A first clue: in this page (whose content has nothing to do with our discussion)
http://www.oc.nps.edu/ripex/sbe2/summary/steep.htmthey say: "...Sand City, California where the beach is composed of a steep beach face...". Steep beach face?
But these movies resolve the mistery. See the Sand City beach:
#" class="bbc_link" target="_blank" rel="noopener noreferrer">Paragliding in sand City#" class="bbc_link" target="_blank" rel="noopener noreferrer">Ridge Soaring in Sand City, Californiaothers:
h t t p://w w
h t t p://w w
h t t p://w w
(strip spaces. Got error. But are the same as the first two)
The coast is really raised above the water over there! And is that coast that Mr. Bishop saw.
Let's do a bit of math, using the same Bishop's method, as he exposed in his post. Well then, the distance from Lovers Point to Sand City beach is 3.3 miles (5.3 km). Applying the formula let's find how much the visual drops.
According to the official measures the earth has an average radius of 6,371 km
http://en.wikipedia.org/wiki/Earth_radiussquare root(6371**2 + 5.3**2) - 6371 = 2.20 metres (7.23 feet)
This does mean that from Lovers Point you can see an object tall as such or taller.
If you roughly calculate the mean altitude of Sand City beach in Google Earth you will find a bigger value than that. This does mean that the observations of Mr. Bishop are perfectly consistent with a round earth!
But we aren't done yet. The poster says: "I can see children running in and out of the water, splashing and playing." Indeed he's talking about water, that is certainly lower than the dunes of the beach. Let's go back to Lovers Point. He was "laying down on the stomach at the edge of the shore on the Lovers Point beach 20 inches above the sea level". But he was on the ground, not in the water. I would bet that he was meaning "20 inches above ground level" Use the "mouse cursor trick" in Google Earth on Lovers Point beach and you will see various altitudes, 1 metre, 2, 3, up to 5 (3.28 to 16.40 feet). Where was exactly Mr. Bishop? He didn't bother to say it. In this page:
http://en.wikipedia.org/wiki/Horizonwe learn that the horizon if you are at height 'h' from ground can be calculated with: d=3.57xsquare root(h), where h is in metres and d (distance of horizon) in km.
If e.g. Tom Bishop was 20 inches (=0.5 metres) in a point located 2 metres above sea level, we have: d = 3.57 x square root(2.5) = 5.64 km (3.5 miles), that is more than the distance Lovers Point - Sand City beach! No wonder he did see the water.
Once again, all that is perfectly compatible with a round earth.
The post we are talking about was inserted in this Wiki page:
http://www.theflatearthsociety.org/wiki/index.php?title=Experimental_Evidencethat contains "proofs" that the earth is flat. The Bishop's contribute is really the most important.
Now Mr. Bishop should do two things:
1) To go in a point of Pacific Grove faced openly at the Bay aiming the telescope exactly at Lighthouse State Beach with the aid of a compass;
2) Let us know what he sees.
I can't wait.