Noone said things "grew down" or whatever, DOWN is the direction towards the Earth's centre of mass. One can also prove that one is standing on the outside of a spinning object by measuring the (apparent) variation in the strength of gravity due to the varying effect of the centripetal acceleration at different places on the globe.
In your theory, different parts of the world would have to be accelerating at different rates, and altitude would not reduce g in the inverse square which it does.
One can do this as long as one has a very accurate scale, because the difference is still small.
On an Earth of radius 6378100 metres, assuming a day is exactly 24 hours, which it isn't quite, and assuming the Earth is a perfect sphere.
And using the following rule: (and the rule can be demonstrated by experiment or by math) T
The force to induce circular motion is equal to the object mass, times the radius of rotation, times the square of the angular velocity in radians per second.
Following from this, a 70kg person will feel a centripetal force of about
2.4N at the equator, and zero at the poles, there being no radius of rotation. This translates as appearing 2.4kg lighter. (I only say that because most scales at home measure "weight" in mass units.
The FE model relies on rectilinear acceleration, and so g cannot vary with altitude of location. Measure your weight in different places and it will be apparent.