/c^2)*x^4)^(1/3) is supposed to be the formula for the bending behaviour of a light ray. b is meant as beta, the Bishop-constant.y is defined differently in the wiki, but I assume here that the direction of decreasing dark energy potential is factually equivalent to the height above the plane.
3.Doesn't that mean that all the functions f1, f2, f3......fn have the function g(x) = y = (.75)((b/c^2)*x^4)^(1/3) as their 1. derivative function?