Each has its own elaborate explanations necessary to explain simple phenomena, and both are subject to revision. Some posts here say that observing a flat terrain and consistently downward oriented gravitation produces a simpler model than a imperceptibly curved surface and gravity following radial vectors around that surface. Appealing to intuition would be a fallacy, but the comparative simplicity of these two specific respects could be acknowledged by testing which model is easier for a child to understand.
I don't know what that means, but I do know that RET gravity does no such thing.
If you don't know what that means, how do you know it doesn't do it?
Easily. If I detect nonsense such as your claim, I can say RET doesn't. Now what did you mean?
Let's review your claim is the OR applies here. Then you claim that you've never applied OR to either FET or RET. You seem to be very confused.
Let me present another way of explaining OR.
Let P(x) be the predictive power or x.
Let x be a set of tenets of a theory.
Let y be another set of tenets.
We reject y as part of the theory iff P(x+y) <= P(x)
OR does not select between two independent theories. It simply pares away unneeded tenets of a theory.
Let's work an made-up example.
Let x = {"The Sun is a sphere"}
Let y = {"The Sun rotates about its axis."}
P(x) does predict its appearance except for sunspots.
P(x+y) does also explain the periodic appearance of the sunspots.
Since P(x+y) > P(x) we do not reject y.
And another example:
Let x = {"To produce a honking noise I can press the center of my steering wheel."}
Let y = {"To produce a honking noise I must swear aloud before pressing the center."}
P(x) does predict the noise.
P(x+y) does also predict the noise.
Since P(x+y) = P(x) we reject y.
(This is how to reduce superstitions, by the way.)