lolz0ar.
Because curvate of the earth is so small that you can't feel it.
Never mind that. I thought I replied to some person who said if the earth was round, then how come we don't feel like walking uphill. I just asked him why we wouldn't feel like walking downhill
On another note, regarding the drawing to scale. It is possible to estimate the maximal height of a mountain on a certain planet. Namely, just assume that the gravitational potential energy released by melting of a small layer of the bottom of the mountain is not greater than the heat needed for melting it. Assuming that the mountain has a conical shape with a height
H and the height of the bottom layer is
x <<
H, then the mass of the melted part is
ρ*V*[1 - (H - x)3/H3] ≈ 3*ρ*V*x/H,
where
V is the total volume of the mountain, and
ρ is its density.
One can show that the CM of a pyramid (cone) is at 1/4 of it's total height from the botton. Therefore, the decrease in potential energy is:
ρ*g*V*H/4 - ρ*g*V*(H - x)*(H-x)/(4*H) = (ρ*g*V*H/4)*[1 - (H - x)2/H2] ≈ (ρ*g*V*H/4)*(2*x/H) = ρ*g*V*x/2
If the Latent heat of fusion (melting) is
L, then the mountain should be stable under this kind of collapse as long as:
ρ*g*V*x/2 < 3*ρ*L*V*x/H
H ≤ 6*L/g
The rhs of this inequality effectively determines the maximal height of a mountain. We note that it does not depend on the total volume, nor the density of the mountain, but just on the latent heat of fusion. The numerical factor 6 comes from the assumed shape (pyramidal or conical) of the mountain. If we assumed a prismoidal or cylindrical shape, the factor would be simply 3.
The numerical values for latent heats are of the order of magnitude of 100 kJ/kg = 10
5 J/kg, which gives a maximal height of the order of 10
4 m ≈ 10 km.
On the shadow diagram, the towers are around one third of the height of the Sun, which would make the Sun to be at most 200 km from the surface of the Earth. This is incorrect according to all FE models.