http://www.sacred-texts.com/earth/za/
Free your mind, brother.

Let A B represent the arc of water 6 miles long, and A C the line of sight. The point of contact with the arc would be at T, a distance of one mile from the observer at A.
From T to the bridge at B would be 5 miles, and the curvature from T to B would be 16 feet 8 inches. The top of the flag on the boat (which was 5 feet high) would have been 11 feet 8 inches below the horizon T, and altogether out of sight.
These two points are six statute miles apart.Lets do some math: 5 statue mile = 8.04672 km - distance from T to B
And curvature: 16 feet 8 inches = 5.08 m
Let's do some math with Circle calculator:
http://www.1728.com/circsect.htmAnd we see that if we take 8 km of earh ( 6370 km radius ) the curvature is 1.25 m!
If we take 8 km and curvature of 5.08 m we see that earth has 1590 km diamater !!!
So in the Expiriment 1 calculations are completely wrong !
Do some math Brother !