Fine, I'll make a new thread for it...

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Fine, I'll make a new thread for it...
« on: March 01, 2011, 08:00:10 PM »
Can anybody explain how impact craters formed on the underside of the moon, and how loose matter stays on the underside of the moon? ???
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Tristan

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Re: Fine, I'll make a new thread for it...
« Reply #1 on: March 02, 2011, 04:58:32 AM »
Can anybody explain how impact craters formed on the underside of the moon, and how loose matter stays on the underside of the moon? ???

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Beorn

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Re: Fine, I'll make a new thread for it...
« Reply #2 on: March 02, 2011, 05:01:46 AM »
The "impact craters" are the valleys where the moonlions live.
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Hessy

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Re: Fine, I'll make a new thread for it...
« Reply #3 on: March 02, 2011, 05:41:05 AM »
The "impact craters" are the valleys where the moonlions live.

Didn't you try to derail another thread by saying exactly that ???

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hoppy

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Re: Fine, I'll make a new thread for it...
« Reply #4 on: March 02, 2011, 05:45:31 AM »
Can anybody explain how impact craters formed on the underside of the moon, and how loose matter stays on the underside of the moon? ???


   No one has been to the moon to investigate that.
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Beorn

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Re: Fine, I'll make a new thread for it...
« Reply #5 on: March 02, 2011, 06:16:06 AM »
The "impact craters" are the valleys where the moonlions live.

Didn't you try to derail another thread by saying exactly that ???

Asking the same questions usually yields the same answers. 1+1 is most of the times 2.
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EnglshGentleman

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Re: Fine, I'll make a new thread for it...
« Reply #6 on: March 02, 2011, 08:02:30 AM »
The "impact craters" are the valleys where the moonlions live.

Didn't you try to derail another thread by saying exactly that ???

Asking the same questions usually yields the same answers. 1+1 is most of the times 2.

Whenever it rains it seems like 1+1 is all of the time 1.

 ???

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Beorn

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Re: Fine, I'll make a new thread for it...
« Reply #7 on: March 02, 2011, 08:04:12 AM »
The "impact craters" are the valleys where the moonlions live.

Didn't you try to derail another thread by saying exactly that ???

Asking the same questions usually yields the same answers. 1+1 is most of the times 2.

Whenever it rains it seems like 1+1 is all of the time 1.

 ???

w+w = w

Where w is equivalent to 1.
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EnglshGentleman

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Re: Fine, I'll make a new thread for it...
« Reply #8 on: March 02, 2011, 08:11:37 AM »
It seems you have learned your math incorrectly.

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Beorn

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Re: Fine, I'll make a new thread for it...
« Reply #9 on: March 02, 2011, 08:38:49 AM »
I have, that's why I try to learn from this site. Can you help me, please?
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Hessy

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Re: Fine, I'll make a new thread for it...
« Reply #10 on: March 02, 2011, 09:27:06 AM »
Not this again... for the love of God, someone lock this thread.

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Re: Fine, I'll make a new thread for it...
« Reply #11 on: March 02, 2011, 11:48:08 AM »
In other words, there is no explanation, thanks.
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Tom Bishop

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Re: Fine, I'll make a new thread for it...
« Reply #12 on: March 04, 2011, 08:25:31 PM »
Take a look at this picture: http://homepage.mac.com/rarendt/Pics/20041126_moon_color.jpg

Can you tell what angle the meteors came in at to hit the moon? How do you know that the meteors aren't hitting the moon from its side rather than it's bottom?

Also, the moon may have been turned another way in the distant past.

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squevil

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Re: Fine, I'll make a new thread for it...
« Reply #13 on: March 04, 2011, 09:09:17 PM »
i would have to agree with tom here. the moon could of turned over time, maybe the effect of UA?
but the rocks on the bottom should fall off. may explain how we have craters too

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markjo

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Re: Fine, I'll make a new thread for it...
« Reply #14 on: March 04, 2011, 09:25:09 PM »
Can you tell what angle the meteors came in at to hit the moon? How do you know that the meteors aren't hitting the moon from its side rather than it's bottom?

You can gain insight about the size, speed and direction of the meteors hitting the moon by examining the size and shape of the impact craters as well as the relative amount and dispersal pattern of the ejecta.  Quite Zetetic, if you ask me.
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fluffycornsnake

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Re: Fine, I'll make a new thread for it...
« Reply #15 on: March 06, 2011, 10:05:12 AM »
w+w = w

Where w is equivalent to 1.

v+v = w

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Re: Fine, I'll make a new thread for it...
« Reply #16 on: March 06, 2011, 01:44:25 PM »
Take a look at this picture: http://homepage.mac.com/rarendt/Pics/20041126_moon_color.jpg

Can you tell what angle the meteors came in at to hit the moon? How do you know that the meteors aren't hitting the moon from its side rather than it's bottom?

Also, the moon may have been turned another way in the distant past.

I'm not sure how they could hit the moon from the side in a flat earth model? ???
The moon may have rotated, certainly...a rotating moon is certainly a novel concept. None of this addresses my other question, which I eagerly await the answer to.
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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #17 on: March 06, 2011, 03:23:40 PM »
I'm not sure how they could hit the moon from the side in a flat earth model? ???

Lunar gravitation?

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None of this addresses my other question, which I eagerly await the answer to.

Lunar gravitation?
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squevil

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Re: Fine, I'll make a new thread for it...
« Reply #18 on: March 06, 2011, 04:58:39 PM »
I'm not sure how they could hit the moon from the side in a flat earth model? ???

Lunar gravitation?

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None of this addresses my other question, which I eagerly await the answer to.

Lunar gravitation?

yeh he does post a very good point about the moons 'gravity' how do the loose objects just stick on?
problem is mate many will be stuck as i didnt notice this in ENAG

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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #19 on: March 06, 2011, 05:38:13 PM »
They "stick on" by lunar gravitation.
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Re: Fine, I'll make a new thread for it...
« Reply #20 on: March 06, 2011, 06:39:42 PM »
They "stick on" by lunar gravitation.

Can you explain how lunar gravitation works, please?
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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #21 on: March 06, 2011, 06:56:53 PM »
I cannot.
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squevil

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Re: Fine, I'll make a new thread for it...
« Reply #22 on: March 06, 2011, 07:47:46 PM »
would it be fair to say its the mass of the moon that creates it?

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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #23 on: March 06, 2011, 07:52:08 PM »
I'm not sure that is fair to say. Assuming some variation of relativity, it would be based on the moon's stress on the mass-energy-momentum tensor. Or the mechanism could be unrelated.
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squevil

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Re: Fine, I'll make a new thread for it...
« Reply #24 on: March 06, 2011, 07:56:35 PM »
im all down for FET but not UA. what im really getting at is if the moon has gravity of a sort then wouldnt earth? perhaps gravity is the mistake and its something else that attracts us to the surface

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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #25 on: March 06, 2011, 08:00:13 PM »
Assuming something resembling GR, perhaps the celestial bodies are simply more energetic (or dense) than the earth. Apart from that, it could be any one of ineffable differences between the earthen bodies and the celestial bodies that account for the gravitation.
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Oracle

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Re: Fine, I'll make a new thread for it...
« Reply #26 on: March 08, 2011, 10:54:17 AM »
Can anybody explain how impact craters formed on the underside of the moon, and how loose matter stays on the underside of the moon? ???

I assume you mean for RET? and not FET?

From what I can discern from FET, you cannot definitively state that what you are seeing upon the face of the moon are in fact craters.  The moon is only 32 miles across and travels in a circular path across the face of the flat earth.  No-one has been to the moon, as that is seen as a hoax.  So to assume that these deformations are in fact craters in FET is presumptious and is inherently a gross erroneous assumption.

For RET, the earth is in a lunar-synchronous orbit, so we always see the same side of the moon which is always directly facing the earth.  It is possible (as stated above) that this may not be a perfect lunar-synchronous orbit, and over the span of thousands or millions of years, there may actually be a discernable rotation noticed.  But even assuming that the orbit is perfectly lunar-synchronous, you would still have to keep in mind that the earth and the moon in RET are spherical, and a meteroite can still impact with the moon on the underside if it approaches at an angle across from the earth side.

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Re: Fine, I'll make a new thread for it...
« Reply #27 on: March 08, 2011, 05:33:36 PM »
I'm not sure that is fair to say. Assuming some variation of relativity, it would be based on the moon's stress on the mass-energy-momentum tensor. Or the mechanism could be unrelated.

What does this mean?

And thank you for the complete response, Oracle.
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Ski

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Re: Fine, I'll make a new thread for it...
« Reply #28 on: March 09, 2011, 02:26:04 PM »
It means that if GR is true the moon's gravitation is not necessarily due to it's mass.
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Re: Fine, I'll make a new thread for it...
« Reply #29 on: March 09, 2011, 05:09:15 PM »
It means that if GR is true the moon's gravitation is not necessarily due to it's mass.

Then what is it necessarily due to? I'm not sure what part of that phenomenon is supposed to apply to the moon but not the earth, given that they both have mass and momentum and all that. And I don't simply want to hear that the earth is different from the moon, that is obvious. I want to know how they are different, and why the moon can attract and earth can't. I think it's a pretty straightforward question and I would genuinely appreciate a similarly straightforward answer.
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