My apologies Rama Set, I got your question 90 degrees out!

This is actually even simpler to work out (well, it is on a round earth at least!). If a person at the North pole sees Jupiter at 35 degrees above the horizon, then for every 60 nautical miles, or one degree of latitude, that you move South, Jupiter will 'rise' one degree in the sky. To put that in the context of your question, at 73N, Jupiter would appear to be 35 + 90 - 73 = 52 degrees above the horizon (35 is it's apparent elevation at 90 degrees latitude (north pole), and the difference in elevation is simply the difference in latitude (90 - 73 = 17)).

For a FE model, your results would depend greatly on the altitude of the celestial bodies. First you would need to calculate a position fir Jupiter, using whatever altitude it's supposed to be at. I'll write you an equation:

e = elevation relative to the horizon (in degrees)

a = altitude of object to be observed

d = horizontal distance to object (note, this is not the line of sight distance! Rather, it is the distance along the ground, assuming the ground is entirely flat)

d = a / tan(e)

So, for Jupiter having an altitude of 3500 miles (chosen because it seems to suit some FE models), and your angle of 35 degrees: d = 3500 / tan(35) = 4998.5 miles. If we now go to 73N, we have traveled 17 * 60 = 1020 **nautical** miles. Better convert those to statute, since that's what we're doing our calculations in = 1147.5 miles. So our horizontal distance to Jupiter is now 4998.5 - 1147.5 = 3851 miles. Rearranging our equation to give us the angle:

tan(e) = a / d

e = tan^{-1} (a / d)

Plug in the numbers:

e = tan^{-1} (3500 / 3851) = 42.3 degrees

Okay, I know that was really long winded, but I hope it answered your question!