# How are there timezones

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#### Rushy

• 8971
##### Re: How are there timezones
« Reply #180 on: August 26, 2012, 04:15:34 PM »
Well, he has won. He and others asked you to clarify specific points about your argument, you refused, you told lies that he couldn't understand it because of the complexity of maths whilst still shoving a high-school level example at us, you continued to refuse to answer the requests he made, and so yes, you do forfeit the debate because you refuse to engage with it.

Thank you for admitting that you can't understand high school level examples. That leads us to why I should post math when you don't understand words? I'm not your request monkey, making a request and then being denied does not equal an instant win.

#### FlatOrange

• 2456
##### Re: How are there timezones
« Reply #181 on: August 26, 2012, 04:48:18 PM »
Irushwithcvs,

If something is too distant to see through the atmo-sph... *ahem* atmolayer, then why does it not also change in size?  The sun and moon, being 32 miles across, should change size proportionately equal to the amount of atmolayer in between.  Additionally, with your descriptions sunsets and sunrises would be a gradual change throughout the day. The sun's intensity at noon would be unmatched.  However, a sunrise and sunset is instant.  It does not fade in or out, it rises.  Over the land.  You can see mountains lit by the sun (buildings for all you city-folk) before the valleys are lit. It's not because of less atmolayer in between the mountain and the valley.  The mountain is taller.

You spend lots of time belittling people on here telling them they don't understand things.  Perhaps you should go outside for awhile and wonder at the world away from your computer.
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#### Cat Earth Theory

• 1614
• I practise the Zetetic Method!
##### Re: How are there timezones
« Reply #182 on: August 26, 2012, 05:11:19 PM »

2. Trigonometry. Take this right angle triangle for example:

Lets us suppose the sun is at point B. Line AC represents the disc of the Earth. An observer at C would see the Sun, while an observer at A would not. Why is this? The Sun's light has to penetrate a great deal more matter to get to point A than Point C. This is because the length of line AB is longer than line BC.

If the sun is 3000 miles up, that means the sun should be 34,290 miles away when the sun is 5 degrees above the horizon.

That's an awfully large area the sun should be visible in.
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#### sonyca

• 13
##### Re: How are there timezones
« Reply #183 on: August 27, 2012, 04:20:00 AM »
If not for burt can you atleast explain the theory for the rest of us.

I explained it throughout the thread, but a recap won't hurt. Basically, the atmolayer, which is made of various materials, is not 100% transparent. Eventually the light is so distorted through reflection and refraction that it never reaches your eye. You can "see" this effect by looking at the sky during daylight hours (hint: the blue haze color is caused by refraction throughout the atmolayer reaching your eye). Once an object becomes too distant from the observer, it disappears. This isn't because the object stopped existing, but because the light from it never reached your eyes. You're not going to see something if the radiation it emits never reaches you. This is the same reason clouds can appear lit up during sunrise or sunset but the Sun itself can not be seen. As the Sun approaches its highest point in the sky, it will appear brighter (same for the Moon) and dim as it approaches the horizon. The Moon shows this effect more nicely than the Sun, even going as far as showing the appropriate red shift when near the horizon.

This is not caused by any type of eclipse. This shifted color is caused by atmolayeric density blocking a portion of the Moon's spectrum emissions. As the Moon becomes higher in the sky, it will whiten.

So what happens to this light, it can't be destroyed so are you saying that it bounces out of the atmolayer? Or simply becomes so spread out by refraction and reflection that we can't see enough of it at once to make anything out

#### ThinkingMan

• 1830
• Oh, Really?
##### Re: How are there timezones
« Reply #184 on: August 27, 2012, 05:51:54 AM »
http://www.theflatearthsociety.org/forum/index.php/topic,54253.msg1335518.html#msg1335518

The flat Earth image you showed is correct. It is also the reason when people use airplanes, they can see "two sunsets" after take off. The upper atmolayer is less dense, allowing a longer viewing of the Sun than could be obtained otherwise. I assume by the smiley you think this is evidence for a round Earth, when in fact is just further supports a flat Earth. Thank you for contributing.

This is a very bad attempt at showing a lack of understanding. Refraction happens exactly opposite of what you are saying. For the sun to appear lower in the sky, the light would have to bend "upwards" upon hitting the atmosphere (layer?). For the light to bend upwards, it would have to be going faster. Light travels slower when moving through a thicker medium, as does anything else. I would say air is thicker than space, right rushy? When light hits a thicker medium and travels slower, it bends "down," causing things to appear higher in the sky. Which means that when you look at the sun during sunset, it is lower (relative to eye-line) than it appears, not higher.

The light bending "downward" is why you can see light hitting the bottoms of clouds before you can actually see the sun itself. And, to address another issue...

... If the light from the sun is being dispersed so much that you can't see the sun, then the light would not reflect off of the bottom of the clouds. If it can't reach your eye directly from the sun, then how is it 1. going to break the law of physics and refract backwards to bounce off of the bottom of the clouds and 2. travel further than you say it can to meet your eye?

Do you need a diagram for this? I'll describe one. Take your triangle, and tilt it so that the longer side (side C, if you will) is level, like the ground. Now bend it, stretch it a bit, and lower corner A to where the bottom of the clouds should be (this should be done so that side C is no longer straight, but side A and B still are, and side C should be an arc so the light can go under the clouds). Corner B should still be the "sun." Corner C is the observer, so lets stretch that and put it under the clouds. It should look something like this...

So basically what you're saying is that we can see the light after it's traveled a longer distance through the atmo(layer?) (from the sun, to cloud, to observer), but not the shorter distance (directly from sun to observer)? This goes against what you've been saying about The light not being able to reach us from the sun, because that light that bounces off of the bottom of the cloud is from the sun. What is the explanation for this? Also, there are many more unanswered questions in this thread.
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