A giant beach ball (gravity)

Using the "round Earth" theory, setting an object on the earth would be like setting grains of sand on a beach ball. Certainly a few grains would stay - right around the top, the surface is nearly horizontal - but when you stray too far from the absolute top of the ball, the grains of sand start sliding off and falling onto the ground. The Earth, if round, should behave in exactly the same fashion. Because the top is a very localized region on a sphere, if the Earth were in fact round, there would be only a very small area of land that would be at all inhabitable. Stray to the outside fringes of the "safe zone", and you start walking at a tilt. The further out you go, the more you slant, until your very survival is determined by the tread on your boots. Reach a certain point, and you slide off the face of the planet entirely. Obviously, something is wrong.

Thats a quote from the alaska.net flat earth website. its not really that logical that explanation because gravity is not a force acting in one direction of the earth it is acting towards the centre, on a RE that is. Every planetary body (including the Earth) is surrounded by its own gravitational field, which exerts an attractive force on all objects. Assuming a spherically symmetrical planet (a reasonable approximation), the strength of this field at any given point is proportional to the planetary body's mass and inversely proportional to the square of the distance from the center of the body. so on earth it is proportional to its size making things accelerate at 9.8m/s/s. on jupiter for example, it is not as heavy as earth and as a result the gravity is on 1/3 that of earths. this is explained very comprehensively and it more than disproved the weird example that the alaska.net site give.

Alaska.net is a parody of this one.

Amazingly Bishop is right, that site is a joke.  This one is serious, lol I know. 

I stipulate that basketguy15 is 15 years old. Prove me wrong.