The formula requires temperatures at the place of the observer, and at the upper layer of the visual target you mentioned.
Since the low was about 8.3C, certainly at 19:30 (viewer from Holland mentiones it was beginning to get dark), or at 20:00, we will have a temperature of about 10C (in fact I could go as high as 12, given the fact that the high was at 15.5C).
Where do you want to go from here?
Let us assume, for the sake of the discussion, that in Milwaukee at 1000 m altitude, there were 23C (of course, this would stretch the imagination, but these are the lengths to which we have to go to convince RE the earth is flat). How could we have 10C at some 183 meters in altitude, and 800 meters higher, 23C, a difference of 13 degrees?
Even with these unbelievable numbers, the lapse rate will be around -90C/km, and the result, of course, negative.
With a high of around 15.5C, there is no way that the layers at about 800-1000 m in altitude could have had more than, say, 18C.
But we used 23C in our formula.
If we use the data from 1925, then the altitude of the observer will be some 10 meters, and the same goes for the target (Racine, in 1925). Then the visual obstacle will measure some 1068 meters.
With these numbers, even if we go to 25C at the visual target, Racine, we still get a negative number.
The surface over the lake Michigan is completely flat, no question about it...
We already talked about the droplets of water contained in the clouds...
Water, though eight hundred times heavier than air, is held in droplets, by the millions of tons, miles above the ground. Clouds and mist are composed of droplets which defy gravitation. For quite a while, that cloud will hold those droplets of water, DEFYING ATTRACTIVE GRAVITY, that is what are talking about here. With no wind present, those droplets defy attractive gravitation...given the difference in weight (800 times heavier than air). The explanation accepted by science is silly, and defies the visible facts.
Nowhere is it asked why ozone does not descend of its own weight or at least why it is not mixed by the wind with other gases.
With attractive gravity, OZONE WOULD DESCEND IMMEDIATELY AS ITS SPECIFIC WEIGHT IS GREATER THAN THAT OF OXYGEN.
And you have no answers about the fact that gases do not stay separated according to specific weights, or about the barometric pressure paradox.
Gravity is the pressure of the ether, the telluric currents, discovered by Tesla, Moray, and Schauberger, to name but a few...please read about Francis Nipher's experiments with gravity...you will find the link in my messages.
The Soviet Academy Science states quite clearly: the explosion was seen from Irkutsk and from the shores of Lake Baikal, here is their map:
http://www.icr.org/research/index/researchp_sa_r05/The inhabitants of Central Siberia saw the fall and explosion of the meteorite over an area with a radius of 600-1000 km.
Given the fact it was a cloudless day, the visual range limit is 400 km.
Nothing could be seen beyond that limit, due to curvature; the visual obstacle from Lake Baikal (435 meters in altitude) is 21.7 km. The visual obstacle from Irkutsk is 67.5 km.
No other explosion occurred at 7:15 over Asia; give up the nonsense...the fuckball is in your court, do the research and prove to us here otherwise...
The description of the trajectory, as being erratic, and of the explosion itself LEAVES NO DOUBTS, no matter how much you bicker about it.
In London, as all over Europe, at exactly 0:20, newspapers could be read without street lighting.
On June 30, 7:15 - 7:20 am, there was sunlight all over Siberia. In London, at 0:15, of course, there was darkness, around midnight. We are told, in the official theory, that this happens because of the curvature of the Earth, which blocks the rays of light from the Sun.
Then, how could an explosion which did take place at some 7km in altitude, on a cloudless day, be seen from Irkutsk, the Gobi desert, and from London itself?
We have the glow of the trajectory, on one side of a globe, and the immediate, instant observation on the other side the same globe, from London.
No glow could be seen on a round earth, given the 7463 km visual obstacle, those are the facts.