Sun Speed

How fast is the sun orbiting above us? Can anyone calculate that?

Kind of. I mean the sun moves at different speeds depending on the time of year for FET.



But we are agreed that when the sun is directly over the equator, the distance of the equator is 24,901 miles. and of course the sun must complete a circle in 24 hours. So 24,901/24 = 1,038 mph which of course is the exact same speed that RErs say the earth spins at.

If we take the tropic of Cancer (North) we agree that line of latitude is at present the radius of the circle will be 6 378 x cos(23° 26′ 16″) which results in 5 851.77 km
Then,  = 3.1416 x 2 x 5851.77 which amounts to 36,767.8km or 22, 846miles. Divided by 24 gives 981 mph which is again how fast RERs claim the earth spins at that point.

So 981 mph is the slowest, and 1038 mph when its over the equator. You should work out how fast over the tropic of Capricorn yourself as a fun exercise. then you'll know the max speed of the FET sun.

It's been too long since I did trigonometry or geometry of any sort. Help a brother cheat on the exam and spoon feed me the answer please?

So what's the surface distance from the north pole to the equator anyway?

There seems to be two different distances between RET and FET.  I'm just curious what others have.

It's been too long since I did trigonometry or geometry of any sort. Help a brother cheat on the exam and spoon feed me the answer please?

One billion miles per hour

Quote from: Rama Set on March 06, 2013, 09:12:39 PM

It's been too long since I did trigonometry or geometry of any sort. Help a brother cheat on the exam and spoon feed me the answer please?

One billion miles per hour

No. Come on, guys. The answer is always 42.

Quote from: Rama Set on March 06, 2013, 09:12:39 PM

It's been too long since I did trigonometry or geometry of any sort. Help a brother cheat on the exam and spoon feed me the answer please?

One billion miles per hour

I guess you are one of those who would step on their grandmother to win :p

Thank you, Thork, for your well-informed answer! Assuming that the sun deviates as far out from the equator as it does toward the equator (327 miles), my calculations tell me the maximum sun speed is approximately 1123mph.

Thank you, Thork, for your well-informed answer! Assuming that the sun deviates as far out from the equator as it does toward the equator (327 miles), my calculations tell me the maximum sun speed is approximately 1123mph.

That sounds about right. If we had biscuits, you'd have earned one.

I did my math much differently and my answers seem to agree with the easier route of Googling "what is the circumference at tropic of capricorn/cancer" which yields "At both, it is 18,380 miles"

18,380 divided by 24~ 766 m/hr

Of course tropic of cancer is much bigger and after doing maths I got 1,308 mph.

Erm yeah, we are still out of biscuits.

It's okay. I was just about to make some anyway.

"If we take the tropic of Cancer (North) we agree that line of latitude is at present the radius of the circle will be 6 378 x cos(23° 26′ 16″) which results in 5 851.77 km"

23.5 degrees / 90 degrees = 26.1% --> 3,963 miles (radius at equator) - 26.1% of radius = 2,928 miles = radius at Tropic of Cancer.  2,928 x pi x 2 = 18,398.5 miles / 24 hrs =~ 767 mph

*stuffs face with biscuits and girl scout cookies*

Would be better if you could stuff your face into a girl scout.

Would be better if you could stuff your face into a girl scout.

 

#notcreepyatall.

Googling "what is the circumference at tropic of capricorn/cancer" which yields "At both, it is 18,380 miles"

Google is not infallible--it is merely bringing up figures that it found search results on. Neither one of us is going to believe that capricorn and cancer are in the same physical location.

No, but I could easily believe they are in two separate locations with the same circumference on a sphere.


24,901 mile circumference is all well and good (I also agree with this figure), but it would require a distance/radius of approximately 3,963 miles to result in a circumference of 24,901 miles.

So again, what is the surface distance in FET from the north pole to the equator?

All known measurements I see show approx. 6,210 miles from the pole to the equator (69 miles between each latitude line, 69x90=6,210), and 3,963 miles from the center of the earth to the equator, or radius.  If all the measurements I find show the surface distance to be 6,210 miles from the pole to the equator, then for FET that results in a 39,018 mile circumference equator. 

Measuring surface distance from the n. pole southward
Tropic of Cancer - 4,602 miles, 28,915 circumference, 1,204 mph sun speed. (4,602x2=9,204x3.1416=28,915/24=1,204mph)

Equator- 6,210 miles, 39,018 circumference, 1,625 mph.

Tropic of Capricorn - 7,827 miles, 49,178 circumference, 2,049 mph.

So if our earth is flat and I'm measuring known distances from the center outward to the equator and tropics and my math is wrong, by all means someone show me what I did wrong, or, are the world's maps and distances according to latitude lines actually incorrect, and my math is right?

Erm yeah, we are still out of biscuits.

No biscuits?! 

Also, I have clicked your sig multiple times now. Dang it.

Quote from: Thork on March 08, 2013, 02:09:38 PM

Erm yeah, we are still out of biscuits.

No biscuits?! 

Also, I have clicked your sig multiple times now. Dang it.

You mean the Rick Roll? Lol

You mean the Rick Roll? Lol

Yeah it's been a long time since I've been rick rolled 

South of the equator, we do see the round earth maps break down. I can't speak to whether this is because of mistakes due to thinking the world is round or intentional falsification--I'm not a cartographer.

Kind of. I mean the sun moves at different speeds depending on the time of year for FET.



But we are agreed that when the sun is directly over the equator, the distance of the equator is 24,901 miles. and of course the sun must complete a circle in 24 hours. So 24,901/24 = 1,038 mph which of course is the exact same speed that RErs say the earth spins at.

If we take the tropic of Cancer (North) we agree that line of latitude is at present the radius of the circle will be 6 378 x cos(23° 26′ 16″) which results in 5 851.77 km
Then,  = 3.1416 x 2 x 5851.77 which amounts to 36,767.8km or 22, 846miles. Divided by 24 gives 981 mph which is again how fast RERs claim the earth spins at that point.

So 981 mph is the slowest, and 1038 mph when its over the equator. You should work out how fast over the tropic of Capricorn yourself as a fun exercise. then you'll know the max speed of the FET sun.

That diagram doesn't make sense, the sun isn't like a flashlight, it doesn't shine directly down, How can it? its spherical. The sun shines Around it in all directions, so actually, there should always be day time?

That diagram doesn't make sense, the sun isn't like a flashlight, it doesn't shine directly down, How can it? its spherical. The sun shines Around it in all directions, so actually, there should always be day time?

No, it's a spotlight that reflects the Earth's luminance.

Quote from: Aeromuch on March 15, 2013, 03:35:16 PM

That diagram doesn't make sense, the sun isn't like a flashlight, it doesn't shine directly down, How can it? its spherical. The sun shines Around it in all directions, so actually, there should always be day time?

No, it's a spotlight that reflects the Earth's luminance.

How do you know this? How does this spotlight work? What is Earth's "luminance", and how could it account for something as bright as the sun?

How do you account for observations showing that the sun:
1. Has surface features
2. Rotates
3. Is a mass of Hydrogen fusing into Helium?

How do you know this? How does this spotlight work? What is Earth's "luminance", and how could it account for something as bright as the sun?

Infrared radiation from the UA getting refocused into radiation covering the spectrum of visible light.

How do you account for observations showing that the sun:
1. Has surface features
2. Rotates
3. Is a mass of Hydrogen fusing into Helium?

Inaccurate conjecture due to inaccurate understanding of the universe.

Quote from: Shmeggley on March 26, 2013, 07:28:02 AM

How do you know this? How does this spotlight work? What is Earth's "luminance", and how could it account for something as bright as the sun?

Infrared radiation from the UA getting refocused into radiation covering the spectrum of visible light.

This is an unverified claim.

Quote from: Shmeggley on March 26, 2013, 07:28:02 AM

How do you account for observations showing that the sun:
1. Has surface features
2. Rotates
3. Is a mass of Hydrogen fusing into Helium?

Inaccurate conjecture due to inaccurate understanding of the universe.

This is also an unverified claim.  Do some experiments on your UA please.  Publish the results somewhere (even here would be good), and then you can stand toe to toe with Solar Physics. 

Quote from: Shmeggley on March 26, 2013, 07:28:02 AM

How do you know this? How does this spotlight work? What is Earth's "luminance", and how could it account for something as bright as the sun?

Infrared radiation from the UA getting refocused into radiation covering the spectrum of visible light.

Quote from: Shmeggley on March 26, 2013, 07:28:02 AM

How do you account for observations showing that the sun:
1. Has surface features
2. Rotates
3. Is a mass of Hydrogen fusing into Helium?

Inaccurate conjecture due to inaccurate understanding of the universe.

A: Wait, is it the Earth's "luminance" or UA? Isn't UA Universal Acceleration? Acceleration doesn't cause infrared radiation. If there was some infrared coming up from the ground wouldn't the ground feel hot? Normally there is some infrared coming from the ground - but that's because the sun warms the Earth! Suppose there was some infrared radiation coming up from the ground due to some reason - how does it get "refocused"? The air doesn't do this, you'd need some kind of lens.

Unless you can answer these questions your reply is incoherent.

B: These observations are trivial.

1. You can see the sunspots yourself using a pinhole camera projection of the sun.

2. Likewise, through spectral analysis of the eastern and western limbs of the sun you can measure a difference in doppler shift - one limb is blue shifted the other red shifted.

3. Again, by looking at absorption and emission lines you can tell what elements the sun contains - this is how helium was discovered - which turn out to be hydrogen and helium. Also we can detect neutrinos from the sun, which come from the fusion reactions.

Again, unless you can explain these phenomena I think it makes more sense to consider the sun a rotating sphere, not a spotlight.

1. You can see the sunspots yourself using a pinhole camera projection of the sun.

Looking at a cells through a microscope, you will see moving spots as well. The slide is not a burning ball of helium 9.3 million miles away. Also, do you know how DLP TVs work?

2. Likewise, through spectral analysis of the eastern and western limbs of the sun you can measure a difference in doppler shift - one limb is blue shifted the other red shifted.

There's no reason this cannot be accounted for by reflection. In fact, reflection makes it quite a bit more intuitive to explain.

3. Again, by looking at absorption and emission lines you can tell what elements the sun contains - this is how helium was discovered - which turn out to be hydrogen and helium. Also we can detect neutrinos from the sun, which come from the fusion reactions.

It seems that the data that you have provided tends toward a spotlight Sun reflecting and focusing the Earth's luminance even more conclusively.

Quote from: Shmeggley on March 27, 2013, 10:19:25 AM

1. You can see the sunspots yourself using a pinhole camera projection of the sun.

Looking at a cells through a microscope, you will see moving spots as well. The slide is not a burning ball of helium 9.3 million miles away. Also, do you know how DLP TVs work?

What a spectacular strawman, well done.

Quote from: Shmeggley on March 27, 2013, 10:19:25 AM

2. Likewise, through spectral analysis of the eastern and western limbs of the sun you can measure a difference in doppler shift - one limb is blue shifted the other red shifted.

There's no reason this cannot be accounted for by reflection. In fact, reflection makes it quite a bit more intuitive to explain.

How does reflection create red-shifting of light? 

Quote from: Shmeggley on March 27, 2013, 10:19:25 AM

3. Again, by looking at absorption and emission lines you can tell what elements the sun contains - this is how helium was discovered - which turn out to be hydrogen and helium. Also we can detect neutrinos from the sun, which come from the fusion reactions.

It seems that the data that you have provided tends toward a spotlight Sun reflecting and focusing the Earth's luminance even more conclusively.

[/quote]

Can you walk me through your conclusion? Tt seems inferred, and not explicit.  Thank you.